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5th grade (Eureka Math/EngageNY)

Unit 1: module 1: place value and decimal fractions, unit 2: module 2: multi-digit whole number and decimal fraction operations, unit 3: module 3: addition and subtractions of fractions, unit 4: module 4: multiplication and division of fractions and decimal fractions, unit 5: module 5: addition and multiplication with volume and area, unit 6: module 6: problem solving with the coordinate plane.

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Eureka Math Grade 5 Module 3 Lesson 12 Answer Key

Engage ny eureka math 5th grade module 3 lesson 12 answer key, eureka math grade 5 module 3 lesson 12 sprint answer key.

Engage NY Math 5th Grade Module 3 Lesson 12 Sprint Answer Key 1

Question 1. \(\frac{2}{4}\) – \(\frac{1}{4}\) = Answer: \(\frac{2}{4}\) – \(\frac{1}{4}\) = \(\frac{1}{4}\)

Question 2. \(\frac{1}{2}\) – \(\frac{1}{4}\) = Answer: \(\frac{1}{2}\) – \(\frac{1}{4}\) = \(\frac{1}{4}\) Explanation : \(\frac{1}{2}\) – \(\frac{1}{4}\) = \(\frac{2}{4}\) – \(\frac{1}{4}\) = \(\frac{1}{4}\)

Question 3. \(\frac{2}{6}\) – \(\frac{1}{6}\) = Answer: \(\frac{2}{6}\) – \(\frac{1}{6}\) = \(\frac{1}{6}\)

Question 4. \(\frac{1}{3}\) – \(\frac{1}{6}\) = Answer: \(\frac{1}{3}\) – \(\frac{1}{6}\) = \(\frac{1}{6}\) Explanation : \(\frac{1}{3}\) – \(\frac{1}{6}\) =\(\frac{2}{6}\) – \(\frac{1}{6}\) = \(\frac{1}{6}\)

Question 5. \(\frac{2}{8}\) – \(\frac{1}{8}\) = Answer: \(\frac{2}{8}\) – \(\frac{1}{8}\) = \(\frac{1}{8}\)

Question 6. \(\frac{1}{4}\) – \(\frac{1}{8}\) = Answer: \(\frac{1}{4}\) – \(\frac{1}{8}\) =\(\frac{1}{8}\) Explanation : \(\frac{1}{4}\) – \(\frac{1}{8}\) = \(\frac{2}{8}\) – \(\frac{1}{8}\) = \(\frac{1}{8}\)

Question 7. \(\frac{6}{8}\) – \(\frac{1}{8}\) = Answer: \(\frac{6}{8}\) – \(\frac{1}{8}\) = \(\frac{5}{8}\)

Question 8. \(\frac{3}{4}\) – \(\frac{1}{8}\) = Answer: \(\frac{3}{4}\) – \(\frac{1}{8}\) = \(\frac{5}{8}\) Explanation : \(\frac{3}{4}\) – \(\frac{1}{8}\) = \(\frac{6}{8}\) – \(\frac{1}{8}\) = \(\frac{5}{8}\)

Question 9. \(\frac{3}{4}\) – \(\frac{3}{8}\) = Answer: \(\frac{3}{4}\) – \(\frac{3}{8}\) = \(\frac{3}{8}\) Explanation : \(\frac{3}{4}\) – \(\frac{3}{8}\) = \(\frac{6}{8}\) – \(\frac{3}{8}\) = \(\frac{3}{8}\)

Question 10. \(\frac{5}{10}\) – \(\frac{2}{10}\) = Answer: \(\frac{5}{10}\) – \(\frac{2}{10}\) = \(\frac{3}{10}\)

Question 11. \(\frac{1}{2}\) – \(\frac{2}{10}\) = Answer: \(\frac{1}{2}\) – \(\frac{2}{10}\) = \(\frac{3}{10}\) Explanation : \(\frac{1}{2}\) – \(\frac{2}{10}\) = \(\frac{5}{10}\) – \(\frac{2}{10}\) = \(\frac{3}{10}\)

Question 12. \(\frac{1}{2}\) – \(\frac{2}{10}\) = Answer: \(\frac{1}{2}\) – \(\frac{2}{10}\) = \(\frac{3}{10}\) Explanation : \(\frac{1}{2}\) – \(\frac{2}{10}\) = \(\frac{5}{10}\) – \(\frac{2}{10}\) = \(\frac{3}{10}\)

Question 13. \(\frac{4}{10}\) – \(\frac{1}{10}\) = Answer: \(\frac{4}{10}\) – \(\frac{1}{10}\) = \(\frac{3}{10}\)

Question 14. \(\frac{2}{5}\) – \(\frac{1}{10}\) = Answer: \(\frac{2}{5}\) – \(\frac{1}{10}\) = \(\frac{3}{10}\) Explanation : \(\frac{2}{5}\) – \(\frac{1}{10}\) = \(\frac{4}{10}\) – \(\frac{1}{10}\) = \(\frac{3}{10}\)

Question 15. \(\frac{2}{5}\) – \(\frac{3}{10}\) = Answer: \(\frac{2}{5}\) – \(\frac{3}{10}\) = \(\frac{1}{10}\) Explanation : \(\frac{2}{5}\) – \(\frac{3}{10}\) = \(\frac{4}{10}\) – \(\frac{3}{10}\) = \(\frac{1}{10}\)

Question 16. \(\frac{6}{10}\) – \(\frac{3}{10}\) = Answer: \(\frac{6}{10}\) – \(\frac{3}{10}\) =\(\frac{3}{10}\)

