, important questions, mcq's, ncert solutions - class 12 chemistry.
Get here all the Important questions for Class 12 Chemistry chapter wise as free PDF download. Here you will get Extra Important Questions with answers, Numericals and Multiple Choice Questions (MCQ's) chapter wise in Printable format. Solving Chapter wise questions is one of the best ways to prepare for the examination. Students are advised to understand the concepts and theories of Chemistry properly before the exam. You can easily find 1 Mark, 2 marks, 3 marks, and 5 marks questions from each chapter of Class 12 Chemistry and prepare for exam more effectively. These preparation material for Class 12 Chemistry , shared by teachers, parents and students, are as per latest NCERT and CBSE Pattern syllabus and assure great success in achieving high score in Final CBSE Board Examinations.
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CBSE Class 12 Chemistry Syllabus
Unit II: Solutions 15 Periods
Types of solutions, expression of concentration of solutions of solids in liquids, solubility of gases in liquids, solid solutions, Raoult's law, colligative properties - relative lowering of vapour pressure, elevation of boiling point, depression of freezing point, osmotic pressure, determination of molecular masses using colligative properties, abnormal molecular mass, Van't Hoff factor.
Unit III: Electrochemistry 18 Periods
Redox reactions, EMF of a cell, standard electrode potential, Nernst equation and its application to chemical cells, Relation between Gibbs energy change and EMF of a cell, conductance in electrolytic solutions, specific and molar conductivity, variations of conductivity with concentration, Kohlrausch's Law, electrolysis and law of electrolysis (elementary idea), dry cell-electrolytic cells and Galvanic cells, lead accumulator, fuel cells, corrosion.
Unit IV: Chemical Kinetics 15 Periods
Rate of a reaction (Average and instantaneous), factors affecting rate of reaction: concentration, temperature, catalyst; order and molecularity of a reaction, rate law and specific rate constant, integrated rate equations and half-life (only for zero and first order reactions), concept of collision theory (elementary idea, no mathematical treatment), activation energy, Arrhenius equation.
Unit VIII: d and f Block Elements 18 Periods
General introduction, electronic configuration, occurrence and characteristics of transition metals, general trends in properties of the first-row transition metals – metallic character, ionization enthalpy, oxidation states, ionic radii, colour, catalytic property, magnetic properties, interstitial compounds, alloy formation, preparation and properties of K2Cr2O7 and KMnO4.
Lanthanoids – Electronic configuration, oxidation states, chemical reactivity and lanthanoid contraction and its consequences.
Actinoids - Electronic configuration, oxidation states and comparison with lanthanoids.
Unit IX: Coordination Compounds 18 Periods
Coordination compounds - Introduction, ligands, coordination number, colour, magnetic properties and shapes, IUPAC nomenclature of mononuclear coordination compounds. Bonding, Werner's theory, VBT, and CFT; structure and stereoisomerism, the importance of coordination compounds (in qualitative analysis, extraction of metals and biological system).
Unit X: Haloalkanes and Haloarenes. 15 Periods Haloalkanes: Nomenclature, nature of C–X bond, physical and chemical properties, optical rotation mechanism of substitution reactions.
Haloarenes: Nature of C–X bond, substitution reactions (Directive influence of halogen in monosubstituted compounds only). Uses and environmental effects of - dichloromethane, trichloromethane, tetrachloromethane, iodoform, freons, DDT.
Unit XI: Alcohols, Phenols and Ethers 14 Periods
Alcohols: Nomenclature, methods of preparation, physical and chemical properties (of primary alcohols only), identification of primary, secondary and tertiary alcohols, mechanism of dehydration, uses with special reference to methanol and ethanol.
Phenols: Nomenclature, methods of preparation, physical and chemical properties, acidic nature of phenol, electrophilic substitution reactions, uses of phenols.
Ethers: Nomenclature, methods of preparation, physical and chemical properties, uses.
Unit XII: Aldehydes, Ketones and Carboxylic Acids 15 Periods
Aldehydes and Ketones: Nomenclature, nature of carbonyl group, methods of preparation, physical and chemical properties, mechanism of nucleophilic addition, reactivity of alpha hydrogen in aldehydes, uses.
Carboxylic Acids: Nomenclature, acidic nature, methods of preparation, physical and chemical properties; uses.
Unit XIII: Amines 14 Periods
Amines: Nomenclature, classification, structure, methods of preparation, physical and chemical properties, uses, identification of primary, secondary and tertiary amines.
Diazonium salts: Preparation, chemical reactions and importance in synthetic organic chemistry.
Unit XIV: Biomolecules 18 Periods
Carbohydrates - Classification (aldoses and ketoses), monosaccharides (glucose and fructose), D-L configuration oligosaccharides (sucrose, lactose, maltose), polysaccharides (starch, cellulose, glycogen); Importance of carbohydrates.
Proteins - Elementary idea of - amino acids, peptide bond, polypeptides, proteins, structure of proteins - primary, secondary, tertiary structure and quaternary structures (qualitative idea only), denaturation of proteins; enzymes. Hormones - Elementary idea excluding structure.
Vitamins - Classification and functions. Nucleic Acids: DNA and RNA.
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Case studies play a pivotal role in CBSE Class 12 Chemistry, as they enable students to apply theoretical knowledge to real-life scenarios. CBSE Class 12 Chemistry Case Study Questions PDF section introduces the significance of case studies in enhancing analytical skills and understanding complex chemical reactions.
Case studies challenge students to think critically, analyze experimental data, and devise problem-solving strategies. They provide a deeper understanding of chemical principles and their practical applications, fostering a holistic learning experience. Familiarize yourself with the structure of case study questions to streamline your preparation. Each case study presents a unique chemical problem, encouraging students to identify relevant concepts and devise accurate solutions.
Table of Contents
CBSE Class 12 Chemistry question paper will have case study questions too. These case-based questions will be objective type in nature. So, Class 12 Chemistry students must prepare themselves for such questions. First of all, you should study NCERT Textbooks line by line, and then you should practice as many questions as possible.
Class 12 students should go through important Case Study problems for Chemistry before the exams. This will help them to understand the type of Case Study questions that can be asked in Grade 12 Chemistry examinations. Our expert faculty for standard 12 Chemistry have designed these questions based on the trend of questions that have been asked in last year’s exams. The solutions have been designed in a manner to help the grade 12 students understand the concepts and also easy-to-learn solutions.
Excel in your Chemistry exams with these practical tips.
Consistent practice with case study questions enhances your ability to tackle complex problems. Dedicate time to solving various case studies to build confidence.
Develop strong analytical skills to approach case studies logically. Break down complex problems into simpler components and analyze them step-by-step.
Allocate sufficient time for each case study during the exam. Practice time management in mock tests to complete the paper within the stipulated time.
