do my sql homework

• How It Works
• Write my homework
• Sociology assignments
• Excel homework
• Online exam help
• Take my online class
• Online test help
• Java homework
• Hire a nerd
• Python homework
• Science homework
• C++ homework
• Case study assignment
• Matlab homework
• Math assignments
• Algebra homework
• Geometry homework
• Chemistry assignments
• Physics assignments
• Statistics homework
• Programming Assignment
• Linguistics assignments
• History assignments
• Economics assignments
• Accounting homework
• Computer science assignments
• English assignments
• Finance assignments
• Homework answers
• Biology assignments
• Homework tips
• Buy assignment
• Do my homework for money
• Solve my homework
• Assignment writer
• College homework help
• Academic subjects
• Nursing assignment
• Psychology homework
• Literature assignment
• Trigonometry homework
• Marketing assignment
• Engineering assignment
• Business homework
• Calculus homework
• Law assignment
• Assignment writing service
• Discussion board post
• Best homework help websites
• Management homework

SQL Homework Help from Best Experts Online

Many students need SQL homework help because they struggle to complete their assignments. Structured Query Language is a programming language that is common with databases. Mastering this language is a very important skill for both students and IT professionals. Our SQL homework solutions are designed to help students build their SQL skills using a variety of databases.

• Share Your Requirements
• Make the Payment
• Get A+ Paper

We have the best SQL experts with in-depth knowledge to offer the help that you need with your SQL assignment. Over the years, we have helped many students complete their assignments and graduate with top grades in their class. Be confident that you can also excel academically and venture into your dream career by using our SQL homework service.

SQL Homework Help from the Best Experts

Our team comprises the most talented and experienced SQL experts. These are professionals with advanced degrees and many years of experience in guiding students to complete their assignments. Many students that struggle to understand the practical implications of SQL have always benefited from our service.

Our company has become the go-to resource for many learners that need help with SQL homework because we know the best way to cater to their needs. Regardless of how complex your assignment seems, we will provide personalized assistance that will enable you to score the top grade in your class. Feel free to contact us at any time you need assistance with your homework.

Custom Help with SQL Homework Assignments

University professors require students to submit high-quality work that’s unique and authentic. If a professor suspects that you copied your homework, they will reject it. What’s more, you risk facing disciplinary actions if the professor suspects that you didn’t do the assignment. But, learners still ask, can I pay somebody to do my homework?

Well, students across the globe have been doing it for years. Many people are pursuing their dream careers because they sought help with assignments. You can also excel by allowing us to help you. Simply get in touch with us and say, “Will you do my SQL homework? I'll pay for it gladly!”

We know that SQL is a complex language with many commands. The commands are not easy for learners to comprehend. What’s more, completing the SQL assignment takes a lot of time. Our goal is to help you complete your assignment with relevant and proper references. Our service will also help you understand the topic better. That’s because we deliver assignments in a simple format that you can easily understand.

Comprehensive SQL Homework Assignment Help

We have a team of experts that help with even the SQL homework SQL students think is the most complex. Our service covers all SQL topics. And, we use a simple language and format to provide our assignment service. Whether you need help with basic SQL homework or advanced SQL, we’re ready to help you.

Our service covers the following:

• Procedural extensions
• Authorizations in SQL
• Advanced SQL, MySQL, PL/SQL
• Relational databases
• Database Design & SQL Query
• XML data structure
• Inheritance and Structured Types in SQL
• SQL Commands
• SQL Statements
• SQL transactions

Simply start a chat conversation by saying something like, “please help with my SQL homework”. Our customer care representative will respond to your request and provide the assistance you need to complete the assignment as soon as possible.

Once you seek our assistance, we make sure that you get plagiarism-free, well-researched, and properly written assignments within your timeframe. We have many quality control measures that we implement to ensure that we always deliver assignments that earn our clients the top grades.

Start a conversation with us now by simply saying, “Do my homework please!” We guarantee you a service that will boost your academic performance and chances of getting your dream job.