Question 17. \(\frac{3}{5}\) – \(\frac{3}{10}\) = Answer: \(\frac{3}{5}\) – \(\frac{3}{10}\) = \(\frac{3}{10}\) Explanation : \(\frac{3}{5}\) – \(\frac{3}{10}\) = \(\frac{6}{10}\) – \(\frac{3}{10}\) = \(\frac{3}{10}\)

Question 18. \(\frac{3}{5}\) – \(\frac{5}{10}\) = Answer: \(\frac{3}{5}\) – \(\frac{5}{10}\) = \(\frac{1}{10}\) Explanation : \(\frac{3}{5}\) – \(\frac{5}{10}\) = \(\frac{6}{10}\) – \(\frac{5}{10}\) = \(\frac{1}{10}\)

Question 19. \(\frac{8}{10}\) – \(\frac{1}{10}\) = Answer: \(\frac{8}{10}\) – \(\frac{1}{10}\) =  \(\frac{7}{10}\)

Question 20. \(\frac{4}{5}\) – \(\frac{1}{10}\) = Answer: \(\frac{4}{5}\) – \(\frac{1}{10}\) = \(\frac{7}{10}\) Explanation : \(\frac{4}{5}\) – \(\frac{1}{10}\) = \(\frac{8}{10}\) – \(\frac{1}{10}\) =  \(\frac{7}{10}\)

Question 21. \(\frac{4}{5}\) – \(\frac{5}{10}\) = Answer: \(\frac{4}{5}\) – \(\frac{5}{10}\) = \(\frac{3}{10}\) Explanation : \(\frac{4}{5}\) – \(\frac{5}{10}\) = \(\frac{8}{10}\) – \(\frac{5}{10}\) =  \(\frac{4}{10}\)

Question 22. \(\frac{4}{5}\) – \(\frac{5}{10}\) = Answer: \(\frac{4}{5}\) – \(\frac{5}{10}\) = \(\frac{3}{10}\) Explanation : \(\frac{4}{5}\) – \(\frac{5}{10}\) = \(\frac{8}{10}\) – \(\frac{5}{10}\) =  \(\frac{4}{10}\)

Question 23. \(\frac{4}{5}\) – \(\frac{7}{10}\) = Answer: \(\frac{4}{5}\) – \(\frac{7}{10}\) = \(\frac{1}{10}\) Explanation : \(\frac{4}{5}\) – \(\frac{7}{10}\) = \(\frac{8}{10}\) – \(\frac{7}{10}\) =  \(\frac{1}{10}\)

Question 24. \(\frac{2}{12}\) – \(\frac{1}{12}\) = Answer: \(\frac{2}{12}\) – \(\frac{1}{12}\) = \(\frac{1}{12}\)

Question 25. \(\frac{1}{6}\) – \(\frac{1}{12}\) = Answer: \(\frac{1}{6}\) – \(\frac{1}{12}\) =\(\frac{1}{12}\) Explanation : \(\frac{1}{6}\) – \(\frac{1}{12}\) = \(\frac{2}{12}\) – \(\frac{1}{12}\) = \(\frac{1}{12}\)

Question 26. \(\frac{6}{12}\) – \(\frac{1}{12}\) = Answer: \(\frac{6}{12}\) – \(\frac{1}{12}\) = \(\frac{5}{12}\)

Question 27. \(\frac{1}{2}\) – \(\frac{1}{12}\) = Answer: \(\frac{1}{2}\) – \(\frac{1}{12}\) =  \(\frac{5}{12}\) Explanation : \(\frac{1}{2}\) – \(\frac{1}{12}\) = \(\frac{6}{12}\) – \(\frac{1}{12}\) = \(\frac{5}{12}\)

Question 28. \(\frac{1}{2}\) – \(\frac{5}{12}\) = Answer: \(\frac{1}{2}\) – \(\frac{5}{12}\) =  \(\frac{1}{12}\) Explanation : \(\frac{1}{2}\) – \(\frac{5}{12}\) = \(\frac{6}{12}\) – \(\frac{5}{12}\) = \(\frac{1}{12}\)

Question 29. \(\frac{10}{12}\) – \(\frac{5}{12}\) = Answer: \(\frac{10}{12}\) – \(\frac{5}{12}\) = \(\frac{5}{12}\)

Question 30. \(\frac{5}{6}\) – \(\frac{5}{12}\) = Answer: \(\frac{5}{6}\) – \(\frac{5}{12}\) = \(\frac{5}{12}\) Explanation : \(\frac{5}{6}\) – \(\frac{5}{12}\) = \(\frac{10}{12}\) – \(\frac{5}{12}\) = \(\frac{5}{12}\)

Question 31. \(\frac{1}{3}\) – \(\frac{3}{12}\) = Answer: \(\frac{1}{3}\) – \(\frac{3}{12}\) = \(\frac{1}{12}\) Explanation : \(\frac{1}{3}\) – \(\frac{3}{12}\) = \(\frac{4}{12}\) – \(\frac{3}{12}\) = \(\frac{1}{12}\)

Question 32. \(\frac{2}{3}\) – \(\frac{1}{12}\) = Answer: \(\frac{2}{3}\) – \(\frac{1}{12}\) = \(\frac{7}{12}\) Explanation : \(\frac{2}{3}\) – \(\frac{1}{12}\) = \(\frac{8}{12}\) – \(\frac{1}{12}\) = \(\frac{7}{12}\)

Question 33. \(\frac{2}{3}\) – \(\frac{3}{12}\) = Answer: \(\frac{2}{3}\) – \(\frac{3}{12}\) = \(\frac{5}{12}\) Explanation : \(\frac{2}{3}\) – \(\frac{3}{12}\) = \(\frac{8}{12}\) – \(\frac{3}{12}\) = \(\frac{5}{12}\)

