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5th grade (Eureka Math/EngageNY)
Unit 1: module 1: place value and decimal fractions, unit 2: module 2: multi-digit whole number and decimal fraction operations, unit 3: module 3: addition and subtractions of fractions, unit 4: module 4: multiplication and division of fractions and decimal fractions, unit 5: module 5: addition and multiplication with volume and area, unit 6: module 6: problem solving with the coordinate plane.
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Eureka Math Grade 5 Module 3 Lesson 12 Answer Key
Engage ny eureka math 5th grade module 3 lesson 12 answer key, eureka math grade 5 module 3 lesson 12 sprint answer key.
Question 1. \(\frac{2}{4}\) – \(\frac{1}{4}\) = Answer: \(\frac{2}{4}\) – \(\frac{1}{4}\) = \(\frac{1}{4}\)
Question 2. \(\frac{1}{2}\) – \(\frac{1}{4}\) = Answer: \(\frac{1}{2}\) – \(\frac{1}{4}\) = \(\frac{1}{4}\) Explanation : \(\frac{1}{2}\) – \(\frac{1}{4}\) = \(\frac{2}{4}\) – \(\frac{1}{4}\) = \(\frac{1}{4}\)
Question 3. \(\frac{2}{6}\) – \(\frac{1}{6}\) = Answer: \(\frac{2}{6}\) – \(\frac{1}{6}\) = \(\frac{1}{6}\)
Question 4. \(\frac{1}{3}\) – \(\frac{1}{6}\) = Answer: \(\frac{1}{3}\) – \(\frac{1}{6}\) = \(\frac{1}{6}\) Explanation : \(\frac{1}{3}\) – \(\frac{1}{6}\) =\(\frac{2}{6}\) – \(\frac{1}{6}\) = \(\frac{1}{6}\)
Question 5. \(\frac{2}{8}\) – \(\frac{1}{8}\) = Answer: \(\frac{2}{8}\) – \(\frac{1}{8}\) = \(\frac{1}{8}\)
Question 6. \(\frac{1}{4}\) – \(\frac{1}{8}\) = Answer: \(\frac{1}{4}\) – \(\frac{1}{8}\) =\(\frac{1}{8}\) Explanation : \(\frac{1}{4}\) – \(\frac{1}{8}\) = \(\frac{2}{8}\) – \(\frac{1}{8}\) = \(\frac{1}{8}\)
Question 7. \(\frac{6}{8}\) – \(\frac{1}{8}\) = Answer: \(\frac{6}{8}\) – \(\frac{1}{8}\) = \(\frac{5}{8}\)
Question 8. \(\frac{3}{4}\) – \(\frac{1}{8}\) = Answer: \(\frac{3}{4}\) – \(\frac{1}{8}\) = \(\frac{5}{8}\) Explanation : \(\frac{3}{4}\) – \(\frac{1}{8}\) = \(\frac{6}{8}\) – \(\frac{1}{8}\) = \(\frac{5}{8}\)
Question 9. \(\frac{3}{4}\) – \(\frac{3}{8}\) = Answer: \(\frac{3}{4}\) – \(\frac{3}{8}\) = \(\frac{3}{8}\) Explanation : \(\frac{3}{4}\) – \(\frac{3}{8}\) = \(\frac{6}{8}\) – \(\frac{3}{8}\) = \(\frac{3}{8}\)
Question 10. \(\frac{5}{10}\) – \(\frac{2}{10}\) = Answer: \(\frac{5}{10}\) – \(\frac{2}{10}\) = \(\frac{3}{10}\)
Question 11. \(\frac{1}{2}\) – \(\frac{2}{10}\) = Answer: \(\frac{1}{2}\) – \(\frac{2}{10}\) = \(\frac{3}{10}\) Explanation : \(\frac{1}{2}\) – \(\frac{2}{10}\) = \(\frac{5}{10}\) – \(\frac{2}{10}\) = \(\frac{3}{10}\)
Question 12. \(\frac{1}{2}\) – \(\frac{2}{10}\) = Answer: \(\frac{1}{2}\) – \(\frac{2}{10}\) = \(\frac{3}{10}\) Explanation : \(\frac{1}{2}\) – \(\frac{2}{10}\) = \(\frac{5}{10}\) – \(\frac{2}{10}\) = \(\frac{3}{10}\)
Question 13. \(\frac{4}{10}\) – \(\frac{1}{10}\) = Answer: \(\frac{4}{10}\) – \(\frac{1}{10}\) = \(\frac{3}{10}\)
Question 14. \(\frac{2}{5}\) – \(\frac{1}{10}\) = Answer: \(\frac{2}{5}\) – \(\frac{1}{10}\) = \(\frac{3}{10}\) Explanation : \(\frac{2}{5}\) – \(\frac{1}{10}\) = \(\frac{4}{10}\) – \(\frac{1}{10}\) = \(\frac{3}{10}\)
Question 15. \(\frac{2}{5}\) – \(\frac{3}{10}\) = Answer: \(\frac{2}{5}\) – \(\frac{3}{10}\) = \(\frac{1}{10}\) Explanation : \(\frac{2}{5}\) – \(\frac{3}{10}\) = \(\frac{4}{10}\) – \(\frac{3}{10}\) = \(\frac{1}{10}\)
Question 16. \(\frac{6}{10}\) – \(\frac{3}{10}\) = Answer: \(\frac{6}{10}\) – \(\frac{3}{10}\) =\(\frac{3}{10}\)