Strictly as per the new term-wise syllabus for Board Examinations to be held in the academic session 2024 for class 12 Multiple Choice Questions based on new typologies introduced by the board- Stand-Alone MCQs, MCQs based on Assertion-Reason Case-based MCQs. Include Questions from CBSE official Question Bank released in April 2024 Answer key with Explanations What are the updates in the book: Strictly as per the Term wise syllabus for Board Examinations to be held in the academic session 2024. Chapter-wise -Topic-wise Multiple choice questions based on the special scheme of assessment for Board Examination for Class 12th Chemistry.
Mastering CBSE Class 12 Chemistry case study questions is crucial for excelling in the exams. Embrace case studies as a valuable learning tool, and with practice, you’ll ace your Chemistry exams with confidence.
The CBSE Class 12 Chemistry case study PDF brings a refreshing perspective to the world of education. By intertwining theoretical knowledge with practical applications, it equips students to face real-world challenges with confidence. The diverse case studies provide invaluable insights, encouraging students to explore chemistry beyond the classroom and make a positive impact on society.
The CBSE Class 12 Chemistry case study PDF is a curated document by CBSE, presenting real-life applications of chemistry concepts for students to understand the subject’s practical relevance.
The case study PDF enhances the learning experience, fosters critical thinking, promotes application-based learning, and prepares students for examinations.
Yes, the case studies cover various branches of chemistry, including organic, inorganic, physical, environmental, and analytical chemistry.
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Class 12 chemistry important questions with answers are provided here for chapter 3 Electrochemistry. These important questions are based on CBSE board curriculum and correspond to the most recent Class 12 chemistry syllabus. By practicing these Class 12 important questions, students will be able to quickly review all of the ideas covered in the chapter and prepare for the Class 12 Annual examinations as well as other entrance exams such as NEET and JEE.
Download Class 12 Chemistry Chapter 3 – Electrochemistry Important Questions with Answers PDF by clicking on the button below.
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Electrochemistry class 12 chemistry one shot and mind maps.
Short answer type questions.
1. Can absolute electrode potential of an electrode be measured?
Solution: No, the absolute potential of an electrode can not be measured because the half-cell containing a single electrode cannot work on its own. It can work only in combination with another half cell.
2. Can E 0 cell or Δ r G 0 for a cell reaction ever be equal to zero?
Solution: No, it cannot be equal to zero for a cell reaction proceeding in a particular direction (forward or backward direction)
3. Under what conditions is E 0 cell = 0 and Δ r G 0 = 0 ?
Solution: At the condition of equilibrium, E 0 cell = 0 and Δ r G 0 = 0
4. What does the negative sign in the expression E 0 Zn2+ /Zn = – 0.76 V means?
Solution: It implies that Zn is more reactive than hydrogen or it is a stronger reducing agent. In a cell containing zinc electrode and standard hydrogen electrode present in two half cells, zinc will be oxidised to Zn 2+ ions while H + ions will get reduced to hydrogen.
5. Aqueous copper sulphate solution and aqueous silver nitrate solution are electrolysed by 1 ampere current for 10 minutes in separate electrolytic cells. Will the mass of copper and silver deposited on the cathode be same or different ? Explain your answer.
Solution: The mass of copper and silver deposited on the cathode in the two electrolytic cells will not be the same.
According to second law of Electrolysis.
(Mass of Cu deposited /mass of Ag deposited) = (equivalent mass of Cu/equivalent mass of Ag)
= 31.75/ 108.
6. Depict the galvanic cell in which the cell reaction is : Cu + 2Ag + → 2Ag + Cu 2+ .
Solution: In the cell reaction: Cu + 2Ag + → 2Ag + Cu 2+
At anode : Cu → Cu 2+ + 2e
At Cathode : 2 Ag + + 2e → 2Ag
The representation of cell = Cu(s) | Cu 2+ (aq) || Ag + (aq) | Ag (s)
7. Value of standard electrode potential for the oxidation of Cl – ions is more positive than that of water, even then in the electrolysis of aqueous sodium chloride, why are Cl – ions oxidised at anode instead of water ?
Solution: The oxidation reactions taking place at anode is:
2Cl – (aq) → Cl 2 (g) + 2e – E 0 (oxid) = -1.36 V
2H 2 O (l) → O 2 (g) + 4H + (aq) + 4e – E 0 (oxid) = -1.23 V
Due to the overvoltage of oxygen (O₂), its liberation is kinetically slower than that of CI ions. Therefore, Cl ions are oxidised to Cl₂ gas.
8. What is electrode potential ?
Solution: Electrode potential appears at the interface between an electrode and electrolyte due to the transfer of charged species across the interface.
9. Why is alternating current used for measuring resistance of an electrolytic solution?
Solution: Alternate current is used for measuring the resistance of an electrolytic solution because direct current will cause the electrolysis of the electrolyte. As a result Concentration of the ions in the solution will change.
10. How will the pH of brine (NaCl solution) be affected when it is electrolysed?
Solution: NaCl is a salt of strong acid and strong base. It is neutral in nature. pH of NaCl solution is 7. However, upon electrolysis of the aqueous solution, Na + and OH – ions are formed. The solution becomes basic and its pH rises.
11. Solutions of two electrolytes ‘A’ and ‘B’ are diluted. The Λ m of ‘B’ increases 1.5 times while that of A increases 25 times. Which of the two is a strong electrolyte? Justify your answer.
Solution: Dilution of the electrolyte mainly decreases interionic attractive force, therefore Λ m increases. In case of strong electrolyte it dissociated completely in solution so on dilution Λ m increases to a small extent. On the other hand, the electrolyte weak is ionised only to a small extent. Upon dilution, its ionisation or dissociation increases to a large extent. That is why, Λ m for weak electrolyte is more higher on dilution.
From the available information A is a weak electrolytes and B is a strong electrolyte.
12. In an aqueous solution how does specific conductivity of electrolytes change with addition of water?
Solution: The specific conductivity or conductivity (🇰) of electrolytes decreases with the addition of water or upon dilution because the number of ions per unit volume decrease.
13. Which reference electrode is used to measure the electrode potential of other electrodes ?
Solution : Standard hydrogen electrode (SHE) is used as reference electrode to measure the electrode potential of other electrodes. Its electrode potential is assumed as zero. The electrode potential of any electrode as measured with respect to a standard hydrogen electrode is known as its standard electrode potential (E).
14. Consider a cell given below
Cu |Cu²+ || Cl- | Cl₂, Pt
Write the reactions that occur at anode and cathode.
Solution: The reaction taking place at the two electrodes are:
At anode : Cu(s) → Cu 2+ (aq) + 2e –
At cathode: Cl 2 (g) + 2e – → 2 Cl –
15. Write the Nernst equation for the cell reaction in the Daniell cell. How will the E cell be affected when concentration of Zn 2+ ions is increased ?