Question 34. \(\frac{2}{3}\) – \(\frac{7}{12}\) = Answer: \(\frac{2}{3}\) – \(\frac{7}{12}\) = \(\frac{1}{12}\) Explanation : \(\frac{2}{3}\) – \(\frac{7}{12}\) = \(\frac{8}{12}\) – \(\frac{7}{12}\) = \(\frac{1}{12}\)

Question 35. \(\frac{1}{4}\) – \(\frac{2}{12}\) = Answer: \(\frac{1}{4}\) – \(\frac{2}{12}\) =  \(\frac{1}{12}\) Explanation : \(\frac{1}{4}\) – \(\frac{2}{12}\) = \(\frac{3}{12}\) – \(\frac{2}{12}\) = \(\frac{1}{12}\)

Question 36. \(\frac{1}{5}\) – \(\frac{1}{15}\) = Answer: \(\frac{1}{5}\) – \(\frac{1}{15}\) = \(\frac{2}{15}\) Explanation : \(\frac{1}{5}\) – \(\frac{1}{15}\) = \(\frac{3}{15}\) – \(\frac{1}{15}\) = \(\frac{2}{15}\)

Question 37. \(\frac{1}{3}\) – \(\frac{1}{15}\) = Answer: \(\frac{1}{3}\) – \(\frac{1}{15}\) =  \(\frac{4}{15}\) Explanation : \(\frac{1}{3}\) – \(\frac{1}{15}\) = \(\frac{5}{15}\) – \(\frac{1}{15}\) = \(\frac{4}{15}\)

Question 38. \(\frac{2}{3}\) – \(\frac{3}{15}\) = Answer: \(\frac{2}{3}\) – \(\frac{3}{15}\) =  \(\frac{7}{15}\) Explanation : \(\frac{2}{3}\) – \(\frac{3}{15}\) = \(\frac{10}{15}\) – \(\frac{3}{15}\) = \(\frac{7}{15}\)

Question 39. \(\frac{2}{5}\) – \(\frac{4}{15}\) = Answer: \(\frac{2}{5}\) – \(\frac{4}{15}\) = \(\frac{2}{15}\) Explanation : \(\frac{2}{5}\) – \(\frac{4}{15}\) = \(\frac{6}{15}\) – \(\frac{4}{15}\) = \(\frac{2}{15}\)

Question 40. \(\frac{3}{4}\) – \(\frac{2}{12}\) = Answer: \(\frac{3}{4}\) – \(\frac{2}{12}\) =  \(\frac{7}{12}\) Explanation : \(\frac{3}{4}\) – \(\frac{2}{12}\) = \(\frac{9}{12}\) – \(\frac{2}{12}\) = \(\frac{7}{12}\)

Question 41. \(\frac{3}{4}\) – \(\frac{5}{16}\) = Answer: \(\frac{3}{4}\) – \(\frac{5}{16}\) = \(\frac{7}{16}\) Explanation : \(\frac{3}{4}\) – \(\frac{5}{16}\) = \(\frac{12}{16}\) – \(\frac{5}{16}\) = \(\frac{7}{16}\)

Question 42. \(\frac{4}{5}\) – \(\frac{5}{15}\) = Answer: \(\frac{4}{5}\) – \(\frac{5}{15}\) = \(\frac{7}{15}\) Explanation : \(\frac{4}{5}\) – \(\frac{5}{15}\) = \(\frac{12}{15}\) – \(\frac{5}{15}\) = \(\frac{7}{15}\)

Question 43. \(\frac{3}{4}\) – \(\frac{4}{12}\) = Answer: \(\frac{3}{4}\) – \(\frac{4}{12}\) =  \(\frac{5}{12}\) Explanation : \(\frac{3}{4}\) – \(\frac{4}{12}\) = \(\frac{9}{12}\) – \(\frac{4}{12}\) = \(\frac{5}{12}\)

Question 44. \(\frac{3}{4}\) – \(\frac{7}{16}\) = Answer: \(\frac{3}{4}\) – \(\frac{7}{16}\) = \(\frac{5}{16}\) Explanation : \(\frac{3}{4}\) – \(\frac{5}{16}\) = \(\frac{12}{16}\) – \(\frac{7}{16}\) = \(\frac{5}{16}\)

Engage NY Math 5th Grade Module 3 Lesson 12 Sprint Answer Key 2

Question 1. \(\frac{2}{10}\) – \(\frac{1}{10}\) = Answer: \(\frac{2}{10}\) – \(\frac{1}{10}\) = \(\frac{1}{10}\)

Question 2. \(\frac{1}{5}\) – \(\frac{1}{10}\) = Answer: \(\frac{1}{5}\) – \(\frac{1}{10}\) = \(\frac{1}{10}\) Explanation : \(\frac{1}{5}\) – \(\frac{1}{10}\) = \(\frac{2}{10}\) – \(\frac{1}{10}\) = \(\frac{1}{10}\)

Question 3. \(\frac{2}{4}\) – \(\frac{1}{4}\) = Answer: \(\frac{2}{4}\) – \(\frac{1}{4}\) = \(\frac{1}{4}\)

Question 4. \(\frac{1}{2}\) – \(\frac{1}{4}\) = Answer: \(\frac{1}{2}\) – \(\frac{1}{4}\) = \(\frac{1}{4}\) Explanation : \(\frac{1}{2}\) – \(\frac{1}{4}\) = \(\frac{2}{4}\) – \(\frac{1}{4}\) = \(\frac{1}{4}\)

Question 5. \(\frac{5}{10}\) – \(\frac{2}{10}\) = Answer: \(\frac{5}{10}\) – \(\frac{2}{10}\) = \(\frac{3}{10}\)

