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8.E: Solving Linear Equations (Exercises)

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8.1 - Solve Equations using the Subtraction and Addition Properties of Equality

In the following exercises, determine whether the given number is a solution to the equation.

  • x + 16 = 31, x = 15
  • w − 8 = 5, w = 3
  • −9n = 45, n = 54
  • 4a = 72, a = 18

In the following exercises, solve the equation using the Subtraction Property of Equality.

  • y + 2 = −6
  • a + \(\dfrac{1}{3} = \dfrac{5}{3}\)
  • n + 3.6 = 5.1

In the following exercises, solve the equation using the Addition Property of Equality.

  • u − 7 = 10
  • x − 9 = −4
  • c − \(\dfrac{3}{11} = \dfrac{9}{11}\)
  • p − 4.8 = 14

In the following exercises, solve the equation.

  • n − 12 = 32
  • y + 16 = −9
  • f + \(\dfrac{2}{3}\) = 4
  • d − 3.9 = 8.2
  • y + 8 − 15 = −3
  • 7x + 10 − 6x + 3 = 5
  • 6(n − 1) − 5n = −14
  • 8(3p + 5) − 23(p − 1) = 35

In the following exercises, translate each English sentence into an algebraic equation and then solve it.

  • The sum of −6 and m is 25.
  • Four less than n is 13.

In the following exercises, translate into an algebraic equation and solve.

  • Rochelle’s daughter is 11 years old. Her son is 3 years younger. How old is her son?
  • Tan weighs 146 pounds. Minh weighs 15 pounds more than Tan. How much does Minh weigh?
  • Peter paid $9.75 to go to the movies, which was $46.25 less than he paid to go to a concert. How much did he pay for the concert?
  • Elissa earned $152.84 this week, which was $21.65 more than she earned last week. How much did she earn last week?

8.2 - Solve Equations using the Division and Multiplication Properties of Equality

In the following exercises, solve each equation using the Division Property of Equality.

  • 13a = −65
  • 0.25p = 5.25
  • −y = 4

In the following exercises, solve each equation using the Multiplication Property of Equality.

  • \(\dfrac{n}{6}\) = 18
  • y −10 = 30
  • 36 = \(\dfrac{3}{4}\)x
  • \(\dfrac{5}{8} u = \dfrac{15}{16}\)

In the following exercises, solve each equation.

  • −18m = −72
  • \(\dfrac{c}{9}\) = 36
  • 0.45x = 6.75
  • \(\dfrac{11}{12} = \dfrac{2}{3} y\)
  • 5r − 3r + 9r = 35 − 2
  • 24x + 8x − 11x = −7−14

8.3 - Solve Equations with Variables and Constants on Both Sides

In the following exercises, solve the equations with constants on both sides.

  • 8p + 7 = 47
  • 10w − 5 = 65
  • 3x + 19 = −47
  • 32 = −4 − 9n

In the following exercises, solve the equations with variables on both sides.

  • 7y = 6y − 13
  • 5a + 21 = 2a
  • k = −6k − 35
  • 4x − \(\dfrac{3}{8}\) = 3x

In the following exercises, solve the equations with constants and variables on both sides.

  • 12x − 9 = 3x + 45
  • 5n − 20 = −7n − 80
  • 4u + 16 = −19 − u
  • \(\dfrac{5}{8} c\) − 4 = \(\dfrac{3}{8} c\) + 4

In the following exercises, solve each linear equation using the general strategy.

  • 6(x + 6) = 24
  • 9(2p − 5) = 72
  • −(s + 4) = 18
  • 8 + 3(n − 9) = 17
  • 23 − 3(y − 7) = 8
  • \(\dfrac{1}{3}\)(6m + 21) = m − 7
  • 8(r − 2) = 6(r + 10)
  • 5 + 7(2 − 5x) = 2(9x + 1) − (13x − 57)
  • 4(3.5y + 0.25) = 365
  • 0.25(q − 8) = 0.1(q + 7)

8.4 - Solve Equations with Fraction or Decimal Coefficients

In the following exercises, solve each equation by clearing the fractions.