• Analogy Homework Help
• Analytical Chemistry Help
• Corporate Finance Homework Help
• C++ Homework Help
• Database Homework Help
• Write My Discussion Board Post
• Government Homework Help
• Grammar Homework Help
• High School Homework Help
• HTML Homework Help
• Inorganic Chemistry Help
• JavaScript Homework Help
• Macroeconomics Homework Help
• Managerial Economics Help
• Marketing Assignment Help
• Mechanical Engineering Homework Help
• Microeconomics Homework Help
• Operations Management Homework Help
• Physical Science Homework Help
• Probability Homework Help
• SPSS Homework Help
• SQL Homework Help

SQL Tutorial

Sql database, sql references, sql examples, sql exercises.

You can test your SQL skills with W3Schools' Exercises.

We have gathered a variety of SQL exercises (with answers) for each SQL Chapter.

Try to solve an exercise by filling in the missing parts of a code. If you're stuck, hit the "Show Answer" button to see what you've done wrong.

Count Your Score

You will get 1 point for each correct answer. Your score and total score will always be displayed.

Start SQL Exercises

Start SQL Exercises ❯

If you don't know SQL, we suggest that you read our SQL Tutorial from scratch.

Kickstart your career

Get certified by completing the course

COLOR PICKER

Contact Sales

If you want to use W3Schools services as an educational institution, team or enterprise, send us an e-mail: [email protected]

Report Error

If you want to report an error, or if you want to make a suggestion, send us an e-mail: [email protected]

Top Tutorials

Top references, top examples, get certified.

MySQL Practice: Best Exercises for Beginners

• online practice

Table of Contents

A Note on Our MySQL Practice Exercises

Dataset: cats, exercise 1: list all cats, exercise 2: select younger cats, exercise 3: list all ragdoll cats, exercise 4: select cats whose favorite toy is a ball, exercise 5: find older cats with a favorite toy, dataset: games, exercise 6: order data by cost and rating, exercise 7: order high-rated games by production cost, exercise 8: count games produced per year, exercise 9: count profitable games by type and company, exercise 10: list the number of games and average cost, dataset: employees, exercise 11: list salary grades for all employees, exercise 13: list all benefits for employee 5, exercise 12: show employees and direct managers, exercise 14: show benefits and how many employees receive them, exercise 15: show benefits not received by any employee, embrace the power of mysql practice exercises.

These 15 MySQL exercises are especially designed for beginners. They cover essential topics like selecting data from one table, ordering and grouping data, and joining data from multiple tables

This article showcases beginner-level MySQL practice exercises, including solutions and comprehensive explanations. If you need to practice …

• Selecting data from one table
• Ordering and grouping data
• Joining data from multiple tables

… these 15 tasks are just for you!

Most of the exercises come from our SQL Practice Set in MySQL , which provides a complete training environment where you can run queries and see the output data. Upon enrolling in this course, you’ll have access to 88 interactive beginner-friendly exercises to get you started towards SQL mastery.

While doing the exercises in this article, you may find this MySQL Cheat Sheet helpful. It contains a quick reference guide for MySQL syntax.

Continuous practice makes perfect, so the only way to learn and master your SQL skills is through practice. Following and solving practice exercises is the key to perfecting your SQL skills.

Let’s get started.

The exercises in the following sections use different datasets and cover distinct topics, including selecting data from one table, ordering and grouping data, and joining data from multiple tables.

Each section contains five exercises that include the following:

• The text of the exercise, which describes what data to fetch from the database.
• The solution query.
• A discussion on how the solution works and how the query was constructed.

We encourage you to solve the exercise on your own before looking at the solution. If you like these exercises, sign up for our SQL Practice Set in MySQL course and solve all 88 exercises!

Section 1: Selecting Data from One Table

We’ll start with the most basic SQL syntax, which is the SELECT statement. It selects data from a single table. You can use the WHERE clause to filter data based on defined conditions.

Let’s introduce the dataset and get to the MySQL practice exercises.

In this section, we’ll use the cat table. It consists of the following columns:

• id – The ID number of a given cat.
• name – The cat’s name.
• breed – The cat’s breed (e.g. Siamese, Ragdoll, etc.).
• coloration – The cat’s coloration.
• age – The cat’s age.
• sex – The cat’s sex.
• fav_toy – The cat’s favorite toy.