Question 6. \(\frac{1}{2}\) – \(\frac{2}{10}\) = Answer: \(\frac{1}{2}\) – \(\frac{2}{10}\) = \(\frac{3}{10}\) Explanation : \(\frac{1}{2}\) – \(\frac{2}{10}\) = \(\frac{5}{10}\) – \(\frac{2}{10}\) = \(\frac{3}{10}\)

Question 7. \(\frac{1}{2}\) – \(\frac{4}{10}\) = Answer: \(\frac{1}{2}\) – \(\frac{4}{10}\) = \(\frac{1}{10}\) Explanation : \(\frac{1}{2}\) – \(\frac{4}{10}\) = \(\frac{5}{10}\) – \(\frac{4}{10}\) = \(\frac{1}{10}\)

Question 8. \(\frac{4}{10}\) – \(\frac{1}{10}\) = Answer: \(\frac{4}{10}\) – \(\frac{1}{10}\) = \(\frac{3}{10}\)

Question 9. \(\frac{2}{5}\) – \(\frac{1}{10}\) = Answer: \(\frac{2}{5}\) – \(\frac{1}{10}\) = \(\frac{3}{10}\) Explanation : \(\frac{2}{5}\) – \(\frac{1}{10}\) = \(\frac{4}{10}\) – \(\frac{1}{10}\) = \(\frac{3}{10}\)

Question 10. \(\frac{2}{5}\) – \(\frac{3}{10}\) = Answer: \(\frac{2}{5}\) – \(\frac{3}{10}\) = \(\frac{1}{10}\) Explanation : \(\frac{2}{5}\) – \(\frac{3}{10}\) = \(\frac{4}{10}\) – \(\frac{3}{10}\) = \(\frac{1}{10}\)

Question 11. \(\frac{6}{10}\) – \(\frac{3}{10}\) = Answer: \(\frac{6}{10}\) – \(\frac{3}{10}\) =\(\frac{3}{10}\)

Question 12. \(\frac{3}{5}\) – \(\frac{3}{10}\) = Answer: \(\frac{3}{5}\) – \(\frac{3}{10}\) = \(\frac{3}{10}\) Explanation : \(\frac{3}{5}\) – \(\frac{3}{10}\) = \(\frac{6}{10}\) – \(\frac{3}{10}\) = \(\frac{3}{10}\)

Question 13. \(\frac{3}{5}\) – \(\frac{5}{10}\) = Answer: \(\frac{3}{5}\) – \(\frac{5}{10}\) = \(\frac{1}{10}\) Explanation : \(\frac{3}{5}\) – \(\frac{5}{10}\) = \(\frac{6}{10}\) – \(\frac{5}{10}\) = \(\frac{1}{10}\)

Question 14. \(\frac{8}{10}\) – \(\frac{1}{10}\) = Answer: \(\frac{8}{10}\) – \(\frac{1}{10}\) =  \(\frac{7}{10}\)

Question 15. \(\frac{4}{5}\) – \(\frac{1}{10}\) = Answer: \(\frac{4}{5}\) – \(\frac{1}{10}\) = \(\frac{7}{10}\) Explanation : \(\frac{4}{5}\) – \(\frac{1}{10}\) = \(\frac{8}{10}\) – \(\frac{1}{10}\) =  \(\frac{7}{10}\)

Question 16. \(\frac{4}{5}\) – \(\frac{5}{10}\) = Answer: \(\frac{4}{5}\) – \(\frac{5}{10}\) = \(\frac{3}{10}\) Explanation : \(\frac{4}{5}\) – \(\frac{5}{10}\) = \(\frac{8}{10}\) – \(\frac{5}{10}\) =  \(\frac{4}{10}\)

Question 17. \(\frac{4}{5}\) – \(\frac{5}{10}\) = Answer: \(\frac{4}{5}\) – \(\frac{5}{10}\) = \(\frac{3}{10}\) Explanation : \(\frac{4}{5}\) – \(\frac{5}{10}\) = \(\frac{8}{10}\) – \(\frac{5}{10}\) =  \(\frac{4}{10}\)

Question 18. \(\frac{4}{5}\) – \(\frac{7}{10}\) = Answer: \(\frac{4}{5}\) – \(\frac{7}{10}\) = \(\frac{1}{10}\) Explanation : \(\frac{4}{5}\) – \(\frac{7}{10}\) = \(\frac{8}{10}\) – \(\frac{7}{10}\) =  \(\frac{1}{10}\)

Question 19. \(\frac{2}{8}\) – \(\frac{1}{8}\) = Answer: \(\frac{2}{8}\) – \(\frac{1}{8}\) = \(\frac{1}{8}\)

Question 20. \(\frac{1}{4}\) – \(\frac{1}{8}\) = Answer: \(\frac{1}{4}\) – \(\frac{1}{8}\) =\(\frac{1}{8}\) Explanation : \(\frac{1}{4}\) – \(\frac{1}{8}\) = \(\frac{2}{8}\) – \(\frac{1}{8}\) = \(\frac{1}{8}\)

Question 21. \(\frac{6}{8}\) – \(\frac{1}{8}\) = Answer: \(\frac{6}{8}\) – \(\frac{1}{8}\) = \(\frac{5}{8}\)

Question 22. \(\frac{3}{4}\) – \(\frac{1}{8}\) = Answer: \(\frac{3}{4}\) – \(\frac{1}{8}\) = \(\frac{5}{8}\) Explanation : \(\frac{3}{4}\) – \(\frac{1}{8}\) = \(\frac{6}{8}\) – \(\frac{1}{8}\) = \(\frac{5}{8}\)