Solution: Daniell cell involves the redox reaction :
Zn(s) + CuSO 4 (aq) → ZnSO 4 (aq) + Cu(s)
Thus in the cell Zn(s) is oxidised to Zn²+ (aq) ions in the oxidation half cell while Cu²+ (aq) ions are reduced to Cu(s) in the reduction half cell.
According to Nernst equation,
Hence E cell decreases as the [Zn 2+ (aq)] increases.
16. What advantage do the fuel cells have over primary and secondary batteries?
Solution: Primary batteries or cells contain a limited amount of reactants and are discharged when the reactants are consumed. Secondary batteries or cells can be recharged but the process takes a long time. Fuel cells work continuously as long the reactants (i.e. fuel) are supplied.
17. Write the cell reaction of a lead storage battery when it is discharged. How does the density of the electrolyte change when the battery is discharged?
Solution: The cell reaction of a lead storage battery when it is discharged, may be given as:
Pb(s) + 4H + (aq) + 2SO 4 2- (aq) → PbO₂(s) + 2PbSO4 (s) + 2H₂O(l)
Density of the electrolyte i.e. conc.H 2 SO 4 solution decreases because of the dilution of electrolyte taking place since water is formed as one of the products.
18. Why on dilution the Λ m of CH 3 COOH increases drastically, while that of CH 3 COONa increases gradually?
Solution: CH 3 COOH is a weak electrolyte and is dissociated to small extent. With dilution, its degree of dissociation increases i.e. more ions are released in solution. Therefore, Λ m of CH 3 COOH increases drastically. On the other hand, CH 3 COONa is a strong electrolyte and is almost completely dissociated in aqueous solution. With dilution, only interionic forces of attraction increase resulting in only small increase in the value of Λ m .
1. Match the terms given in Column I with the units given in Column II.
Solution: (a) – (iii); (b) – (iv); (c) – (i); (d) – (ii)
2. Match the items of Column I and Column II.
Solution: (a) – (iv); (b) – (iii); (c) – (i); (d) – (ii)
3. Match the items of Column I and Column II.
Solution: (a) – (iv); (b) – (iii); (c) – (ii); (d) – (i)
4. Match the items of Column I and Column II.
Solution: (a) – (iv); (b) – (iii); (c) – (i),(v); (d) – (ii)
Note: In the following questions a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices:
(a) Both assertion and reason are true and the reason is correct explanation for assertion.
(b) Both assertion and reason are true and the reason is not correct explanation for assertion.
(c) Assertion is true but the reason is false.
(d) Both assertion and reason are false.
(e) Assertion is false but reason is true.
1. Assertion : Cu is less reactive than hydrogen.
Reason : E 0 Cu2+/Cu is negative.
Solution: (c) Assertion is true but the reason is false.
2. Assertion: E cell should have a positive value for the cell to function.
Reason: E cathode < E anode
3. Assertion : Conductivity of all electrolytes decreases on dilution.
Reason : On dilution number of ions per unit volume decreases.
Solution: (a) Both assertion and reason are true and the reason is correct explanation for assertion.
4. Assertion : Λ m for weak electrolytes shows a sharp increase when the electrolytic solution is diluted.
Reason : For weak electrolytes degree of dissociation increases with dilution of solution.
5. Assertion :Mercury cell does not give steady potential.
Reason: In the cell reaction, ions are not involved in solution.
Solution: (e) Assertion is false but reason is true.
1. Define the terms specific conductance, molar conductance and equivalent conductance. Derive the relationship between molar conductance and equivalent conductance.
(a) Specific conductance:
The reciprocal of specific resistance is termed as specific conductance or it is the conductance of one centimeter cube of a conductor.
It is denoted by the symbol 🇰 (kappa).
🇰 = 1/ρ or 🇰 = (l/a) x C
Specific conductance is also called conductivity.
(b) Molar conductance:
Molar conductance is defined as the conductance of all the ions produced by ionisation of 1 g- mole of an electrolyte when present in per litre of solution. It is denoted by Λ m .
Molar conductance Λ m = k x 1000/M
(c) Equivalent conductance:
Equivalent conductance is defined as the conductance of all ions produced by one gram-equivalent of an electrolyte present per litre of solution. It is denoted by Λ eq .
Equivalent conductance Λ eq = k x 1000/N.
Relationship between molar conductance and equivalent conductance.
Λ m = k x 1000/M , Λ eq = k x 1000/N
∴ Λ m / Λ eq = n
Where n= valence factor.
2. State Kohlrausch’s law. How does the law help in calculating Λ 0 ∞ CH 3 COOH ?
At infinite dilution, when dissociation is complete, each ion makes a definite contribution towards equivalent conductance of the electrolyte irrespective of the nature of the ion with which it is associated and the value of equivalent conductance at infinite dilution for any electrolyte is the sum of contribution of its constituent ions”, i. e. anions and cations.
Λ ∞ = λ a + λ c
The λ a and λ c are called the ionic conductances of cation and a anion at infinite dilution respectively.
The molar conductivity of an strong electrolyte at infinite dilution is the sum of the ionic conductivity of the cations and anions.
In case of weak electrolytes, it is not possible to determine the value of limiting molar conductance at infinite dilution. However this can be determine by using Kohlrausch’s law.
Example CH3COOH is a weak electrolyte.
Λ ∞ m (CH3COOH) = λ m ∞ (CH3COO-) + λ m ∞ (H + )
= Λ ∞ m (CH3COONa) + Λ ∞ m (HCl) – Λ ∞ m (NaCl)
3. What is the relationship between Gibbs free energy of the cell reaction in a galvanic cell and the emf or E cell ? When will the maximum work be obtained from a galvanic cell ?
The relation may be given as :
ΔG = -nF E cell
If the redox reaction is under standard conditions, then
ΔG° = -nFE cell
Here nF is the quantity of charge passed. In case we want to obtain maximum work from the galvanic charge has to be passed reversibly. As pointed above, the reversible work done by the galvanic cell is equal decrease in its Gibbs free energy.
4. What is Nernst equation ? write the Nernst equation for the reaction.
2Cr(s) + 3Cd 2+ (aq) → 2Cr 3+ (aq) + 3Cd (s)
Nernst equation is an equation relating the capacity of an atom/ion to take up one or more electrons (reduction potential) measured at any conditions to that measured at standard conditions (standard reduction potentials) of 298K and one molar or one atmospheric pressure .