Select all data from the cat table.

Explanation:

We use the SELECT statement to define the columns to be outputted by the query. Here, we want to select all columns, so we use the asterisk character ( * ), which stands for all columns.

The FROM clause specifies the name of the table from which data is extracted.

It works just like we’d say it – we select all the columns from the cat table.

Select the name, breed, and coloration for every cat that is younger than five years old.

Again we use the SELECT statement to define the columns to be output by the query – here, the name , breed , and coloration columns.

It is followed by the FROM clause, which tells the database to get the data from the cat table.

Finally, we define the condition in the WHERE clause. As we want to select only cats that are younger than five years old, we impose a condition on the age column to be less than 5: WHERE age < 5 .

Select the ID and name for every cat that is of the Ragdoll breed.

We select the id and name columns from the cat table.

Next, we define a condition in the WHERE clause. As we want to list all cats of the Ragdoll breed, we impose a condition on the breed column to be equal to Ragdoll: WHERE breed = 'Ragdoll' . Note that in SQL we must enclose text strings in single quotation marks.

Select all data for cats whose:

• Breed starts with an 'R'.
• Favorite toy starts with the word 'ball'.
• Coloration name ends with an 'm'.

We use the SELECT statement to select all data. The asterisk character ( * ) stands for all columns. Therefore, SELECT * selects all columns available in the cat table, which is defined in the FROM clause.

Here, we define multiple conditions on different columns. We use the percentage character ( % ), which is a wildcard that stands for any sequence of characters.

• The breed column value must start with an 'R' followed by any sequence of characters: breed LIKE 'R%' .
• The fav_toy column value must start with the word 'ball' followed by any sequence of characters: fav_toy LIKE 'ball%' .
• The coloration column value must end with an 'm' preceded by any sequence of characters: coloration LIKE '%m' .

Since all these conditions must be applied at the same time, we combine them in the WHERE clause using the AND operator. This ensures that all conditions hold true for the selected data rows.

Select all data for cats that are:

• More than 10 years old.
• Either of the Ragdoll or Abyssinian breeds.
• Have a known favorite toy.

Again we select all columns from the cat table using an asterisk character ( * ) listed along the SELECT statement. Then we impose the conditions on the columns:

• We want to select cats that are older than 10, so we impose a condition on the age column: age > 10 .
• We want to select cats that are of Ragdoll or Abyssinian breeds, so we impose a condition on the breed column: ( breed = 'Ragdoll' OR breed = 'Abyssinian' ). Please note that this is a composite condition and we must enclose it in parentheses. The two parts are combined with the OR operator because we want to select either Ragdoll or Abyssinian cats.
• We want to select cats that have a favorite toy. Therefore, we impose a condition on the fav_toy column: fav_toy IS NOT NULL . We use the IS NOT NULL expression to ensure that selected cats have a favorite toy assigned.

To apply all three conditions at the same time, we combine them using the AND operator.

Section 2: Ordering and Grouping Data

Now that we’ve recalled how to query data from a table and filter it by imposing different conditions, let’s move on to ordering, aggregating, and grouping data.

In this section, we’ll use the games table, which has the following columns:

• id – The ID of a given game.
• title – The game’s title.
• company – The name of the company that produced the game.
• type – The game’s genre.
• production_year – The year when the game was created.
• system – The system on which the game is played.
• production_cost – The cost of producing this game.
• revenue – The revenue generated by the game.
• rating – The game’s

Select all data from the games table and order the results by the production cost from cheapest to most expensive. If multiple games have the same production cost, order the results by ratings, from best to worst.

We select all columns from the games table: SELECT * FROM games .

Next, we order the output data using the ORDER BY clause and the production_cost column. As we want it to be in ascending order, we follow the column name with the ASC keyword: ORDER BY production_cost ASC .

The secondary column by which we want to order the output data is the rating column. To order the data from best to worst rating (that is, in descending order), we use the DESC keyword: rating DESC .