  • \(\dfrac{2}{5} n − \dfrac{1}{10} = \dfrac{7}{10}\)
  • \(\dfrac{1}{3} x + \dfrac{1}{5} x = 8\)
  • \(\dfrac{3}{4} a − \dfrac{1}{3} = \dfrac{1}{2} a + \dfrac{5}{6}\)
  • \(\dfrac{1}{2}\)(k + 3) = \(\dfrac{1}{3}\)(k + 16)

In the following exercises, solve each equation by clearing the decimals.

  • 0.8x − 0.3 = 0.7x + 0.2
  • 0.36u + 2.55 = 0.41u + 6.8
  • 0.6p − 1.9 = 0.78p + 1.7
  • 0.10d + 0.05(d − 4) = 2.05

PRACTICE TEST

  • \(\dfrac{23}{5}\)
  • n − 18 = 31
  • 4y − 8 = 16
  • −8x − 15 + 9x − 1 = −21
  • −15a = 120
  • \(\dfrac{2}{3}\)x = 6
  • x + 3.8 = 8.2
  • 10y = −5y + 60
  • 8n + 2 = 6n + 12
  • 9m − 2 − 4m + m = 42 − 8
  • −5(2x + 1) = 45
  • −(d + 9) = 23
  • 2(6x + 5) − 8 = −22
  • 8(3a + 5) − 7(4a − 3) = 20 − 3a
  • \(\dfrac{1}{4} p + \dfrac{1}{3} = \dfrac{1}{2}\)
  • 0.1d + 0.25(d + 8) = 4.1
  • Translate and solve: The difference of twice x and 4 is 16.
  • Samuel paid $25.82 for gas this week, which was $3.47 less than he paid last week. How much did he pay last week?

Contributors and Attributions

Lynn Marecek (Santa Ana College) and MaryAnne Anthony-Smith (Formerly of Santa Ana College). This content is licensed under Creative Commons Attribution License v4.0 "Download for free at http://cnx.org/contents/[email protected] ."

A zeroing feedback gradient-based neural dynamics model for solving dynamic quadratic programming problems with linear equation constraints in finite time

  • Original Article
  • Published: 27 May 2024

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problem solving linear equations pdf

  • Shangfeng Du 1 ,
  • Dongyang Fu   ORCID: orcid.org/0000-0003-0426-4356 1 ,
  • Long Jin 2 ,
  • Yang Si 1 &
  • Yongze Li 1  

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Gradient-based neural dynamics (GND) models are a classical algorithm for solving optimization problems, but it has non-negligible flaws in solving dynamic problems. In this study, a novel GND model, namely the zeroing feedback gradient-based neural dynamics (ZF-GND) models, is proposed based on the original GND model for tracking down the exact solution of dynamic quadratic programming problem (DQP). Further, a nonlinear projection function is designed to accelerate the convergence of the model. An upper bound on the convergence time of the ZF-GND model is rigorously defined through theoretical analysis. The superior effect of the ZF-GND model in terms of convergence is verified through comparison experiments. Finally, an application of robot motion planning is introduced to verify the practicality of the ZF-GND model.

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Acknowledgements

This research was funded in part by the National Key Research and Development Program of China under Grant No. 2022YFC3103101, Key Special Project for Introduced Talents Team of Southern Marine Science and Engineering Guangdong Laboratory under Contract GML2021GD0809, National Natural Science Foundation of China under Contract 42206187, Key projects of the Guangdong Education Department under Grant No. 2023ZDZX4009.