E cell = E 0 – [RT/nF] ln Q
E cell = cell potential of the cell
E 0 = cell potential under standard conditions
R = universal gas constant
T = temperature
n = number of electrons transferred in the redox reaction
F = Faraday constant
Q = reaction quotient
In the equation : 2Cr(s) + 3Cd 2+ (aq) → 2Cr 3+ (aq) + 3Cd (s)
E cell = E 0 – [RT/nF] ln {[Cr 3+ ] 2 /[Cd 2+ ] 3 }
5. State Faraday’s first law of electrolysis. How much charge in terms of Faraday is required for reduction of 1 mole of Cu 2+ ions to Cu?
When an electric current is passed through an electrolyte, the amount of substance deposited is proportional to the quantity of electric charge passed through the electrolyte.
If W be the mass of the substance deposited by passing Q coulomb of charge, then according to the law, we have the relation:
A coulomb is the quantity of charge when a current of one ampere is passed for one second. Thus, amount of charge in coulombs,
Q = current in amperes x time in seconds
W = Z x I x t
where, Z is a constant, known as electrochemical equivalent, and is characteristic of the substance deposited.
When a current of one ampere is passed for one second,i.e one coulomb (Q = 1), then
The electrode reaction is Cu 2+ + 2e−→Cu
∴ quantity of charge required for reduction of 1 mole of Cu2+ =2F
Cu 2+ =2F =2×96500=193000C
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Electrochemistry case study questions with answer key.
Final Semester - June 2015
Read the passage given below and answer the following questions: Molar conductivity of ions are given as product of charge on ions to their ionic mobilities and Faraday's constant. \(\lambda_{A^{n+}}=n \mu_{A^{n+}} F\) (here \(\mu\) is the ionic mobility of A n+ ). For electrolytes say A X B y , molar conductivity is given by \(\lambda_{m\left(A_{x} B_{y}\right)}=x_{n} \mu_{A^{n+}} F+y_{m} \lambda_{A^{m}-F}\)
The following questions are multiple choice questions. Choose the most appropriate answer (i) At infinite dilution, the equivalent conductance of CaSO 4 is
(ii) If the degree of dissociation of CaSO 4 solution is 10% then equivalent conductance of CaSO 4 is
(iii) What is the unit of equivalent conductivity?
(iv) If the molar conductance value of Ca 2+ and Cl - at infinite dilution are 118.88 x 10 -4 m 2 mho mol -1 and 77.33 x 10 -4 m 2 mho mol -1 respectively then the molar conductance of CaCl 2 (in m 2 mho mol -1 ) will be
Read the passage given below and answer the following questions: Standard electrode potentials are used for various processes: (i) It is used to measure relative strengths of various oxidants and reductants. (ii) It is used to calculate standard cell potential. (iii) It is used to predict possible reactions. A set of half-reactions (in acidic medium) along with their standard reduction potential, E o (in volt) values are given below \(\mathrm{I}_{2}+2 e^{-} \rightarrow 2 \mathrm{I}^{-} ; \quad E^{\circ}=0.54 \mathrm{~V}\) \(\mathrm{Cl}_{2}+2 e^{-} \rightarrow 2 \mathrm{Cl}^{-} ; \quad E^{\circ}=1.36 \mathrm{~V}\) \(\mathrm{Mn}^{3+}+e^{-} \rightarrow \mathrm{Mn}^{2+} ; \quad E^{\circ}=1.50 \mathrm{~V}\) \(\mathrm{Fe}^{3+}+e^{-} \longrightarrow \mathrm{Fe}^{2+} ; \quad E^{\circ}=0.77 \mathrm{~V}\) \(\mathrm{O}_{2}+4 \mathrm{H}^{+}+4 e^{-} \longrightarrow 2 \mathrm{H}_{2} \mathrm{O} ; E^{\circ}=1.23 \mathrm{~V}\) The following questions are multiple choice questions. Choose the most appropriate answer: (i) Which of the following statements is correct?
(ii) Mn 3+ is not stable in acidic medium, while Fe 3+ is stable because
(iii) The strongest reducing agent in the aqueous solution is
(iv) The emf for the following reaction is \(\mathrm{I}_{2}+\mathrm{KCl} \rightleftharpoons 2 \mathrm{KI}+\mathrm{Cl}_{2}\)
Read the passage given below and answer the following questions : All chemical reactions involve interaction of atoms and molecules. A large number of atoms/molecules are present in a few gram of any chemical compound varying with their atomic/molecular masses. To handle such large number conveniently, the mole concept was introduced. All electrochemical cell reactions are also based on mole concept. For example, a 4.0 molar aqueous solution of NaCI is prepared and 500 mL of this solution is electrolysed. This leads to the evolution of chlorine gas at one of the electrode. The amount of products formed can be calculated by using mole concept. The following questions are multiple choice questions. Choose the most appropriate answer : (i) The total number of moles of chlorine gas evolved is
(ii) If cathode is a Hg electrode, then the maximum weight of amalgam formed from this solution is
(iii) In the electrolysis, the number of moles of electrons involved are
(iv) In electrolysis of aqueous NaCl solution when Pt electrode is taken, then which gas is liberated at cathode?
Read the passage given below and answer the following questions: The concentration of potassium ions inside a biological cell is at least twenty times higher than the outside. The resulting potential difference across the cell is important in several processes such as transmission of nerve impulses and maintaining the ion balance. A simple model for such a concentration cell involving a metal M is M (s) | M + (aq.; 0.05 molar) || M + (aq; 1 molar) |M (s) . The following questions are multiple choice questions. Choose the most appropriate answer: (i) For the above cell,
(ii) The value of equilibrium constant for a feasible cell reaction is
(iii) What is the emf ofthe cell when the cell reaction attains equilibrium?
(iv) The potential of an electrode change with change in
Read the passage given below and answer the following questions: The electrochemical cell shown below is concentration cell. M|M 2+ (saturated solution of a sparingly soluble salt, MX 2 ) || M 2+ (0.001 mol dm -3 ) | M The emf of the cell depends on the difference in concentrations of M 2+ ions at the two electrodes. The emf of the cell at 298 K is 0.059 V. The following questions are multiple choice questions. Choose the most appropriate answer: (i) The solubility product (K sp, mol 3 dm -9 ) of MX 2 at 298 K based on the information available for the given concentration cell is (take 2.303 x R x 298/P = 0.059)
(ii) The value of \(\Delta G\) (in kJ mol -1 ) for the given cell is (take 1F = 96500 C mol -1 )
(iii) The equilibrium constant for the following reaction is \(\mathrm{Fe}^{2+}+\mathrm{Ce}^{4+} \rightleftharpoons \mathrm{Ce}^{3+}+\mathrm{Fe}^{3+}\) (Given, \(E^{0} \mathrm{Ce}^{4+} / \mathrm{Ce}^{3+}=1.44\) and E o \(E_{\mathrm{Fe}^{3+} / \mathrm{Fe}^{2+}}=0.68 \mathrm{~V}\) )
(iv) To calculate the emf of the cell, which of the following options is correct?