Question 23. \(\frac{3}{4}\) – \(\frac{3}{8}\) = Answer: \(\frac{3}{4}\) – \(\frac{3}{8}\) = \(\frac{3}{8}\) Explanation : \(\frac{3}{4}\) – \(\frac{3}{8}\) = \(\frac{6}{8}\) – \(\frac{3}{8}\) = \(\frac{3}{8}\)

Question 24. \(\frac{5}{15}\) – \(\frac{1}{15}\) = Answer: \(\frac{5}{15}\) – \(\frac{1}{15}\) = \(\frac{4}{15}\)

Question 25. \(\frac{1}{3}\) – \(\frac{1}{15}\) = Answer: \(\frac{1}{3}\) – \(\frac{1}{15}\) =  \(\frac{4}{15}\) Explanation : \(\frac{1}{3}\) – \(\frac{1}{15}\) = \(\frac{5}{15}\) – \(\frac{1}{15}\) = \(\frac{4}{15}\)

Question 26. \(\frac{3}{15}\) – \(\frac{1}{15}\) = Answer: \(\frac{3}{15}\) – \(\frac{1}{15}\) = \(\frac{2}{15}\)

Question 27. \(\frac{1}{5}\) – \(\frac{1}{15}\) = Answer: \(\frac{1}{5}\) – \(\frac{1}{15}\) = \(\frac{2}{15}\) Explanation : \(\frac{1}{5}\) – \(\frac{1}{15}\) = \(\frac{3}{15}\) – \(\frac{1}{15}\) = \(\frac{2}{15}\)

Question 28. \(\frac{1}{5}\) – \(\frac{2}{15}\) = Answer: \(\frac{1}{5}\) – \(\frac{2}{15}\) = \(\frac{1}{15}\) Explanation : \(\frac{1}{5}\) – \(\frac{2}{15}\) = \(\frac{3}{15}\) – \(\frac{2}{15}\) = \(\frac{1}{15}\)

Question 29. \(\frac{12}{15}\) – \(\frac{4}{15}\) = Answer: \(\frac{12}{15}\) – \(\frac{4}{15}\) = \(\frac{8}{15}\)

Question 30. \(\frac{4}{5}\) – \(\frac{4}{15}\) = Answer: \(\frac{4}{5}\) – \(\frac{2}{15}\) = \(\frac{2}{3}\) Explanation : \(\frac{4}{5}\) – \(\frac{2}{15}\) = \(\frac{12}{15}\) – \(\frac{2}{15}\) = \(\frac{10}{15}\)= \(\frac{2}{3}\)

Question 31. \(\frac{1}{4}\) – \(\frac{2}{12}\) = Answer: \(\frac{1}{4}\) – \(\frac{2}{12}\) =  \(\frac{1}{12}\) Explanation : \(\frac{1}{4}\) – \(\frac{2}{12}\) = \(\frac{3}{12}\) – \(\frac{2}{12}\) = \(\frac{1}{12}\)

Question 32. \(\frac{3}{4}\) – \(\frac{2}{12}\) = Answer: \(\frac{3}{4}\) – \(\frac{2}{12}\) =  \(\frac{7}{12}\) Explanation : \(\frac{3}{4}\) – \(\frac{2}{12}\) = \(\frac{9}{12}\) – \(\frac{2}{12}\) = \(\frac{7}{12}\)

Question 33. \(\frac{3}{4}\) – \(\frac{4}{12}\) = Answer: \(\frac{3}{4}\) – \(\frac{4}{12}\) =  \(\frac{5}{12}\) Explanation : \(\frac{3}{4}\) – \(\frac{4}{12}\) = \(\frac{9}{12}\) – \(\frac{4}{12}\) = \(\frac{5}{12}\)

Question 34. \(\frac{3}{4}\) – \(\frac{8}{12}\) = Answer: \(\frac{3}{4}\) – \(\frac{8}{12}\) =  \(\frac{1}{12}\) Explanation : \(\frac{3}{4}\) – \(\frac{8}{12}\) = \(\frac{9}{12}\) – \(\frac{8}{12}\) = \(\frac{1}{12}\)

Question 35. \(\frac{1}{3}\) – \(\frac{3}{12}\) = Answer: \(\frac{1}{3}\) – \(\frac{3}{12}\) = \(\frac{1}{12}\) Explanation : \(\frac{1}{3}\) – \(\frac{3}{12}\) = \(\frac{4}{12}\) – \(\frac{3}{12}\) = \(\frac{1}{12}\)

Question 36. \(\frac{1}{6}\) – \(\frac{1}{12}\) = Answer: \(\frac{1}{6}\) – \(\frac{1}{12}\) =\(\frac{1}{12}\) Explanation : \(\frac{1}{6}\) – \(\frac{1}{12}\) = \(\frac{2}{12}\) – \(\frac{1}{12}\) = \(\frac{1}{12}\)

Question 37. \(\frac{1}{3}\) – \(\frac{3}{15}\) = Answer: \(\frac{1}{3}\) – \(\frac{3}{15}\) =  \(\frac{2}{15}\) Explanation : \(\frac{1}{3}\) – \(\frac{3}{15}\) = \(\frac{5}{15}\) – \(\frac{3}{15}\) = \(\frac{2}{15}\)

Question 38. \(\frac{2}{3}\) – \(\frac{2}{15}\) = Answer: \(\frac{2}{3}\) – \(\frac{2}{15}\) =  \(\frac{8}{15}\) Explanation : \(\frac{2}{3}\) – \(\frac{2}{15}\) = \(\frac{10}{15}\) – \(\frac{2}{15}\) = \(\frac{8}{15}\)

Question 39. \(\frac{2}{5}\) – \(\frac{2}{15}\) = Answer: \(\frac{2}{5}\) – \(\frac{2}{15}\) = \(\frac{4}{15}\) Explanation : \(\frac{2}{5}\) – \(\frac{2}{15}\) = \(\frac{6}{15}\) – \(\frac{2}{15}\) = \(\frac{4}{15}\)