Question 17. \(\frac{3}{5}\) – \(\frac{3}{10}\) = Answer: \(\frac{3}{5}\) – \(\frac{3}{10}\) = \(\frac{3}{10}\) Explanation : \(\frac{3}{5}\) – \(\frac{3}{10}\) = \(\frac{6}{10}\) – \(\frac{3}{10}\) = \(\frac{3}{10}\)
Question 18. \(\frac{3}{5}\) – \(\frac{5}{10}\) = Answer: \(\frac{3}{5}\) – \(\frac{5}{10}\) = \(\frac{1}{10}\) Explanation : \(\frac{3}{5}\) – \(\frac{5}{10}\) = \(\frac{6}{10}\) – \(\frac{5}{10}\) = \(\frac{1}{10}\)
Question 19. \(\frac{8}{10}\) – \(\frac{1}{10}\) = Answer: \(\frac{8}{10}\) – \(\frac{1}{10}\) = \(\frac{7}{10}\)
Question 20. \(\frac{4}{5}\) – \(\frac{1}{10}\) = Answer: \(\frac{4}{5}\) – \(\frac{1}{10}\) = \(\frac{7}{10}\) Explanation : \(\frac{4}{5}\) – \(\frac{1}{10}\) = \(\frac{8}{10}\) – \(\frac{1}{10}\) = \(\frac{7}{10}\)
Question 21. \(\frac{4}{5}\) – \(\frac{5}{10}\) = Answer: \(\frac{4}{5}\) – \(\frac{5}{10}\) = \(\frac{3}{10}\) Explanation : \(\frac{4}{5}\) – \(\frac{5}{10}\) = \(\frac{8}{10}\) – \(\frac{5}{10}\) = \(\frac{4}{10}\)
Question 22. \(\frac{4}{5}\) – \(\frac{5}{10}\) = Answer: \(\frac{4}{5}\) – \(\frac{5}{10}\) = \(\frac{3}{10}\) Explanation : \(\frac{4}{5}\) – \(\frac{5}{10}\) = \(\frac{8}{10}\) – \(\frac{5}{10}\) = \(\frac{4}{10}\)
Question 23. \(\frac{4}{5}\) – \(\frac{7}{10}\) = Answer: \(\frac{4}{5}\) – \(\frac{7}{10}\) = \(\frac{1}{10}\) Explanation : \(\frac{4}{5}\) – \(\frac{7}{10}\) = \(\frac{8}{10}\) – \(\frac{7}{10}\) = \(\frac{1}{10}\)
Question 24. \(\frac{2}{12}\) – \(\frac{1}{12}\) = Answer: \(\frac{2}{12}\) – \(\frac{1}{12}\) = \(\frac{1}{12}\)
Question 25. \(\frac{1}{6}\) – \(\frac{1}{12}\) = Answer: \(\frac{1}{6}\) – \(\frac{1}{12}\) =\(\frac{1}{12}\) Explanation : \(\frac{1}{6}\) – \(\frac{1}{12}\) = \(\frac{2}{12}\) – \(\frac{1}{12}\) = \(\frac{1}{12}\)
Question 26. \(\frac{6}{12}\) – \(\frac{1}{12}\) = Answer: \(\frac{6}{12}\) – \(\frac{1}{12}\) = \(\frac{5}{12}\)
Question 27. \(\frac{1}{2}\) – \(\frac{1}{12}\) = Answer: \(\frac{1}{2}\) – \(\frac{1}{12}\) = \(\frac{5}{12}\) Explanation : \(\frac{1}{2}\) – \(\frac{1}{12}\) = \(\frac{6}{12}\) – \(\frac{1}{12}\) = \(\frac{5}{12}\)
Question 28. \(\frac{1}{2}\) – \(\frac{5}{12}\) = Answer: \(\frac{1}{2}\) – \(\frac{5}{12}\) = \(\frac{1}{12}\) Explanation : \(\frac{1}{2}\) – \(\frac{5}{12}\) = \(\frac{6}{12}\) – \(\frac{5}{12}\) = \(\frac{1}{12}\)
Question 29. \(\frac{10}{12}\) – \(\frac{5}{12}\) = Answer: \(\frac{10}{12}\) – \(\frac{5}{12}\) = \(\frac{5}{12}\)
Question 30. \(\frac{5}{6}\) – \(\frac{5}{12}\) = Answer: \(\frac{5}{6}\) – \(\frac{5}{12}\) = \(\frac{5}{12}\) Explanation : \(\frac{5}{6}\) – \(\frac{5}{12}\) = \(\frac{10}{12}\) – \(\frac{5}{12}\) = \(\frac{5}{12}\)
Question 31. \(\frac{1}{3}\) – \(\frac{3}{12}\) = Answer: \(\frac{1}{3}\) – \(\frac{3}{12}\) = \(\frac{1}{12}\) Explanation : \(\frac{1}{3}\) – \(\frac{3}{12}\) = \(\frac{4}{12}\) – \(\frac{3}{12}\) = \(\frac{1}{12}\)
Question 32. \(\frac{2}{3}\) – \(\frac{1}{12}\) = Answer: \(\frac{2}{3}\) – \(\frac{1}{12}\) = \(\frac{7}{12}\) Explanation : \(\frac{2}{3}\) – \(\frac{1}{12}\) = \(\frac{8}{12}\) – \(\frac{1}{12}\) = \(\frac{7}{12}\)
Question 33. \(\frac{2}{3}\) – \(\frac{3}{12}\) = Answer: \(\frac{2}{3}\) – \(\frac{3}{12}\) = \(\frac{5}{12}\) Explanation : \(\frac{2}{3}\) – \(\frac{3}{12}\) = \(\frac{8}{12}\) – \(\frac{3}{12}\) = \(\frac{5}{12}\)
Question 34. \(\frac{2}{3}\) – \(\frac{7}{12}\) = Answer: \(\frac{2}{3}\) – \(\frac{7}{12}\) = \(\frac{1}{12}\) Explanation : \(\frac{2}{3}\) – \(\frac{7}{12}\) = \(\frac{8}{12}\) – \(\frac{7}{12}\) = \(\frac{1}{12}\)