Read the passage given below and answer the following questions : The potential of each electrode is known as electrode potential. Standard electrode potential is the potential when concentration of each species taking part in electrode reaction is unity and the reaction is taking place at 298 K. By convention, the standard ectrode potential of hydrogen (SHE) is 0.0 V. The electrode potential value for eacfi electrode process is a measure of relative tendency of the active species in the process to remain in the oxidisedlreduced form. The negative electrode potential means that the redox couple is stronger reducing agent than H + /H 2 couple. A positive electrode potential means that the redox couple is a weaker reducing agent than the H + /H 2 couple. Metals which have higher positive value of standard reduction potential form the oxides of greater thermal stability. In these questions (i-iv), a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices. (i) Assertion : An electrochemical cell can be set-up only if the redox reaction is spontaneous. Reason : A reaction is spontaneous if the free energy change is negative.
(ii) Assertion : The standard electrode potential of hydrogen is 0.0 V. Reason : It is by convention.
(iii) Assertion : The negative value of standard reduction potential means that reduction takes place on this electrode with reference to hydrogen electrode. Reason : The standard electrode potential of a half cell has a fixed value.
(iv) Assertion : The absolute value of electrode potential cannot be determined experimentally. Reason : The electrode potential values are generally determined with respect to SHE.
Read the passage given below and answer the following questions: Two types of conductors are generally used, metallic and electrolytic. Free electrons are the current carrier in metallic and in electrolytic conductors, free ions. Specific conductance or conductivity of an electrolytic solution is given by \(\kappa=C \times \frac{l}{A}\) where, C = l/R and l/A = G* (cell constant) Molar conductance ( \(\Lambda_{m}\) ) and equivalent conductance ( \(\Lambda_{e}\) ) of an electrolyte solution are calculated as \(\Lambda_{m}=\frac{\kappa \times 1000}{M} \text { or } \Lambda_{e}=\frac{\kappa \times 1000}{N}\) where, M = molarity of solution and Nis normality of solution. Molar conductance of strong electrolyte depends on the concentration. \(\Lambda_{m}=\Lambda_{m}^{0}-b \sqrt{C}\) \(\Lambda_{m}^{\circ}\) = molar conductance at infinite dilution, b = constant, C = conc of solution In these questions (i-iv), a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices. (i) Assertion : The molar conductivity of strong electrolyte decreases with increase in concentration. Reason : At high concentration, migration of ions is slow
(ii) Assertion : Equivalent conductance of all electrolytes increases with increasing concentration. Reason : More number of ions are available per gram equivalent at higher concentration.
(iii) Assertion : Specific conductance decreases with dilution whereas equivalent conductance increases. Reason : On dilution, number of ions per milli litre decreases but total number of ions increases considerably
(iv) Assertion : The ratio of specific conductivity to the observed conductance does not depend upon the concentration of the solution taken in the conductivity cell. Reason : Specific conductivity decreases with dilution whereas observed conductance increases with dilution.
Read the passage given below and answer the following questions: Electrical work done in unit time is equal to electrical potential multiplied by total charge passed. In order to obtain maximum work from a cell, the charge has to be passed reversibly. The reversible work done by a cell is equal to decrease in its Gibb's energy. Hence, Gibb's energy of reaction is given by \(\Delta G=-n F E_{\text {cell }}\) Hence, E is the emf of the cell and nF is the amount of energy. In these questions (i-iv), a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices (i) Assertion : \(\Delta G^{\circ}=-n F E^{\circ}\) Reason : E o should be positive for a spontaneous reaction
(ii) Assertion : An electrochemical cell can be set up only if the redox reaction is spontaneous. Reason : A reaction is spontaneous if free energy change is negative.
(iii) Assertion : Current stops flowing when E cell = 0. Reason : Equilibrium of the cell reaction is attained.
(iv) Assertion: E cell should have a positive value for the cell to function. Reason : E cell = E cathode - E anode
Read the passage given below and answer the following questions: Nernst equation relates the reduction potential of an electrochemical reaction to the standard potential and activities of the chemical species undergoing oxidation and reduction. Let us consider the reaction, \(M_{(a q)}^{n+} \longrightarrow n M_{(s)}\) For this reaction, the electrode potential measured with respect to standard hydrogen electrode can be given as \(E_{\left(M^{n+} / M\right)}=E_{\left(M^{n+} / M\right)}^{\circ}-\frac{R T}{n F} \ln \frac{[M]}{\left[M^{n+}\right]}\) In these questions ( i-iv), a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices.
(i) Assertion : For concentration cell, \(\begin{array}{c} \mathrm{Zn}_{(s)}\left|\mathrm{Zn}^{2+}{ }_{(a q)} \| \mathrm{Zn}^{2+}{ }_{(a q)}\right| \mathrm{Zn} \\ \mathrm{C}_{1} \quad \mathrm{C}_{2} \end{array}\) For spontaneous cell reaction, C 1 < C 2 . Reason : For concentration cell \(E_{\text {cell }}=\frac{R T}{n F} \log \frac{C_{2}}{C_{1}}\) For spontaneous reaction, \(E_{\text {cell }}=+\mathrm{ve} \Rightarrow C_{2}>C_{1}\) (ii) Assertion : For the cell reaction, \(\mathrm{Zn}_{(s)}+\mathrm{Cu}_{(a q)}^{2+} \longrightarrow \mathrm{Zn}_{(a q)}^{2+}+\mathrm{Cu}_{(s)}\) voltmeter gives zero reading at equilibrium. Reason : At the equilibrium, there is no change in concentration of Cu 2+ and Zn 2+ ions. (iii) Assertion : The Nernst equation gives the concentration dependence of emf of the cell. Reason : In a cell, current flows from cathode to anode (iv) Assertion : Increase in the concentration of copper half cell in a cell, increases the emf of the cell Reason : \(E_{\text {cell }}=E_{\text {cell }}^{\circ}+\frac{0.059}{2} \log \frac{\left[\mathrm{Cu}^{2+}\right]}{\left[\mathrm{Zn}^{2+}\right]}\)
Metallic conductance involves movement of electrons where as electrolytic conductance involves movement of ions. Specific conductance increases with increase in concentration where as A m (molar conductivity) decreases with increase in concentration. Electrochemical cell converts chemical energy of redox reaction into electricity. Mercury cell, Dry cells are primary cells where as Ni-Cd cell, lead storage battery are secondary cells. Electroehemical series is arrangement of elements in increasing order of their reduction potential. Electrolytic cell converts electrical energy into chemical energy which is used in electrolysis. Amount of products formed are decided with the help of Faraday's laws of Electrolysis. Kohlrausch law helps to determine limiting molar conductivity of weak electrolyte, their degree of ionisation ( \(\alpha\) ) and their dissociation constants. Corrosion is electrochemical phenomenon. Metal undergoing corrosion acts as anode, loses electrons to form ions which combine with substances present in atmosphere to form surface compounds. More reactive metals are coated over less reactive metals to prevent corrosions. H 2 -O 2 fuel cell was used in apollo space programme. (a) Out of 0.5 M, 0.01 M, 0.1 M and 1.0 M which solution of KCl will have highest value of specific conductance? Why? (b) Write the product of electrolysis of aq. NaCI on cathode. Why? (c) When does electrochemical cell behaves like electrolytic cell? (d) For an electrochemical cell Mg(s) + 2Ag + (aq) \(\rightarrow\) 2Ag(s) + Mg 2+ . Give the cell representation and write Nernst equation. (e) Which will have higher conductance, silver wire at 30° or at 60°C? (f) Calculate maximum work obtained from the cell Ni(s) + 2Ag + (aq) \(\rightarrow\) Ni 2+ (aq) + 2Ag(s) E o cell = 1.05V. (g) Which cell is used in hearing aids and watches?