Question 40. \(\frac{3}{4}\) – \(\frac{4}{12}\) = Answer: \(\frac{3}{4}\) – \(\frac{4}{12}\) =  \(\frac{5}{12}\) Explanation : \(\frac{3}{4}\) – \(\frac{4}{12}\) = \(\frac{9}{12}\) – \(\frac{4}{12}\) = \(\frac{5}{12}\)

Question 41. \(\frac{3}{4}\) – \(\frac{7}{16}\) = Answer: \(\frac{3}{4}\) – \(\frac{7}{16}\) = \(\frac{5}{16}\) Explanation : \(\frac{3}{4}\) – \(\frac{5}{16}\) = \(\frac{12}{16}\) – \(\frac{7}{16}\) = \(\frac{5}{16}\)

Question 42. \(\frac{4}{5}\) – \(\frac{4}{15}\) = Answer: \(\frac{4}{5}\) – \(\frac{4}{15}\) = \(\frac{8}{15}\) Explanation : \(\frac{4}{5}\) – \(\frac{4}{15}\) = \(\frac{12}{15}\) – \(\frac{4}{15}\) = \(\frac{8}{15}\)

Question 43. \(\frac{3}{4}\) – \(\frac{2}{12}\) = Answer: \(\frac{3}{4}\) – \(\frac{2}{12}\) =  \(\frac{7}{12}\) Explanation : \(\frac{3}{4}\) – \(\frac{2}{12}\) = \(\frac{9}{12}\) – \(\frac{2}{12}\) = \(\frac{7}{12}\)

Question 44. \(\frac{3}{4}\) – \(\frac{5}{16}\) = Answer: \(\frac{3}{4}\) – \(\frac{5}{16}\) = \(\frac{7}{16}\) Explanation : \(\frac{3}{4}\) – \(\frac{5}{16}\) = \(\frac{12}{16}\) – \(\frac{5}{16}\) = \(\frac{7}{16}\)

Eureka Math Grade 5 Module 3 Lesson 12 Problem Set Answer Key

Question 1. Subtract. a. 3\(\frac{1}{5}\) – 2\(\frac{1}{4}\) = b. 4\(\frac{2}{5}\) – 3\(\frac{3}{4}\) = c. 7\(\frac{1}{5}\) – 4\(\frac{1}{5}\) = d. 7\(\frac{2}{5}\) – 5\(\frac{2}{3}\) = e. 4\(\frac{2}{7}\) – 3\(\frac{1}{3}\) = f. 9\(\frac{2}{3}\) – 2\(\frac{6}{7}\) = g. 17\(\frac{2}{3}\) – 5\(\frac{5}{6}\) = h. 18\(\frac{1}{3}\) – 3\(\frac{3}{8}\) = Answer: a. 3\(\frac{1}{5}\) – 2\(\frac{1}{4}\) = \(\frac{19}{20}\) Explanation : 3\(\frac{1}{5}\) – 2\(\frac{1}{4}\) = \(\frac{16}{5}\) – \(\frac{9}{4}\) lcm of 5 and 4 is 20 . \(\frac{64}{20}\) – \(\frac{45}{20}\) = \(\frac{19}{20}\)

b. 4\(\frac{2}{5}\) – 3\(\frac{3}{4}\) = \(\frac{13}{20}\) Explanation : 4\(\frac{2}{5}\) – 3\(\frac{3}{4}\) = \(\frac{22}{5}\) – \(\frac{15}{4}\) lcm of 5 and 4 is 20 . \(\frac{88}{20}\) – \(\frac{75}{20}\) = \(\frac{13}{20}\)

c. 7\(\frac{1}{5}\) – 4\(\frac{1}{5}\) = Explanation : 7\(\frac{1}{5}\) – 4\(\frac{1}{5}\) = \(\frac{36}{5}\) – \(\frac{21}{5}\) = \(\frac{15}{5}\) = 3 .

d. 7\(\frac{2}{5}\) – 5\(\frac{2}{3}\) = 1\(\frac{11}{15}\) . Explanation : 7\(\frac{2}{5}\) – 5\(\frac{2}{3}\) = \(\frac{37}{5}\) – \(\frac{17}{3}\) lcm of 5 and 3 is 15 . \(\frac{111}{15}\) – \(\frac{85}{15}\) = \(\frac{26}{15}\) = 1\(\frac{11}{15}\) .

e. 4\(\frac{2}{7}\) – 3\(\frac{1}{3}\) = \(\frac{20}{21}\) Explanation : 4\(\frac{2}{7}\) – 3\(\frac{1}{3}\) = \(\frac{30}{7}\) – \(\frac{10}{3}\) lcm of 7 and 3 is 21. \(\frac{90}{21}\) – \(\frac{70}{21}\) = \(\frac{20}{21}\)

f. 9\(\frac{2}{3}\) – 2\(\frac{6}{7}\) = 6\(\frac{17}{21}\) Explanation : 9\(\frac{2}{3}\) – 2\(\frac{6}{7}\) = \(\frac{29}{3}\) – \(\frac{20}{7}\) lcm of 3 and 7 is 21. \(\frac{203}{21}\) – \(\frac{60}{21}\) = \(\frac{143}{21}\) = 6\(\frac{17}{21}\)

g. 17\(\frac{2}{3}\) – 5\(\frac{5}{6}\) = 11\(\frac{5}{6}\) Explanation : 17\(\frac{2}{3}\) – 5\(\frac{5}{6}\) = \(\frac{53}{3}\) – \(\frac{35}{6}\) lcm of 3 and 6 is 6 . \(\frac{106}{6}\) – \(\frac{35}{6}\) = \(\frac{71}{6}\) = 11\(\frac{5}{6}\)

h. 18\(\frac{1}{3}\) – 3\(\frac{3}{8}\) = 14\(\frac{23}{24}\) Explanation : 18\(\frac{1}{3}\) – 3\(\frac{3}{8}\) = \(\frac{55}{3}\) – \(\frac{27}{8}\) lcm of 3 and 8 is 24 . \(\frac{440}{24}\) – \(\frac{81}{24}\) = \(\frac{359}{24}\) = 14\(\frac{23}{24}\)