Question 35. \(\frac{1}{4}\) – \(\frac{2}{12}\) = Answer: \(\frac{1}{4}\) – \(\frac{2}{12}\) = \(\frac{1}{12}\) Explanation : \(\frac{1}{4}\) – \(\frac{2}{12}\) = \(\frac{3}{12}\) – \(\frac{2}{12}\) = \(\frac{1}{12}\)
Question 36. \(\frac{1}{5}\) – \(\frac{1}{15}\) = Answer: \(\frac{1}{5}\) – \(\frac{1}{15}\) = \(\frac{2}{15}\) Explanation : \(\frac{1}{5}\) – \(\frac{1}{15}\) = \(\frac{3}{15}\) – \(\frac{1}{15}\) = \(\frac{2}{15}\)
Question 37. \(\frac{1}{3}\) – \(\frac{1}{15}\) = Answer: \(\frac{1}{3}\) – \(\frac{1}{15}\) = \(\frac{4}{15}\) Explanation : \(\frac{1}{3}\) – \(\frac{1}{15}\) = \(\frac{5}{15}\) – \(\frac{1}{15}\) = \(\frac{4}{15}\)
Question 38. \(\frac{2}{3}\) – \(\frac{3}{15}\) = Answer: \(\frac{2}{3}\) – \(\frac{3}{15}\) = \(\frac{7}{15}\) Explanation : \(\frac{2}{3}\) – \(\frac{3}{15}\) = \(\frac{10}{15}\) – \(\frac{3}{15}\) = \(\frac{7}{15}\)
Question 39. \(\frac{2}{5}\) – \(\frac{4}{15}\) = Answer: \(\frac{2}{5}\) – \(\frac{4}{15}\) = \(\frac{2}{15}\) Explanation : \(\frac{2}{5}\) – \(\frac{4}{15}\) = \(\frac{6}{15}\) – \(\frac{4}{15}\) = \(\frac{2}{15}\)
Question 40. \(\frac{3}{4}\) – \(\frac{2}{12}\) = Answer: \(\frac{3}{4}\) – \(\frac{2}{12}\) = \(\frac{7}{12}\) Explanation : \(\frac{3}{4}\) – \(\frac{2}{12}\) = \(\frac{9}{12}\) – \(\frac{2}{12}\) = \(\frac{7}{12}\)
Question 41. \(\frac{3}{4}\) – \(\frac{5}{16}\) = Answer: \(\frac{3}{4}\) – \(\frac{5}{16}\) = \(\frac{7}{16}\) Explanation : \(\frac{3}{4}\) – \(\frac{5}{16}\) = \(\frac{12}{16}\) – \(\frac{5}{16}\) = \(\frac{7}{16}\)
Question 42. \(\frac{4}{5}\) – \(\frac{5}{15}\) = Answer: \(\frac{4}{5}\) – \(\frac{5}{15}\) = \(\frac{7}{15}\) Explanation : \(\frac{4}{5}\) – \(\frac{5}{15}\) = \(\frac{12}{15}\) – \(\frac{5}{15}\) = \(\frac{7}{15}\)
Question 43. \(\frac{3}{4}\) – \(\frac{4}{12}\) = Answer: \(\frac{3}{4}\) – \(\frac{4}{12}\) = \(\frac{5}{12}\) Explanation : \(\frac{3}{4}\) – \(\frac{4}{12}\) = \(\frac{9}{12}\) – \(\frac{4}{12}\) = \(\frac{5}{12}\)
Question 44. \(\frac{3}{4}\) – \(\frac{7}{16}\) = Answer: \(\frac{3}{4}\) – \(\frac{7}{16}\) = \(\frac{5}{16}\) Explanation : \(\frac{3}{4}\) – \(\frac{5}{16}\) = \(\frac{12}{16}\) – \(\frac{7}{16}\) = \(\frac{5}{16}\)
Question 1. \(\frac{2}{10}\) – \(\frac{1}{10}\) = Answer: \(\frac{2}{10}\) – \(\frac{1}{10}\) = \(\frac{1}{10}\)
Question 2. \(\frac{1}{5}\) – \(\frac{1}{10}\) = Answer: \(\frac{1}{5}\) – \(\frac{1}{10}\) = \(\frac{1}{10}\) Explanation : \(\frac{1}{5}\) – \(\frac{1}{10}\) = \(\frac{2}{10}\) – \(\frac{1}{10}\) = \(\frac{1}{10}\)
Question 3. \(\frac{2}{4}\) – \(\frac{1}{4}\) = Answer: \(\frac{2}{4}\) – \(\frac{1}{4}\) = \(\frac{1}{4}\)
Question 4. \(\frac{1}{2}\) – \(\frac{1}{4}\) = Answer: \(\frac{1}{2}\) – \(\frac{1}{4}\) = \(\frac{1}{4}\) Explanation : \(\frac{1}{2}\) – \(\frac{1}{4}\) = \(\frac{2}{4}\) – \(\frac{1}{4}\) = \(\frac{1}{4}\)
Question 5. \(\frac{5}{10}\) – \(\frac{2}{10}\) = Answer: \(\frac{5}{10}\) – \(\frac{2}{10}\) = \(\frac{3}{10}\)
Question 6. \(\frac{1}{2}\) – \(\frac{2}{10}\) = Answer: \(\frac{1}{2}\) – \(\frac{2}{10}\) = \(\frac{3}{10}\) Explanation : \(\frac{1}{2}\) – \(\frac{2}{10}\) = \(\frac{5}{10}\) – \(\frac{2}{10}\) = \(\frac{3}{10}\)
Question 7. \(\frac{1}{2}\) – \(\frac{4}{10}\) = Answer: \(\frac{1}{2}\) – \(\frac{4}{10}\) = \(\frac{1}{10}\) Explanation : \(\frac{1}{2}\) – \(\frac{4}{10}\) = \(\frac{5}{10}\) – \(\frac{4}{10}\) = \(\frac{1}{10}\)