Show the production cost values of games that were produced between 2010 and 2015 and were rated higher than 7. Order data by the cheapest to the most expensive production cost.

We select the production_cost column from the games table.

As we want to select only games produced between 2010 and 2015 and rated higher than 7, we impose conditions on the production_year and rating columns and combine them with the AND operator: production_year BETWEEN 2010 AND 2015 AND rating > 7 .

Finally, we order the output data by the production_cost column. We add the ASC keyword (which stands for ascending)  to order the data from cheapest to most expensive production costs.

For each year, display:

• The year ( production_year ).
• How many games were released in this year (as the count column).
• The average production costs per game for that year (as the avg_cost column).
• The average revenue per game for that year (as the avg_revenue column).

We select the following from the games table:

• The production_year
• The count of all games produced in that We use the COUNT() aggregate function , passing an asterisk ( * ) as its argument, to count all rows.
• The average production cost in that We use the AVG() aggregate function, passing the production_cost column as its argument, to calculate the average production cost.
• The average revenue within a given year. We use the AVG() aggregate function, passing the revenue column as its argument, to calculate the average revenue.

As we want to calculate these statistics (count and average) for each year, we need to group all data by the production_year column. We use the GROUP BY clause, passing production_year as its argument, so the data is put into as many groups as there are distinct values in the production_year column.

Count how many games of a given type and produced by a given company turned out to be profitable (their revenue was greater than their production cost). Show the number of games (as number_of_games ) and the company and type columns.

We select the company and type columns and the count of all games of each type produced by a given company. Therefore, we must list both the company and type columns in the GROUP BY clause so the groups are based on combinations of unique values from the company and type columns.

As we only need the profitable games, we impose a condition in the WHERE clause that ensures the revenue column value is greater than the production_cost column value. If that is not the case, this game will not be counted.

For each company, select its name, the number of games it produced (as the number_of_games column) and the average cost of production (as the avg_cost column). Show only companies that produced more than one game.

• The company name.
• The number of games produced by the company using the COUNT() aggregate function. Please note that you can use either the company column or an asterisk character (*) as an argument to COUNT() . The difference is that COUNT(*) counts all rows and COUNT(company) counts all rows where the company column is not null. In this case, the company column stores values for each row, so we can use the two options interchangeably. In most other queries, COUNT(column) and COUNT(*) are not interchangeable.
• The average production cost per company, using the AVG() aggregate function. Here, we pass the production_cost column as an argument to AVG() because we want to calculate an average for the values stored in this column.

As the SELECT statement lists one column ( company ) and two aggregate functions that perform calculations per company, we must group the output data by the company column.

To show only the companies that produced more than one game, we must impose a condition on the number_of_games column. However, we cannot use the WHERE clause because number_of_games is an alias name for the value calculated using the COUNT(company) aggregate function.

We use the HAVING clause to impose conditions on aggregate functions . This clause is processed after the GROUP BY clause. You can use either the alias name ( HAVING number_of_games > 1 ) or the aggregate function itself ( HAVING COUNT(company) > 1 ) to create such a condition.

Section 3: Joining Data from Multiple Tables

Now that we’ve reviewed how to query, filter, order, and group data from a single table, it’s time to move on to joining data from multiple tables and performing operations on joined data.

In this section, we’ll use the employees dataset that consists of the following tables:

• id – The ID of a given employee.
• first_name – The employee’s first name.
• last_name – The employee’s last name.
• salary – The employee’s salary.
• manager_id – The ID of this employee's manager.
• grade – The salary grade.
• lower_limit – This grade’s lower limit.
• upper_limit – This grade’s upper limit.
• salary_req – The minimum salary required to obtain a given benefit.
• benefit_name – The benefit name.

Select the first name, last name, salary, and salary grade of employees whose salary fits between the lower_limit and upper_limit from the salgrade table.

We want to select columns stored in the employee and salgrade tables. Therefore, we must join these two tables – or, as we do in this case, list them both in the FROM clause.

We select the first and last name and the salary from the employee table, and the grade column from the salgrade table. We list both these tables in the FROM clause.

We provide the join condition in the WHERE clause. The salary value from the employee table must fall between the lower_limit value and the upper_limit value from the salgrade table.