Electrochemistry plays a very important part in our daily life. Primary cells like dry cell is used in torches, wall clock, mercury cell is used in hearing aids, watches. Secondary cells Ni-Cd cell is used in cordless phones, lithium battery is used in mobiles, lead storage battery is used in vehicle and inverter. Fuel cells like H 2 -O 2 cell was used in apollo space programme. A 38% solution of sulphuric and is used in lead storage battery. Its density is 1.30 g mL -1 . The battery holds 3.5 L of the acid. During the discharge of the battery, the density of H 2 SO 4 falls to 1.14 g mL -1 (20% solution by mass) (Molar mass of H 2 SO 4 is 98 g mol -1 ). (a) Write the chemical reaction taking place at anode when lead storage battery is in use. (b) How much electricity in Faraday is required to carry out the reduction of one mole of PbO 2 ? (c) What is molarity of sulphuric acid before discharge? (d) What is mass of sulphuric acid in solution after discharge? (e) Write the products of electrolysis when dilute sulphuric acid is electrolysed using platinum electrodes.
Observe the following table in which conductivity and molar conductivity of NaCI at 298 K at different concentration for different electrolytes is given. Answer the questions based in the table that follows: Conductivities and molar conductivities of NaCI at 298 K at different concentrations.
(a) What happens to conductivity on dilution and why? (b) Why is \(\Lambda_{\mathrm{m}}^{\mathrm{o}}\) (limiting molar conductivity) for HCI more than NaCl? (c) Calculate degree of dissociation ( \(\alpha\) ) of NaCI of 0.001 M concentration using the table. (d) Calculate \(\Lambda_{\mathrm{m}}^{\mathrm{o}}\) of CH 3 COOH using the table. (e) Calculate Ka of 0.01 M CH 3 COOH solution if \(\Lambda_{\mathrm{m}}^{\mathrm{o}}\) for CH 3 COOH is 390.07S cm 2 mol -1 , \(\Lambda_{\mathrm{m}}\) = 39.07S cm -1 .
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MTG ScoreMore Case Study Based Sample Questions Chemistry Class 12 is specially designed to help students get familiar with solving these new patterns of questions. The book covers 800 + sample questions for practice with detailed explanations to each question. Practising these questions will definitely help students to get an edge in their CBSE preparations.
For the academic year 2020-21 CBSE has incorporated more Objective type/MCQ based questions which will focus on measuring critical thinking ability of students.
The new pattern of questions includes Case study based questions, Passage based questions, Assertion and Reason type questions. In Case study based/ Passage based questions, students will be expected to answer questions after reading a given paragraph or a passage. Assertion and Reason type question is just another way of checking the clarity of one’s concept.
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15 questions mcq test - case based questions test: electrochemistry, read the passage given below and answer the following questions: the cell constant is usually determined by measuring the resistance of the cell containing a solution whose conductivity is already known. for this purpose, we generally use kcl solutions whose conductivity is known accurately at various concentrations and at different temperatures. consider the resistance of a conductivity cell filled with 0.1 m kcl solution is 200 ohm. if the resistance of the same cell when filled with 0.02 m kcl solution is 420 ohm. (conductivity of 0.1 m kcl solution is 1.29 s m –1 .) the following questions are multiple choice questions. choose the most appropriate answer: q. what is the conductivity of 0.02 m kcl solution.
= 0.614Sm -1
Read the passage given below and answer the following questions:
The cell constant is usually determined by measuring the resistance of the cell containing a solution whose conductivity is already known. For this purpose, we generally use KCl solutions whose conductivity is known accurately at various concentrations and at different temperatures. Consider the resistance of a conductivity cell filled with 0.1 M KCl solution is 200 Ohm. If the resistance of the same cell when filled with 0.02 M KCl solution is 420 Ohm. (Conductivity of 0.1 M KCl solution is 1.29 S m –1 .)
The following questions are Multiple Choice Questions. Choose the most appropriate answer:
Q. SI unit for conductivity of a solution is
A galvanic cell consists of a metallic zinc plate immersed in 0.1 M Zn(NO 3 ) 2 solution and metallic plate of lead in 0.02 M Pb(NO 3 ) 2 solution.
The following questions are multiple choice questions.
Choose the most appropriate answer:
Q. How will the cell be represented ?
According to Nernst equation
Q. What product is obtained at cathode?
Cathode reaction: Pb 2+ (aq) + 2e – → Pb(s)
Q. Which of the following statements is not correct about an inert electrode in a cell ?
Products of electrolysis depend on the nature of material being electrolysed and the type of electrodes being used. If the electrode is inert (e.g., platinum or gold), it does not participate in the chemical reaction and acts only as source or sink for electrons. On the other hand, if the electrode is reactive, it participates in the electrode reaction. Thus, the products of electrolysis may be different for reactive and inert electrodes. Aqueous copper sulphate solution and aqueous silver nitrate solution are electrolysed by 1 ampere current for 10 minutes in separate electrolytic cells.
In these questions, a statement of assertion followed by a statement of reason. Choose the correct answer out of the following choices.
Assertion (A): The mass of copper and silver, deposited on the cathode be same.
Reason (R): Copper and silver have different equivalent masses.
It will be different for silver since the equivalent weight of silver is different.
Assertion (A): At equilibrium condition E cell = 0 or Δ r G = 0.
Reason (R): E cell is zero when both electrodes of the cell are of the same metal.
