2022 AMC 8 Problems/Problem 22

  • 2 Solution 1
  • 3 Solution 2
  • 4 Video Solution by Math-X (First understand the problem!!!)
  • 5 Video Solution(🚀70 seconds🚀)
  • 6 Video Solution by OmegaLearn
  • 7 Video Solution
  • 8 Video Solution
  • 9 Video Solution
  • 10 Video Solution
  • 11 Video Solution
  • 12 Video Solution
  • 13 See Also

$2$

~MRENTHUSIASM

$\frac{1}{3}$

Video Solution by Math-X (First understand the problem!!!)

https://youtu.be/oUEa7AjMF2A?si=qG63Tc0Nj4iuSeSr&t=4163

Video Solution(🚀70 seconds🚀)

https://youtu.be/3xtTYyciReI

~Education, the Study of Everything

Video Solution by OmegaLearn

https://youtu.be/XixU0JZ5FLk?t=704

~ pi_is_3.14

Video Solution

https://www.youtube.com/watch?v=SFp4HaieEBg

~Mathematical Dexterity

https://youtu.be/Ij9pAy6tQSg?t=2111

~Interstigation

https://www.youtube.com/watch?v=m2D9W9LWUpU

https://youtu.be/0orAAUaLIO0?t=137

~STEMbreezy

https://youtu.be/KYnheOL86oA

~savannahsolver

https://youtu.be/K_V7ACKBhhs

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arts of problem solving amc 8

IMAGES

  1. Art of Problem Solving

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  3. AMC 8 真的没用吗?我们采访了 12 位得奖的学生

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  4. Art of Problem Solving

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  5. AMC 8 Problems and Solutions

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  6. Art of Problem Solving

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VIDEO

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  2. Dooriyaan

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  4. 2023 AMC 8 problem 23

  5. A Collection of Maths Problem Solving Questions:#77

  6. Art of Problem Solving: 2013 AMC 10 A #24

COMMENTS

  1. AMC 8 Problems and Solutions - Art of Problem Solving

    AMC 8 Problems and Solutions. AMC 8 / AJHSME problems and solutions. 2024 AMC 8. 2023 AMC 8. 2022 AMC 8. 2020 AMC 8. 2019 AMC 8. 2018 AMC 8. 2017 AMC 8.

  2. AMC 8 - Art of Problem Solving

    The AMC 8 is administered by the American Mathematics Competitions (AMC). Art of Problem Solving (AoPS) is a proud sponsor of the AMC. The test is intended to foster interest in mathematics and also to help middle school students learn mathematical problem solving . The AMC 8 replaced the AJHSME .

  3. Art of Problem Solving

    Solution 1. Clearly, the amount of money Ricardo has will be maximized when he has the maximum number of nickels. Since he must have at least one penny, the greatest number of nickels he can have is , giving a total of cents. Analogously, the amount of money he has will be least when he has the greatest number of pennies; as he must have at ...

  4. 2022 AMC 8 Problems/Problem 22 - Art of Problem Solving

    Solution 2. Since Zia will wait for the bus if the bus is at the previous stop, we can create an equation to solve for when the bus is at the previous stop. The bus travels of a stop per minute, and Zia travels of a stop per minute. Now we create the equation, (the accounts for us wanting to find when the bus reaches the stop before Zia's).