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Du, S., Fu, D., Jin, L. et al. A zeroing feedback gradient-based neural dynamics model for solving dynamic quadratic programming problems with linear equation constraints in finite time. Neural Comput & Applic (2024). https://doi.org/10.1007/s00521-024-09762-3

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    What is most important is that they are e↵ective: they succeed in solving any linear equation. Let's apply these ideas to the equations of parts a through g of example 9. Example 9Solutions. a. 2(x +5) = 3x 1; Simplify the left side: 2x +10 = 3x 1; Subtract 2x from both sides: 10 = x 1; Add 1 to both sides: 11 = x.

  16. PDF Solving Systems of Linear

    Step 1: Notice that the coefi cients of the y-terms are opposites. So, you can add the equations to obtain an equation in one variable, x. 2x 14 Add the equations. Step 2: Solve for x. x 7 Divide each side by 2. Step 3: Substitute 7 for x in one of the original equations and solve for y. 7 3y 2 Substitute 7 for .

  17. 1.20: Word Problems for Linear Equations

    Solution: Translating the problem into an algebraic equation gives: 2x − 5 = 13 2 x − 5 = 13. We solve this for x x. First, add 5 to both sides. 2x = 13 + 5, so that 2x = 18 2 x = 13 + 5, so that 2 x = 18. Dividing by 2 gives x = 182 = 9 x = 18 2 = 9. c) A number subtracted from 9 is equal to 2 times the number.

  18. 8.E: Solving Linear Equations (Exercises)

    8.1 - Solve Equations using the Subtraction and Addition Properties of Equality. In the following exercises, determine whether the given number is a solution to the equation. x + 16 = 31, x = 15. w − 8 = 5, w = 3. −9n = 45, n = 54. 4a = 72, a = 18. In the following exercises, solve the equation using the Subtraction Property of Equality.

  19. PDF 8.1 SOLVING SYSTEMS BY GRAPHING AND SUBSTITUTION

    this section we solve systems of linear equations in two variables and use systems to solve problems. Solving a System by Graphing Because the graph of each linear equation is a line, points that satisfy both equations lie on both lines. For some systems these points can be found by graphing. EXAMPLE 1 A system with only one solution

  20. Linear equations, functions, & graphs

    This topic covers: - Intercepts of linear equations/functions - Slope of linear equations/functions - Slope-intercept, point-slope, & standard forms - Graphing linear equations/functions - Writing linear equations/functions - Interpreting linear equations/functions - Linear equations/functions word problems

  21. PDF Linear Equations

    So for the rectangle of length 8 and width 3 the formula would give, P =2(8) +2(3) = 16 + 6= 22. With problems that we will consider here the formula P =2L +2W will be used. Example 7. 4. The perimeter of a rectangle is 44. The length is 5 less than double the width. Find the dimensions.

  22. PDF Solving Multi-Step Equations

    14 Chapter 1 Solving Linear Equations Solving Real-Life Problems Modeling with Mathematics Use the table to fi nd the number of miles x you need to bike on Friday so that the mean number of miles biked per day is 5. SOLUTION 1. Understand the Problem You know how many miles you biked Monday through Thursday. You are asked to fi nd the number

  23. A Hybrid Natural Transform Homotopy Perturbation Method for Solving

    A hybrid analytical method for solving linear and nonlinear fractional partial differential equations is presented. The proposed analytical approach is an elegant combination of the Natural Transform Method (NTM) and a well-known method, Homotopy Perturbation Method (HPM).

  24. Solving Partial Differential Problems with Tau Toolbox

    This paper briefly examines how literature addresses the numerical solution of partial differential equations by the spectral Tau method. It discusses the implementation of such a numerical solution for PDE's presenting the construction of the problem's algebraic representation and exploring solution mechanisms with different orthogonal polynomial bases. It highlights contexts of ...

  25. A zeroing feedback gradient-based neural dynamics model for solving

    Study is devoted to solving dynamics quadratic programming (DQP) problems with linear equation constraints, and a zeroing feedback GND model (ZF-GND) is proposed. The ZF-GND model introduces a time-varying term based on the GND model, which can eliminate the time delay problem in the computation of the GND model and enables the model to obtain ...