Question 8. \(\frac{4}{10}\) – \(\frac{1}{10}\) = Answer: \(\frac{4}{10}\) – \(\frac{1}{10}\) = \(\frac{3}{10}\)
Question 9. \(\frac{2}{5}\) – \(\frac{1}{10}\) = Answer: \(\frac{2}{5}\) – \(\frac{1}{10}\) = \(\frac{3}{10}\) Explanation : \(\frac{2}{5}\) – \(\frac{1}{10}\) = \(\frac{4}{10}\) – \(\frac{1}{10}\) = \(\frac{3}{10}\)
Question 10. \(\frac{2}{5}\) – \(\frac{3}{10}\) = Answer: \(\frac{2}{5}\) – \(\frac{3}{10}\) = \(\frac{1}{10}\) Explanation : \(\frac{2}{5}\) – \(\frac{3}{10}\) = \(\frac{4}{10}\) – \(\frac{3}{10}\) = \(\frac{1}{10}\)
Question 11. \(\frac{6}{10}\) – \(\frac{3}{10}\) = Answer: \(\frac{6}{10}\) – \(\frac{3}{10}\) =\(\frac{3}{10}\)
Question 12. \(\frac{3}{5}\) – \(\frac{3}{10}\) = Answer: \(\frac{3}{5}\) – \(\frac{3}{10}\) = \(\frac{3}{10}\) Explanation : \(\frac{3}{5}\) – \(\frac{3}{10}\) = \(\frac{6}{10}\) – \(\frac{3}{10}\) = \(\frac{3}{10}\)
Question 13. \(\frac{3}{5}\) – \(\frac{5}{10}\) = Answer: \(\frac{3}{5}\) – \(\frac{5}{10}\) = \(\frac{1}{10}\) Explanation : \(\frac{3}{5}\) – \(\frac{5}{10}\) = \(\frac{6}{10}\) – \(\frac{5}{10}\) = \(\frac{1}{10}\)
Question 14. \(\frac{8}{10}\) – \(\frac{1}{10}\) = Answer: \(\frac{8}{10}\) – \(\frac{1}{10}\) = \(\frac{7}{10}\)
Question 15. \(\frac{4}{5}\) – \(\frac{1}{10}\) = Answer: \(\frac{4}{5}\) – \(\frac{1}{10}\) = \(\frac{7}{10}\) Explanation : \(\frac{4}{5}\) – \(\frac{1}{10}\) = \(\frac{8}{10}\) – \(\frac{1}{10}\) = \(\frac{7}{10}\)
Question 16. \(\frac{4}{5}\) – \(\frac{5}{10}\) = Answer: \(\frac{4}{5}\) – \(\frac{5}{10}\) = \(\frac{3}{10}\) Explanation : \(\frac{4}{5}\) – \(\frac{5}{10}\) = \(\frac{8}{10}\) – \(\frac{5}{10}\) = \(\frac{4}{10}\)
Question 17. \(\frac{4}{5}\) – \(\frac{5}{10}\) = Answer: \(\frac{4}{5}\) – \(\frac{5}{10}\) = \(\frac{3}{10}\) Explanation : \(\frac{4}{5}\) – \(\frac{5}{10}\) = \(\frac{8}{10}\) – \(\frac{5}{10}\) = \(\frac{4}{10}\)
Question 18. \(\frac{4}{5}\) – \(\frac{7}{10}\) = Answer: \(\frac{4}{5}\) – \(\frac{7}{10}\) = \(\frac{1}{10}\) Explanation : \(\frac{4}{5}\) – \(\frac{7}{10}\) = \(\frac{8}{10}\) – \(\frac{7}{10}\) = \(\frac{1}{10}\)
Question 19. \(\frac{2}{8}\) – \(\frac{1}{8}\) = Answer: \(\frac{2}{8}\) – \(\frac{1}{8}\) = \(\frac{1}{8}\)
Question 20. \(\frac{1}{4}\) – \(\frac{1}{8}\) = Answer: \(\frac{1}{4}\) – \(\frac{1}{8}\) =\(\frac{1}{8}\) Explanation : \(\frac{1}{4}\) – \(\frac{1}{8}\) = \(\frac{2}{8}\) – \(\frac{1}{8}\) = \(\frac{1}{8}\)
Question 21. \(\frac{6}{8}\) – \(\frac{1}{8}\) = Answer: \(\frac{6}{8}\) – \(\frac{1}{8}\) = \(\frac{5}{8}\)
Question 22. \(\frac{3}{4}\) – \(\frac{1}{8}\) = Answer: \(\frac{3}{4}\) – \(\frac{1}{8}\) = \(\frac{5}{8}\) Explanation : \(\frac{3}{4}\) – \(\frac{1}{8}\) = \(\frac{6}{8}\) – \(\frac{1}{8}\) = \(\frac{5}{8}\)
Question 23. \(\frac{3}{4}\) – \(\frac{3}{8}\) = Answer: \(\frac{3}{4}\) – \(\frac{3}{8}\) = \(\frac{3}{8}\) Explanation : \(\frac{3}{4}\) – \(\frac{3}{8}\) = \(\frac{6}{8}\) – \(\frac{3}{8}\) = \(\frac{3}{8}\)
Question 24. \(\frac{5}{15}\) – \(\frac{1}{15}\) = Answer: \(\frac{5}{15}\) – \(\frac{1}{15}\) = \(\frac{4}{15}\)
Question 25. \(\frac{1}{3}\) – \(\frac{1}{15}\) = Answer: \(\frac{1}{3}\) – \(\frac{1}{15}\) = \(\frac{4}{15}\) Explanation : \(\frac{1}{3}\) – \(\frac{1}{15}\) = \(\frac{5}{15}\) – \(\frac{1}{15}\) = \(\frac{4}{15}\)
Question 26. \(\frac{3}{15}\) – \(\frac{1}{15}\) = Answer: \(\frac{3}{15}\) – \(\frac{1}{15}\) = \(\frac{2}{15}\)