Show all benefits received by the employee with id = 5 . Select the first and last name of that employee and the benefits' names.

We select the first and last name from the employee table and the name of the benefit from the benefits table. Therefore, we must join the two tables using the JOIN statement.

To qualify for a certain benefit, the employee’s salary (stored in the salary column of the employee table) must be greater than or equal to the salary value required to obtain this benefit (stored in the salary_req column of the benefits table). Therefore, the join condition is exactly that: employee.salary >= benefits.salary_req .

As we want to show all benefits for the employee with id = 5 , we impose this condition in the WHERE clause.

Show each employee's first name, last name, salary, and the first name and last name of their direct manager in the same row. List only employees who have a direct manager.

Each record in the employee table contains a manager_id value that points to the id column of another employee who is this employee’s direct manager. Therefore, we must join the employee table with itself – i.e. a self-join.

The employee table aliased as e is used to select employees’ first name, last name, and salary. The employee table aliased as m is used to select the first and last name of the managers. This is defined in the ON clause, where we impose a join condition saying that the manager_id column from the e table must be equal to the id column from the m table. In effect, this makes the m table store managers of employees stored in the e table.

For each benefit, find the number of employees that receive it. Show two columns: the benefit_name and the count (name that column employee_count ). Don't show benefits that aren't received by anyone.

We want to count how many employees receive a given benefit. Therefore, we must join the benefits and employee tables.

To qualify for a certain benefit, the employee’s salary (stored in the salary column of the employee table) must be greater than or equal to the salary value required to obtain this benefit (stored in the salary_req column of the benefits table). Therefore, the join condition is exactly that: salary_req <= employee.salary .

This exercise brings together JOIN s and GROUP BY . We select the benefit name and the count of employees who receive a given benefit. Therefore, we must group the data by the benefit_name column.

For each benefit, find the number of employees that receive it. Show two columns: the benefit_name and the count (name that column employee_count ). Impose a condition to select only benefits that are not received by any employee ( employee_count = 0 ).

This exercise is analogical to the previous exercise.

To list all benefits – including the ones that no employee receives – we use the LEFT JOIN statement: benefits LEFT JOIN employee . It ensures that all rows from the left-hand side table (here, benefits ) are listed, no matter whether they match the join condition or not.

Next, to select only the employee_count values of zero, we must impose a condition on the COUNT(employee.id) aggregate function. To do so, we use the HAVING clause (introduced in exercise 10).

This article covered the basics of MySQL queries, including selecting and filtering data, ordering and grouping data, and joining multiple tables.

If you enjoyed the MySQL practice exercises showcased in this article, I suggest taking our SQL Practice Set in MySQL for more.

For additional help on SQL practice, check out these blog posts:

• SQL for Data Analysis: 15 Practical Exercises with Solutions .
• 10 Beginner SQL Practice Exercises with Solutions .
• How to Create Your Own Database to Practice SQL .
• 12 Ways to Practice SQL Online .

And remember, practice makes perfect.

You may also like

How Do You Write a SELECT Statement in SQL?

What Is a Foreign Key in SQL?

Enumerate and Explain All the Basic Elements of an SQL Query

SQL Homework Help

Get all the sql homework help you need.

SQL (Structured Query Language) is a popular and efficient programming language for managing relational databases. It is impossible not to stumble on SQL when dealing with data. In fact, Apache, Cassandra, Hadoop, and some other big data platforms use SQL to access their data. Many websites and mobile applications use SQL to gather information for your search engine history. So, when it comes to data management, you cannot overemphasize the advantages of SQL.

Despite its popularity and importance, only a few students understand the core concept of the SQL course! Therefore, you may be worried if you have a pile of SQL homework to solve. But this can quickly turn into a nightmare after all attempts to solve your SQL assignment have failed. Whether you are afraid of the pile of homework or tired of wrong solutions, there’s some good news. You can now easily get all the SQL homework help you need! With our SQL experts, you can always avoid the looming failure behind every SQL assignment. So, why wait when you can join the team of A+ students now?