Engage-NY-Eureka-Math-5th-Grade-Module-3-Lesson-12-Answer-Key-Eureka-Math-Grade-5-Module-3-Lesson-12-Problem-Set-Answer-Key-Question-2

Question 3. Mr. Neville Iceguy mixed up 12\(\frac{3}{5}\) gallons of chili for a party. If 7\(\frac{3}{4}\)gallons of chili was mild, and the rest was extra spicy, how much extra spicy chili did Mr. Iceguy make? Answer: Fraction of chili mixed up for a party = 12\(\frac{3}{5}\) gallons = \(\frac{63}{5}\) gallons Fraction of chilli is mild = 7\(\frac{3}{4}\)gallons = \(\frac{31}{4}\)gallons Fraction of chilli is extra spicy = x \(\frac{63}{5}\) =  \(\frac{31}{4}\) + x x = \(\frac{63}{5}\) – \(\frac{31}{4}\) lcm of 5 and 4 is 20 . x = \(\frac{252}{20}\) – \(\frac{155}{20}\) = \(\frac{97}{20}\) = 4\(\frac{17}{20}\) Therefore, Fraction of chilli is extra spicy = x = 4\(\frac{17}{20}\) gallons .

Question 4. Jazmyne decided to spend 6\(\frac{1}{2}\) hours studying over the weekend. She spent 1\(\frac{1}{4}\) hours studying on Friday evening and 2\(\frac{2}{3}\) hours on Saturday. How much longer does she need to spend studying on Sunday in order to reach her goal? Answer: Total Fraction of time should spend on Studying = 6\(\frac{1}{2}\) hours = \(\frac{13}{2}\) hours Fraction of Time spent on Friday for studying = 1\(\frac{1}{4}\) hours = \(\frac{5}{4}\) hours Fraction of Time spent on Saturday for studying = 2\(\frac{2}{3}\) hours = \(\frac{8}{3}\) hours Fraction of Time should spend on Sunday for studying = x \(\frac{13}{2}\) = \(\frac{5}{4}\) + \(\frac{8}{3}\) + x lcm of 2 , 4 , and 3 is 12 . x = \(\frac{13}{2}\) – \(\frac{5}{4}\) – \(\frac{8}{3}\) x = \(\frac{78}{12}\) – \(\frac{15}{12}\) – \(\frac{32}{12}\) x = \(\frac{78}{12}\) – \(\frac{47}{12}\) x = \(\frac{31}{12}\) x = 2\(\frac{7}{12}\) Therefore, Fraction of Time should spend on Sunday for studying = x = 2\(\frac{7}{12}\) hours .

Eureka Math Grade 5 Module 3 Lesson 12 Exit Ticket Answer Key

Subtract. Question 1. 5\(\frac{1}{2}\) – 1\(\frac{1}{3}\) = Answer: 5\(\frac{1}{2}\) – 1\(\frac{1}{3}\) = 4\(\frac{1}{6}\) . Explanation : 5\(\frac{1}{2}\) – 1\(\frac{1}{3}\) = \(\frac{11}{2}\) – \(\frac{4}{3}\) lcm of 2 and 3 is 6 \(\frac{33}{6}\) – \(\frac{8}{6}\) = \(\frac{25}{6}\) = 4\(\frac{1}{6}\) .

Question 2. 8\(\frac{3}{4}\) – 5\(\frac{5}{6}\) = Answer: 8\(\frac{3}{4}\) – 5\(\frac{5}{6}\) = 2\(\frac{11}{12}\) Explanation : 8\(\frac{3}{4}\) – 5\(\frac{5}{6}\) = \(\frac{35}{4}\) – \(\frac{35}{6}\) lcm of 4 and 6 is 12 . \(\frac{105}{12}\) – \(\frac{70}{12}\) = \(\frac{35}{12}\) = 2\(\frac{11}{12}\)

Eureka Math Grade 5 Module 3 Lesson 12 Homework Answer Key

Question 1. Subtract. a. 3\(\frac{1}{4}\) – 2\(\frac{1}{3}\) = b. 3\(\frac{2}{3}\) – 2\(\frac{3}{4}\) = c. 6\(\frac{1}{5}\) – 4\(\frac{1}{4}\) = d. 6\(\frac{3}{5}\) – 4\(\frac{3}{4}\) = e. 5\(\frac{2}{7}\) – 4\(\frac{1}{3}\) = f. 8\(\frac{2}{3}\) – 3\(\frac{5}{7}\) = g. 18\(\frac{3}{4}\) – 5\(\frac{7}{8}\) = h. 17\(\frac{1}{5}\) – 2\(\frac{5}{8}\) = Answer: a. 3\(\frac{1}{4}\) – 2\(\frac{1}{3}\) = \(\frac{11}{12}\) Explanation : 3\(\frac{1}{4}\) – 2\(\frac{1}{3}\) = \(\frac{13}{4}\) – \(\frac{7}{3}\) lcm of 4 and 3 is 12 \(\frac{39}{12}\) – \(\frac{28}{12}\) = \(\frac{11}{12}\)

b. 3\(\frac{2}{3}\) – 2\(\frac{3}{4}\) = \(\frac{11}{12}\) Explanation : 3\(\frac{2}{3}\) – 2\(\frac{3}{4}\) = \(\frac{11}{3}\) – \(\frac{11}{4}\) lcm of 3 and 4 is 12 \(\frac{44}{12}\) – \(\frac{33}{12}\) = \(\frac{11}{12}\)

c. 6\(\frac{1}{5}\) – 4\(\frac{1}{4}\) = 3\(\frac{13}{20}\) Explanation : 6\(\frac{1}{5}\) – 4\(\frac{1}{4}\) = \(\frac{31}{5}\) – \(\frac{17}{4}\) lcm of 4 and 5 is 20 . \(\frac{124}{20}\) – \(\frac{51}{20}\) = \(\frac{73}{20}\) = 3\(\frac{13}{20}\) .