Question 27. \(\frac{1}{5}\) – \(\frac{1}{15}\) = Answer: \(\frac{1}{5}\) – \(\frac{1}{15}\) = \(\frac{2}{15}\) Explanation : \(\frac{1}{5}\) – \(\frac{1}{15}\) = \(\frac{3}{15}\) – \(\frac{1}{15}\) = \(\frac{2}{15}\)
Question 28. \(\frac{1}{5}\) – \(\frac{2}{15}\) = Answer: \(\frac{1}{5}\) – \(\frac{2}{15}\) = \(\frac{1}{15}\) Explanation : \(\frac{1}{5}\) – \(\frac{2}{15}\) = \(\frac{3}{15}\) – \(\frac{2}{15}\) = \(\frac{1}{15}\)
Question 29. \(\frac{12}{15}\) – \(\frac{4}{15}\) = Answer: \(\frac{12}{15}\) – \(\frac{4}{15}\) = \(\frac{8}{15}\)
Question 30. \(\frac{4}{5}\) – \(\frac{4}{15}\) = Answer: \(\frac{4}{5}\) – \(\frac{2}{15}\) = \(\frac{2}{3}\) Explanation : \(\frac{4}{5}\) – \(\frac{2}{15}\) = \(\frac{12}{15}\) – \(\frac{2}{15}\) = \(\frac{10}{15}\)= \(\frac{2}{3}\)
Question 31. \(\frac{1}{4}\) – \(\frac{2}{12}\) = Answer: \(\frac{1}{4}\) – \(\frac{2}{12}\) = \(\frac{1}{12}\) Explanation : \(\frac{1}{4}\) – \(\frac{2}{12}\) = \(\frac{3}{12}\) – \(\frac{2}{12}\) = \(\frac{1}{12}\)
Question 32. \(\frac{3}{4}\) – \(\frac{2}{12}\) = Answer: \(\frac{3}{4}\) – \(\frac{2}{12}\) = \(\frac{7}{12}\) Explanation : \(\frac{3}{4}\) – \(\frac{2}{12}\) = \(\frac{9}{12}\) – \(\frac{2}{12}\) = \(\frac{7}{12}\)
Question 33. \(\frac{3}{4}\) – \(\frac{4}{12}\) = Answer: \(\frac{3}{4}\) – \(\frac{4}{12}\) = \(\frac{5}{12}\) Explanation : \(\frac{3}{4}\) – \(\frac{4}{12}\) = \(\frac{9}{12}\) – \(\frac{4}{12}\) = \(\frac{5}{12}\)
Question 34. \(\frac{3}{4}\) – \(\frac{8}{12}\) = Answer: \(\frac{3}{4}\) – \(\frac{8}{12}\) = \(\frac{1}{12}\) Explanation : \(\frac{3}{4}\) – \(\frac{8}{12}\) = \(\frac{9}{12}\) – \(\frac{8}{12}\) = \(\frac{1}{12}\)
Question 35. \(\frac{1}{3}\) – \(\frac{3}{12}\) = Answer: \(\frac{1}{3}\) – \(\frac{3}{12}\) = \(\frac{1}{12}\) Explanation : \(\frac{1}{3}\) – \(\frac{3}{12}\) = \(\frac{4}{12}\) – \(\frac{3}{12}\) = \(\frac{1}{12}\)
Question 36. \(\frac{1}{6}\) – \(\frac{1}{12}\) = Answer: \(\frac{1}{6}\) – \(\frac{1}{12}\) =\(\frac{1}{12}\) Explanation : \(\frac{1}{6}\) – \(\frac{1}{12}\) = \(\frac{2}{12}\) – \(\frac{1}{12}\) = \(\frac{1}{12}\)
Question 37. \(\frac{1}{3}\) – \(\frac{3}{15}\) = Answer: \(\frac{1}{3}\) – \(\frac{3}{15}\) = \(\frac{2}{15}\) Explanation : \(\frac{1}{3}\) – \(\frac{3}{15}\) = \(\frac{5}{15}\) – \(\frac{3}{15}\) = \(\frac{2}{15}\)
Question 38. \(\frac{2}{3}\) – \(\frac{2}{15}\) = Answer: \(\frac{2}{3}\) – \(\frac{2}{15}\) = \(\frac{8}{15}\) Explanation : \(\frac{2}{3}\) – \(\frac{2}{15}\) = \(\frac{10}{15}\) – \(\frac{2}{15}\) = \(\frac{8}{15}\)
Question 39. \(\frac{2}{5}\) – \(\frac{2}{15}\) = Answer: \(\frac{2}{5}\) – \(\frac{2}{15}\) = \(\frac{4}{15}\) Explanation : \(\frac{2}{5}\) – \(\frac{2}{15}\) = \(\frac{6}{15}\) – \(\frac{2}{15}\) = \(\frac{4}{15}\)
Question 40. \(\frac{3}{4}\) – \(\frac{4}{12}\) = Answer: \(\frac{3}{4}\) – \(\frac{4}{12}\) = \(\frac{5}{12}\) Explanation : \(\frac{3}{4}\) – \(\frac{4}{12}\) = \(\frac{9}{12}\) – \(\frac{4}{12}\) = \(\frac{5}{12}\)
Question 41. \(\frac{3}{4}\) – \(\frac{7}{16}\) = Answer: \(\frac{3}{4}\) – \(\frac{7}{16}\) = \(\frac{5}{16}\) Explanation : \(\frac{3}{4}\) – \(\frac{5}{16}\) = \(\frac{12}{16}\) – \(\frac{7}{16}\) = \(\frac{5}{16}\)
Question 42. \(\frac{4}{5}\) – \(\frac{4}{15}\) = Answer: \(\frac{4}{5}\) – \(\frac{4}{15}\) = \(\frac{8}{15}\) Explanation : \(\frac{4}{5}\) – \(\frac{4}{15}\) = \(\frac{12}{15}\) – \(\frac{4}{15}\) = \(\frac{8}{15}\)