Still thinking about how you’d get help with your SQL homework? Our committed professional tutors understand the headaches that SQL homework can give students. So, we set out to answer one of the most frequently asked questions students always ask—”how do I do my SQL assignment?” When dealing with SQL homework, there are a lot of concepts you must first learn, and that comes with a lot of googling and reading. We understand every bit of your SQL assignment worries, and we know how stressful that could be. Besides, you don’t have all the time in the world. That’s why we stepped in so every student could get SQL homework help.

Why do you need help with SQL Homework?

There is a lot of SQL jargon that can leave even the smartest students baffled all day long. Imagine being overwhelmed with what the right type of SQL to use is, the keys applicable, when to apply SQL joins, and a host of other things. The truth is, with the many SQL technicalities, most students would fail without some SQL homework help.

There are quite a number of reasons why you might need help with your SQL homework. You don’t necessarily have to face the task of doing your SQL assignment alone. The odds are definitely in your favor of outsourcing your SQL assignment! Why do I need help to do my SQL homework? Let’s see a few!

1.    Maximize your Time.

It can take time to create a database, query the database, and use the database. But it becomes tiring when you don’t exactly understand the right thing to do, and you can end up with no results after many attempts. That’s time-consuming! You can choose to waste time by going solo or maximize your time by getting SQL assignment help.

You already have a bunch of things or easier assignments to sort out and do. So, instead of trying to do the hard stuff all alone, you can give your SQL homework to our experts, and the rest is history. You’ll get excellent input and an A+ with no stress at all on your part.

2.    Improve your Grades.

When it comes to computer programming and data-related courses, it is done by numbers. A little mistake can get you to the wrong answers and leave you with pitiful results. Despite all the time and effort you put into it. But not any longer! Are you ready to boost your grades? Our SQL experts can help you! Contact our SQL experts today to get the best scores on all your SQL assignments. We know how to get you excellent grades on your homework!

3.    Meet Deadlines.

Programming languages and data management require a good deal of meticulousness. Sometimes, you get so busy that it’s too late when you remember you have a lot of assignments to deal with. At such times, don’t bother to attempt them under pressure, because you might get them all wrong! The best option is to contact SQL homework help. Our services consider your deadlines, and we are up to the task of keeping them. With us, you can meet all your submission deadlines!

4.     Get 24/7 Support

The SQL learning journey requires the full-time support of mentors! Some of its concepts require a comprehensive explanation. You don’t want to be left alone with your SQL problems. With our SQL assignment help, it is easy for you to ask all your questions and get prompt answers. At any time, you can enjoy the services of our professional tutors and even get step-by-step explanations of the solutions.

SQL Assignment Help – We’re the Best Option!

Are you in search of reputable online SQL assignment help? Do you need an on-time delivery service for your SQL assignment? We are the perfect match for your search! At a student-friendly price, we deliver top-notch services. Our clients have given us top ratings for every project we’ve received. It’s your turn!

Relax and get expert help with SQL homework from us! Enjoy the step-by-step approach used by our competent SQL tutors to solve your questions. No more worries about getting poor grades. Our experts understand every instruction that comes with your questions. The secret to A+ grades lies at our fingertips!

What do I Need to Know to do my SQL Assignment?

If you have not mastered how to use the key terms of SQL, don’t attempt to do your assignment! If you do, you might end up with a migraine. Some of the SQL terms like the assignment operator, the logical operators such as AND, OR, IN, BETWEEN, ANY, NOT, and some other fundamentals must first be learned. 

A little bit of a mix-up in the rules that guide SQL would cost you a lot of points! To avoid this, all you might have to do with your SQL homework is consult experts who know the do’s and don’ts of SQL. Their many years of experience make it difficult for them to make mistakes! Getting SQL homework assistance is the unequivocal answer to the question “how do I do my SQL homework? Continue learning to be a pro in SQL while you get good grades and enjoy the benefits of SQL homework help!

Don’t wait until your grades on the SQL assignment become the lowest in class. All you need to do is to contact our SQL assignment help at any time! No matter how much homework you have, we have enough professionals to deliver it for you and your friends. Get all the help you need now!