Products of electrolysis depend on the nature of material being electrolysed and the type of electrodes being used. If the electrode is inert (e.g., platinum or gold), it does not participate in the chemical reaction and acts only as source or sink for electrons. On the other hand, if the electrode is reactive, it participates in the electrode reaction. Thus, the products of electrolysis may be different for reactive and inert electrodes. Aqueous copper sulphate solution and aqueous silver nitrate solution are electrolysed by 1 ampere current for 10 minutes in separate electrolytic cells. In these questions, a statement of assertion followed by a statement of reason. Choose the correct answer out of the following choices.
Assertion (A): In a galvanic cell, chemical energy is converted into electrical energy.
Reason (R): Redox reactions provide the chemical energy to the cell.
Assertion (A): The negative sign in the expression E Zn 2+/ Zn = – 0.76V means Zn 2+ cannot be oxidised to Zn.
Reason (R): Zn is more reactive than hydrogen & Zn will oxidised, & H + will get reduced.
All chemical reactions involve interaction of atoms and molecules. A large number of atoms/molecules are present in a few gram of any chemical compound varying with their atomic/molecular masses. To handle such large number conveniently, the mole concept was introduced. All electrochemical cell reactions are also based on mole concept. For example, a 4.0 molar aqueous solution of NaCl is prepared and 500 mL of this solution is electrolysed. This leads to the evolution of chlorine gas at one of the electrode. The amount of products formed can be calculated by using mole concept.
The following questions are multiple choice questions. Choose the most appropriate answer:
Q. The total number of moles of chlorine gas evolved is
Q. If cathode is a Hg electrode, then the maximum weight of amalgam formed from this solution is
2 moles of amalgam = 23 x 2 + 2 x 200
All chemical reactions involve interaction of atoms and molecules. A large number of atoms/molecules are present in a few grams of any chemical compound varying with their atomic/molecular masses. To handle such large numbers conveniently, the mole concept was introduced. All electrochemical cell reactions are also based on mole concept. For example, a 4.0 molar aqueous solution of NaCl is prepared and 500 mL of this solution is electrolysed. This leads to the evolution of chlorine gas at one of the electrode. The amount of products formed can be calculated by using mole concept.
Q. In electrolysis of NaCl when Pt electrode is taken then H 2 is liberated at cathode while with Hg cathode it forms sodium amalgam :-
Conc of H+ ions is larger when the Pt electrode is taken. Hence, H+ ions are discharged in preference to Na+ ions. When Hg cathode is used Na+ ions are discharged.
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Fuels cells generate electricity from an electrochemical reaction in which oxygen and a fuel combine to form water. Fuel cells work by converting the chemical energy found in the fuel, e.g. hydrogen gas, into electrical energy (electricity).
In a fuel cell, the fuel is oxidized at the anode which yields electrons that flow through an external circuit doing electrical work, before an oxidant (often oxygen) is reduced by these electrons at the cathode.
\[O_{2(g)} + \underset{\text{Fuel}}{H_{2(g)}} \rightarrow 2H_2O_{(l)} \nonumber \]
The resulting electricity can be used in a variety of ways, including: powering motor vehicles, electrical devices, and airplanes. Fuel cells also produce heat as a by-product which is finding increasing use in heating homes, especially in Japan. With its multifunctional products and by-products, fuel cells are rapidly becoming the hot ticket alternative source of energy as we move into a greener and more progressive era.
A hydrogen fuel cell enables hydrogen to be combined electrochemically with oxygen to produce electricity, water, and heat. One fuel cell alone only produces a small amount of power. However, grouping the individual fuel cells together creates a fuel cell stack (as shown below in the diagram). When delivered to a fuel cell engine, fuel cell stacks create enough energy to power buses and other vehicles, and have even been used to power spacecraft.
Each fuel cell in the stack contains two electrodes - a positive cathode (where the reduction occurs) and a negative anode (where the oxidation occurs). The energy-producing reactions take place at the surfaces of the electrodes. Each individual pair of electrodes is separated by an electrolyte (either in solid or liquid form). This electrolyte carries electrically charged particles (ions) between the electrodes. The rate of a given reaction can be increased with the help of a catalyst such as platinum or nickel.
The power (\(P\)) produced by a fuel cell is equal to the voltage (\(V\)) multiplied by the current (\(I\)) at which it is being operated. This is measured in watts (W).
\[P= IV \nonumber \]
There are a number of factors that reduce the efficiency in fuel cells, which can be broadly categorized as reversible, irreversible and fuel utilization losses.
'Reversible' losses correspond to losses that underpin the deviation between the standard electrode potential of the full electrochemical cell and the actual operating open-circuit voltage (OCV).
'Irreversible' losses describe the various contributions from different components of the fuel cell to the loss of voltage with respect to OCV, as the current drawn from the cell/stack is increased. This includes an activation barrier that must be overcome at low currents, which can represent a loss of ~200 mV. This results from the reactions requiring energy to overcome a threshold before occurring, despite a thermodynamic driving force. This is especially relevant in the case of the reduction of oxygen at the cathode. Further losses are experienced in the intermediate regime as a result of ohmic resistance (both ionic and electronic) and due to mass transport limitations at high current loads.
Particularly in the case of PEMFCs, the flows of waste water and unspent fuel occur at rates that exceed the capabilities of the fuel cell's physical capabilities and not all fuel that enters at the inlet is utilized. This also results in a drop of overall efficiency.
Since the efficiency of a fuel cell is directly proportional to the power generated, its efficiency is almost proportional to its voltage.
Fuel cells create little to no environmentally damaging emissions: generally, the only byproduct in a hydrogen fuel cell, typically found in automobiles, is water.
Fuel cells are being used all over the globe. Here are some examples:
1. Answer: A) Solid Oxide Fuel Cell (SOFC)
Explanation: As explained by the table in the 'Different Types of Fuel Cells' section, the Solid Oxide Fuel Cell (SOFC) is the most efficient with an efficiency of 50-65%.
2. Answer: Water OR Heat
Explanation: Both water and heat are by-products of an active hydrogen fuel cell.
3. Answer: United Technologies Corporation
Explanation: United Technologies Corporation was the first company to commercialize fuel cells.
4. Answer: It serves as a bridge between anode and cathode.
Explanation: An electrolyte serves a bridge that connects the anode and cathode parts of a fuel cell. This is because of the ionic nature of salts in solution. As a voltage is applied, these ions align either at the cathode or at the anode according to their charge. This creates a bridge that the voltage can cross.
5. Answer: No (very little) carbon-dioxide emissions OR Very high efficiency
Explanation: The very efficient nature of fuel cells relative to standard combustion engines and other similar devices is highly valued in today's society because of the rising cost of energy. The relatively low emissions produced by fuel cells is also beneficial to the environment.