Question 43. \(\frac{3}{4}\) – \(\frac{2}{12}\) = Answer: \(\frac{3}{4}\) – \(\frac{2}{12}\) = \(\frac{7}{12}\) Explanation : \(\frac{3}{4}\) – \(\frac{2}{12}\) = \(\frac{9}{12}\) – \(\frac{2}{12}\) = \(\frac{7}{12}\)
Question 44. \(\frac{3}{4}\) – \(\frac{5}{16}\) = Answer: \(\frac{3}{4}\) – \(\frac{5}{16}\) = \(\frac{7}{16}\) Explanation : \(\frac{3}{4}\) – \(\frac{5}{16}\) = \(\frac{12}{16}\) – \(\frac{5}{16}\) = \(\frac{7}{16}\)
Eureka Math Grade 5 Module 3 Lesson 12 Problem Set Answer Key
Question 1. Subtract. a. 3\(\frac{1}{5}\) – 2\(\frac{1}{4}\) = b. 4\(\frac{2}{5}\) – 3\(\frac{3}{4}\) = c. 7\(\frac{1}{5}\) – 4\(\frac{1}{5}\) = d. 7\(\frac{2}{5}\) – 5\(\frac{2}{3}\) = e. 4\(\frac{2}{7}\) – 3\(\frac{1}{3}\) = f. 9\(\frac{2}{3}\) – 2\(\frac{6}{7}\) = g. 17\(\frac{2}{3}\) – 5\(\frac{5}{6}\) = h. 18\(\frac{1}{3}\) – 3\(\frac{3}{8}\) = Answer: a. 3\(\frac{1}{5}\) – 2\(\frac{1}{4}\) = \(\frac{19}{20}\) Explanation : 3\(\frac{1}{5}\) – 2\(\frac{1}{4}\) = \(\frac{16}{5}\) – \(\frac{9}{4}\) lcm of 5 and 4 is 20 . \(\frac{64}{20}\) – \(\frac{45}{20}\) = \(\frac{19}{20}\)
b. 4\(\frac{2}{5}\) – 3\(\frac{3}{4}\) = \(\frac{13}{20}\) Explanation : 4\(\frac{2}{5}\) – 3\(\frac{3}{4}\) = \(\frac{22}{5}\) – \(\frac{15}{4}\) lcm of 5 and 4 is 20 . \(\frac{88}{20}\) – \(\frac{75}{20}\) = \(\frac{13}{20}\)
c. 7\(\frac{1}{5}\) – 4\(\frac{1}{5}\) = Explanation : 7\(\frac{1}{5}\) – 4\(\frac{1}{5}\) = \(\frac{36}{5}\) – \(\frac{21}{5}\) = \(\frac{15}{5}\) = 3 .
d. 7\(\frac{2}{5}\) – 5\(\frac{2}{3}\) = 1\(\frac{11}{15}\) . Explanation : 7\(\frac{2}{5}\) – 5\(\frac{2}{3}\) = \(\frac{37}{5}\) – \(\frac{17}{3}\) lcm of 5 and 3 is 15 . \(\frac{111}{15}\) – \(\frac{85}{15}\) = \(\frac{26}{15}\) = 1\(\frac{11}{15}\) .
e. 4\(\frac{2}{7}\) – 3\(\frac{1}{3}\) = \(\frac{20}{21}\) Explanation : 4\(\frac{2}{7}\) – 3\(\frac{1}{3}\) = \(\frac{30}{7}\) – \(\frac{10}{3}\) lcm of 7 and 3 is 21. \(\frac{90}{21}\) – \(\frac{70}{21}\) = \(\frac{20}{21}\)
f. 9\(\frac{2}{3}\) – 2\(\frac{6}{7}\) = 6\(\frac{17}{21}\) Explanation : 9\(\frac{2}{3}\) – 2\(\frac{6}{7}\) = \(\frac{29}{3}\) – \(\frac{20}{7}\) lcm of 3 and 7 is 21. \(\frac{203}{21}\) – \(\frac{60}{21}\) = \(\frac{143}{21}\) = 6\(\frac{17}{21}\)
g. 17\(\frac{2}{3}\) – 5\(\frac{5}{6}\) = 11\(\frac{5}{6}\) Explanation : 17\(\frac{2}{3}\) – 5\(\frac{5}{6}\) = \(\frac{53}{3}\) – \(\frac{35}{6}\) lcm of 3 and 6 is 6 . \(\frac{106}{6}\) – \(\frac{35}{6}\) = \(\frac{71}{6}\) = 11\(\frac{5}{6}\)
h. 18\(\frac{1}{3}\) – 3\(\frac{3}{8}\) = 14\(\frac{23}{24}\) Explanation : 18\(\frac{1}{3}\) – 3\(\frac{3}{8}\) = \(\frac{55}{3}\) – \(\frac{27}{8}\) lcm of 3 and 8 is 24 . \(\frac{440}{24}\) – \(\frac{81}{24}\) = \(\frac{359}{24}\) = 14\(\frac{23}{24}\)
Question 3. Mr. Neville Iceguy mixed up 12\(\frac{3}{5}\) gallons of chili for a party. If 7\(\frac{3}{4}\)gallons of chili was mild, and the rest was extra spicy, how much extra spicy chili did Mr. Iceguy make? Answer: Fraction of chili mixed up for a party = 12\(\frac{3}{5}\) gallons = \(\frac{63}{5}\) gallons Fraction of chilli is mild = 7\(\frac{3}{4}\)gallons = \(\frac{31}{4}\)gallons Fraction of chilli is extra spicy = x \(\frac{63}{5}\) = \(\frac{31}{4}\) + x x = \(\frac{63}{5}\) – \(\frac{31}{4}\) lcm of 5 and 4 is 20 . x = \(\frac{252}{20}\) – \(\frac{155}{20}\) = \(\frac{97}{20}\) = 4\(\frac{17}{20}\) Therefore, Fraction of chilli is extra spicy = x = 4\(\frac{17}{20}\) gallons .