d. 6\(\frac{3}{5}\) – 4\(\frac{3}{4}\) = 1\(\frac{17}{20}\) Explanation : 6\(\frac{3}{5}\) – 4\(\frac{3}{4}\) = \(\frac{33}{5}\) – \(\frac{19}{4}\) lcm of 4 and 5 is 20 . \(\frac{132}{20}\) – \(\frac{95}{20}\) = \(\frac{37}{20}\) = 1\(\frac{17}{20}\)

e. 5\(\frac{2}{7}\) – 4\(\frac{1}{3}\) = \(\frac{20}{21}\) Explanation : 5\(\frac{2}{7}\) – 4\(\frac{1}{3}\) = \(\frac{37}{7}\) – \(\frac{13}{3}\) lcm of 3 and 7 is 21. \(\frac{111}{21}\) – \(\frac{91}{21}\) = \(\frac{20}{21}\)

f. 8\(\frac{2}{3}\) – 3\(\frac{5}{7}\) = 4\(\frac{20}{21}\) Explanation : 8\(\frac{2}{3}\) – 3\(\frac{5}{7}\) = \(\frac{26}{3}\) – \(\frac{26}{7}\) lcm of 3 and 7 is 21. \(\frac{182}{21}\) – \(\frac{78}{21}\) = \(\frac{104}{21}\) = 4\(\frac{20}{21}\)

g. 18\(\frac{3}{4}\) – 5\(\frac{7}{8}\) = 11\(\frac{9}{8}\) Explanation : 18\(\frac{3}{4}\) – 5\(\frac{7}{8}\) = \(\frac{75}{4}\) – \(\frac{47}{8}\) lcm of 4 and 8 is 8 . \(\frac{130}{8}\) – \(\frac{47}{8}\) = \(\frac{97}{8}\) = 11\(\frac{9}{8}\)

h. 17\(\frac{1}{5}\) – 2\(\frac{5}{8}\) = 14\(\frac{23}{40}\) Explanation : 17\(\frac{1}{5}\) – 2\(\frac{5}{8}\) = \(\frac{86}{5}\) – \(\frac{21}{8}\) lcm of 5 and 8 is 40 . \(\frac{688}{40}\) – \(\frac{105}{40}\) = \(\frac{583}{40}\) = 14\(\frac{23}{40}\)

Engage-NY-Eureka-Math-5th-Grade-Module-3-Lesson-12-Answer-Key-Eureka-Math-Grade-5-Module-3-Lesson-12-Homework-Answer-Key-Question-2

Question 3. Ms. Sanger blended 8\(\frac{3}{4}\) gallons of iced tea with some lemonade for a picnic. If there were 13\(\frac{2}{5}\) gallons of the beverage, how many gallons of lemonade did she use? Answer: Fraction of gallons of iced tea with some lemonade for a picnic = 8\(\frac{3}{4}\) = \(\frac{35}{4}\) gallons . Fraction of gallons of the beverage = 13\(\frac{2}{5}\) = \(\frac{67}{5}\) . Fraction of gallons of the lemonade = x \(\frac{67}{5}\) = \(\frac{35}{4}\) – x x =  \(\frac{67}{5}\) – \(\frac{35}{4}\) lcm of 4 and 5 is 20 . x = \(\frac{268}{20}\) – \(\frac{175}{20}\) x = \(\frac{93}{20}\) = 4\(\frac{13}{20}\) Therefore, Fraction of gallons of the lemonade = x = 4\(\frac{13}{20}\) gallons .

Question 4. A carpenter has 10\(\frac{1}{2}\) feet of wooden plank. He cuts off 4\(\frac{1}{4}\) feet to replace the slat of a deck and 3\(\frac{2}{3}\) feet to repair a bannister. He uses the rest of the plank to fix a stair. How many feet of wood does the carpenter use to fix the stair? Answer: Total Fraction of wooden plank = 10\(\frac{1}{2}\) feet = \(\frac{21}{2}\) feet Fraction of wooden plank cut off = 4\(\frac{1}{4}\) feet = \(\frac{17}{4}\) feet Fraction of wooden plank used to repair a bannister = 3\(\frac{2}{3}\) feet = \(\frac{11}{3}\) feet Fraction of wooden plank used for stair = x feet 10\(\frac{1}{2}\) = \(\frac{17}{4}\) + \(\frac{11}{3}\) + x \(\frac{21}{2}\) = \(\frac{17}{4}\) + \(\frac{11}{3}\) + x lcm of 2 , 4 and 3 is 12 . \(\frac{126}{12}\) = \(\frac{51}{4}\) + \(\frac{44}{3}\) + x x = \(\frac{126}{12}\) – \(\frac{95}{4}\) x = \(\frac{31}{4}\) = 7\(\frac{3}{4}\) . Therefore, Fraction of wooden plank used for stair = 7\(\frac{3}{4}\) feet .

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