Question 4. Jazmyne decided to spend 6\(\frac{1}{2}\) hours studying over the weekend. She spent 1\(\frac{1}{4}\) hours studying on Friday evening and 2\(\frac{2}{3}\) hours on Saturday. How much longer does she need to spend studying on Sunday in order to reach her goal? Answer: Total Fraction of time should spend on Studying = 6\(\frac{1}{2}\) hours = \(\frac{13}{2}\) hours Fraction of Time spent on Friday for studying = 1\(\frac{1}{4}\) hours = \(\frac{5}{4}\) hours Fraction of Time spent on Saturday for studying = 2\(\frac{2}{3}\) hours = \(\frac{8}{3}\) hours Fraction of Time should spend on Sunday for studying = x \(\frac{13}{2}\) = \(\frac{5}{4}\) + \(\frac{8}{3}\) + x lcm of 2 , 4 , and 3 is 12 . x = \(\frac{13}{2}\) – \(\frac{5}{4}\) – \(\frac{8}{3}\) x = \(\frac{78}{12}\) – \(\frac{15}{12}\) – \(\frac{32}{12}\) x = \(\frac{78}{12}\) – \(\frac{47}{12}\) x = \(\frac{31}{12}\) x = 2\(\frac{7}{12}\) Therefore, Fraction of Time should spend on Sunday for studying = x = 2\(\frac{7}{12}\) hours .
Eureka Math Grade 5 Module 3 Lesson 12 Exit Ticket Answer Key
Subtract. Question 1. 5\(\frac{1}{2}\) – 1\(\frac{1}{3}\) = Answer: 5\(\frac{1}{2}\) – 1\(\frac{1}{3}\) = 4\(\frac{1}{6}\) . Explanation : 5\(\frac{1}{2}\) – 1\(\frac{1}{3}\) = \(\frac{11}{2}\) – \(\frac{4}{3}\) lcm of 2 and 3 is 6 \(\frac{33}{6}\) – \(\frac{8}{6}\) = \(\frac{25}{6}\) = 4\(\frac{1}{6}\) .
Question 2. 8\(\frac{3}{4}\) – 5\(\frac{5}{6}\) = Answer: 8\(\frac{3}{4}\) – 5\(\frac{5}{6}\) = 2\(\frac{11}{12}\) Explanation : 8\(\frac{3}{4}\) – 5\(\frac{5}{6}\) = \(\frac{35}{4}\) – \(\frac{35}{6}\) lcm of 4 and 6 is 12 . \(\frac{105}{12}\) – \(\frac{70}{12}\) = \(\frac{35}{12}\) = 2\(\frac{11}{12}\)
Eureka Math Grade 5 Module 3 Lesson 12 Homework Answer Key
Question 1. Subtract. a. 3\(\frac{1}{4}\) – 2\(\frac{1}{3}\) = b. 3\(\frac{2}{3}\) – 2\(\frac{3}{4}\) = c. 6\(\frac{1}{5}\) – 4\(\frac{1}{4}\) = d. 6\(\frac{3}{5}\) – 4\(\frac{3}{4}\) = e. 5\(\frac{2}{7}\) – 4\(\frac{1}{3}\) = f. 8\(\frac{2}{3}\) – 3\(\frac{5}{7}\) = g. 18\(\frac{3}{4}\) – 5\(\frac{7}{8}\) = h. 17\(\frac{1}{5}\) – 2\(\frac{5}{8}\) = Answer: a. 3\(\frac{1}{4}\) – 2\(\frac{1}{3}\) = \(\frac{11}{12}\) Explanation : 3\(\frac{1}{4}\) – 2\(\frac{1}{3}\) = \(\frac{13}{4}\) – \(\frac{7}{3}\) lcm of 4 and 3 is 12 \(\frac{39}{12}\) – \(\frac{28}{12}\) = \(\frac{11}{12}\)
b. 3\(\frac{2}{3}\) – 2\(\frac{3}{4}\) = \(\frac{11}{12}\) Explanation : 3\(\frac{2}{3}\) – 2\(\frac{3}{4}\) = \(\frac{11}{3}\) – \(\frac{11}{4}\) lcm of 3 and 4 is 12 \(\frac{44}{12}\) – \(\frac{33}{12}\) = \(\frac{11}{12}\)
c. 6\(\frac{1}{5}\) – 4\(\frac{1}{4}\) = 3\(\frac{13}{20}\) Explanation : 6\(\frac{1}{5}\) – 4\(\frac{1}{4}\) = \(\frac{31}{5}\) – \(\frac{17}{4}\) lcm of 4 and 5 is 20 . \(\frac{124}{20}\) – \(\frac{51}{20}\) = \(\frac{73}{20}\) = 3\(\frac{13}{20}\) .
d. 6\(\frac{3}{5}\) – 4\(\frac{3}{4}\) = 1\(\frac{17}{20}\) Explanation : 6\(\frac{3}{5}\) – 4\(\frac{3}{4}\) = \(\frac{33}{5}\) – \(\frac{19}{4}\) lcm of 4 and 5 is 20 . \(\frac{132}{20}\) – \(\frac{95}{20}\) = \(\frac{37}{20}\) = 1\(\frac{17}{20}\)
e. 5\(\frac{2}{7}\) – 4\(\frac{1}{3}\) = \(\frac{20}{21}\) Explanation : 5\(\frac{2}{7}\) – 4\(\frac{1}{3}\) = \(\frac{37}{7}\) – \(\frac{13}{3}\) lcm of 3 and 7 is 21. \(\frac{111}{21}\) – \(\frac{91}{21}\) = \(\frac{20}{21}\)
f. 8\(\frac{2}{3}\) – 3\(\frac{5}{7}\) = 4\(\frac{20}{21}\) Explanation : 8\(\frac{2}{3}\) – 3\(\frac{5}{7}\) = \(\frac{26}{3}\) – \(\frac{26}{7}\) lcm of 3 and 7 is 21. \(\frac{182}{21}\) – \(\frac{78}{21}\) = \(\frac{104}{21}\) = 4\(\frac{20}{21}\)
g. 18\(\frac{3}{4}\) – 5\(\frac{7}{8}\) = 11\(\frac{9}{8}\) Explanation : 18\(\frac{3}{4}\) – 5\(\frac{7}{8}\) = \(\frac{75}{4}\) – \(\frac{47}{8}\) lcm of 4 and 8 is 8 . \(\frac{130}{8}\) – \(\frac{47}{8}\) = \(\frac{97}{8}\) = 11\(\frac{9}{8}\)
h. 17\(\frac{1}{5}\) – 2\(\frac{5}{8}\) = 14\(\frac{23}{40}\) Explanation : 17\(\frac{1}{5}\) – 2\(\frac{5}{8}\) = \(\frac{86}{5}\) – \(\frac{21}{8}\) lcm of 5 and 8 is 40 . \(\frac{688}{40}\) – \(\frac{105}{40}\) = \(\frac{583}{40}\) = 14\(\frac{23}{40}\)
Question 3. Ms. Sanger blended 8\(\frac{3}{4}\) gallons of iced tea with some lemonade for a picnic. If there were 13\(\frac{2}{5}\) gallons of the beverage, how many gallons of lemonade did she use? Answer: Fraction of gallons of iced tea with some lemonade for a picnic = 8\(\frac{3}{4}\) = \(\frac{35}{4}\) gallons . Fraction of gallons of the beverage = 13\(\frac{2}{5}\) = \(\frac{67}{5}\) . Fraction of gallons of the lemonade = x \(\frac{67}{5}\) = \(\frac{35}{4}\) – x x = \(\frac{67}{5}\) – \(\frac{35}{4}\) lcm of 4 and 5 is 20 . x = \(\frac{268}{20}\) – \(\frac{175}{20}\) x = \(\frac{93}{20}\) = 4\(\frac{13}{20}\) Therefore, Fraction of gallons of the lemonade = x = 4\(\frac{13}{20}\) gallons .
Question 4. A carpenter has 10\(\frac{1}{2}\) feet of wooden plank. He cuts off 4\(\frac{1}{4}\) feet to replace the slat of a deck and 3\(\frac{2}{3}\) feet to repair a bannister. He uses the rest of the plank to fix a stair. How many feet of wood does the carpenter use to fix the stair? Answer: Total Fraction of wooden plank = 10\(\frac{1}{2}\) feet = \(\frac{21}{2}\) feet Fraction of wooden plank cut off = 4\(\frac{1}{4}\) feet = \(\frac{17}{4}\) feet Fraction of wooden plank used to repair a bannister = 3\(\frac{2}{3}\) feet = \(\frac{11}{3}\) feet Fraction of wooden plank used for stair = x feet 10\(\frac{1}{2}\) = \(\frac{17}{4}\) + \(\frac{11}{3}\) + x \(\frac{21}{2}\) = \(\frac{17}{4}\) + \(\frac{11}{3}\) + x lcm of 2 , 4 and 3 is 12 . \(\frac{126}{12}\) = \(\frac{51}{4}\) + \(\frac{44}{3}\) + x x = \(\frac{126}{12}\) – \(\frac{95}{4}\) x = \(\frac{31}{4}\) = 7\(\frac{3}{4}\) . Therefore, Fraction of wooden plank used for stair = 7\(\frac{3}{4}\) feet .
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Eureka Math Grade 5 Module 5 Lesson 12 Homework Answer Key. Question 1. Measure each rectangle to the nearest 14 inch with your ruler, and label the dimensions. Use the area model to find the area. Answer: a. Area =. 1 3/4 x 3 1/2. = 3 + 2 1/4 + 1/2 + 3/8.
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Engage NY // Eureka Math Grade 5 Module 2 Lesson 12 Homework. Engage NY // Eureka Math Grade 5 Module 2 Lesson 12 Homework.
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Select amount. 5th grade (Eureka Math/EngageNY) 6 units · 140 skills. Unit 1 Module 1: Place value and decimal fractions. Unit 2 Module 2: Multi-digit whole number and decimal fraction operations. Unit 3 Module 3: Addition and subtractions of fractions. Unit 4 Module 4: Multiplication and division of fractions and decimal fractions.
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Lesson 12: Reason using benchmarks to compare two fractions on the number line. Lesson 12 Homework 4 5 Name Date 1. a. Plot the following points on the number line without measuring. i. 2 3 ii. 1 6 iii. 4 1 b. Use the number line in Part (a) to compare the fractions Ç Á ] ] v P E U Y U } A } v Z o ] v .
Lesson 12 Homework Helper 5 • 4 2. Circle the expression(s) that give the same product as 4 ... Eureka Math - TESK - Succeed - Grade 5 - Module 4 - Lesson 12 Author: Great Minds Subject: Compare and evaluate expressions with parentheses and brackets. Keywords: compare, homework
Eureka Essentials: Grade 5 URL An outline of learning goals, key ideas, pacing suggestions, and more! ... Lesson 12 Video Page. Lesson PDF Page. Homework Solutions Page. Promethean ... This work by EMBARC.Online based upon Eureka Math and is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.
EngageNY/Eureka Math Grade 5 Module 5 Lesson 12For more videos, please visit http://bit.ly/eurekapusdPLEASE leave a message if a video has a technical diffic...
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As the creator of Engage NY Math and Eureka Math, Great Minds is the only place where you can get print editions of the PK-12 curriculum.Our printed materials are available in two configurations: Learn, Practice, Succeed, or student workbooks, teacher editions, assessment and fluency materials. The Learn, Practice, Succeed configuration is available for grades K-8 and offers teachers ...
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EngageNY/Eureka Math Grade 5 Module 1 Lesson 12For more Eureka Math (EngageNY) videos and other resources, please visit http://EMBARC.onlinePLEASE leave a me...
ISBN 978-1-64497-958-7. 3. 2. 1. Learn ♦ Practice ♦ Succeed Eureka Math® student materials for A Story of Units® (K-5) are available in the Learn, Practice, Succeed trio. This series ...
Subtract fractions greater than or equal to one, remove entire subtrahend from minuend or whole, common core, common denominator, tape diagrams, word problem...
It's Homework Time! Help for fourth graders with Eureka Math Module 5 Lesson 12.
Eureka Math Grade 5 Module 3 Lesson 12 Homework Answer Key. Question 1. Subtract. lcm of 4 and 5 is 20 . - = = 3 . lcm of 4 and 5 is 20 . lcm of 3 and 7 is 21.