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Jennifer Howard-Grenville and Ujjwal Pandey
Roula Khalaf, Editor of the FT, selects her favourite stories in this weekly newsletter.
Hydrogen is often hyped as the “Swiss army knife” of the energy transition because of its potential versatility in decarbonising fossil fuel-intensive energy production and industries. Making use of that versatility, however, will require hydrogen producers and distributors to cut costs, manage technology risks, and obtain support from policymakers.
To cut carbon dioxide emissions, hydrogen production must shift from its current reliance on fossil fuels. The most common method yields “grey hydrogen”, made from natural gas but without emissions capture. “Blue hydrogen,” which is also made from natural gas but with the associated carbon emissions captured and stored, is favourable.
But “green hydrogen” uses renewable energy sources, including wind and solar, to split water into hydrogen and oxygen via electrolysis. And, because there are no carbon emissions during production or combustion, green hydrogen can help to decarbonise energy generation as well as industry sectors — such as steel, chemicals and transport — that rely heavily on fossil fuels.
Ultimately, though, the promise of green hydrogen will hinge on how businesses and policymakers weigh several questions, trade-offs, and potential long-term consequences. We know from previous innovations that progress can be far from straightforward.
Wind power, for example, is a mature renewable energy technology and a key enabler in green hydrogen production, but it suffers vulnerabilities on several fronts. Even Denmark’s Ørsted — the world’s largest developer of offshore wind power and a beacon for renewable energy — recently said it was struggling to deliver new offshore wind projects profitably in the UK.
Generally, the challenge arises from interdependencies between macroeconomic conditions — such as energy costs and interest rates — and business decision-making around investments. In the case of Ørsted, it said the escalating costs of turbines, labour, and financing have exceeded the inflation-linked fixed price for electricity set by regulators.
Business leaders will also need to steer through uncertainties — such as market demand, technological risks, regulatory ambiguity, and investment risks — as they seek to incorporate green hydrogen.
This is the third in a series of monthly business school-style teaching case studies devoted to responsible-business dilemmas faced by organisations. Read the piece and FT articles suggested at the end before considering the questions raised.
About the authors: Jennifer Howard-Grenville is Diageo professor of organisation studies at Cambridge Judge Business School; Ujjwal Pandey is an MBA candidate at Cambridge Judge and a former consultant at McKinsey.
The series forms part of a wide-ranging collection of FT ‘instant teaching case studies ’ that explore business challenges.
Two factors could help business leaders gain more clarity.
The first factor will be where, and how quickly, costs fall and enable the necessary increase to large-scale production. For instance, the cost of the electrolysers needed to split water into hydrogen and oxygen remains high because levels of production are too low. These costs and slow progress in expanding the availability and affordability of renewable energy sources have made green hydrogen much more expensive than grey hydrogen, so far — currently, two to three times the cost.
The FT’s Lex column calculated last year that a net zero energy system would create global demand for hydrogen of 500mn tonnes, annually, by 2050 — which would require an investment of $20tn. However, only $29bn had been committed by potential investors, Lex noted, despite some 1,000 new projects being announced globally and estimated to require total investment of $320bn.
Solar power faced similar challenges a decade ago. Thanks to low-cost manufacturing in China and supportive government policies, the sector has grown and is, within a very few years , expected to surpass gas-fired power plant installed capacity, globally. Green hydrogen requires a similar concerted effort. With the right policies and technological improvements, the cost of green hydrogen could fall below the cost of grey hydrogen in the next decade, enabling widespread adoption of the former.
Countries around the world are introducing new and varied incentives to address this gap between the expected demand and supply of green hydrogen. In Canada, for instance, Belgium’s Tree Energy Solutions plans to build a $4bn plant in Quebec, to produce synthetic natural gas from green hydrogen and captured carbon, attracted partly by a C$17.7bn ($12.8bn) tax credit and the availability of hydropower.
Such moves sound like good news for champions of green hydrogen, but companies still need to manage the short-term risks from potential policy and energy price swings. The US Inflation Reduction Act, which offers tax credits of up to $3 per kilogramme for producing low-carbon hydrogen, has already brought in limits , and may not survive a change of government.
Against such a backdrop, how should companies such as Hystar — a Norwegian maker of electrolysers already looking to expand capacity from 50 megawatts to 4 gigawatts a year in Europe — decide where and when to open a North American production facility?
The second factor that will shape hydrogen’s future is how and where it is adopted across different industries. Will it be central to the energy sector, where it can be used to produce synthetic fuels, or to help store the energy generated by intermittent renewables, such as wind and solar? Or will it find its best use in hard-to-abate sectors — so-called because cutting their fossil fuel use, and their CO₂ emissions, is difficult — such as aviation and steelmaking?
Steel producers are already seeking to pivot to hydrogen, both as an energy source and to replace the use of coal in reducing iron ore. In a bold development in Sweden, H2 Green Steel says it plans to decarbonise by incorporating hydrogen in both these ways, targeting 2.5mn tonnes of green steel production annually .
Meanwhile, the global aviation industry is exploring the use of hydrogen to replace petroleum-based aviation fuels and in fuel cell technologies that transform hydrogen into electricity. In January 2023, for instance, Anglo-US start-up ZeroAvia conducted a successful test flight of a hydrogen fuel cell-powered aircraft.
The path to widespread adoption, and the transformation required for hydrogen’s range of potential applications, will rely heavily on who invests, where and how. Backers have to be willing to pay a higher initial price to secure and build a green hydrogen supply in the early phases of their investment.
It will also depend on how other technologies evolve. No industry is looking only to green hydrogen to achieve their decarbonisation aims. Other, more mature technologies — such as battery storage for renewable energy — may instead dominate, leaving green hydrogen to fulfil niche applications that can bear high costs.
As with any transition, there will be unintended consequences. Natural resources (sun, wind, hydropower) and other assets (storage, distribution, shipping) that support the green hydrogen economy are unevenly distributed around the globe. There will be new exporters — countries with abundant renewables in the form of sun, wind or hydropower, such as Australia or some African countries — and new importers, such as Germany, with existing industry that relies on hydrogen but has relatively low levels of renewable energy sourced domestically.
How will the associated social and environmental costs be borne, and how will the economic and development benefits be shared? Tackling climate change through decarbonisation is urgent and essential, but there are also trade-offs and long-term consequences to the choices made today.
Lex in depth: the staggering cost of a green hydrogen economy
How Germany’s steelmakers plan to go green
Hydrogen-electric aircraft start-up secures UK Infrastructure Bank backing
Aviation start-ups test potential of green hydrogen
Consider these questions:
Are the trajectories for cost/scale-up of other renewable energy technologies (eg solar, wind) applicable to green hydrogen? Are there features of the current economic, policy, and business landscape that point to certain directions for green hydrogen’s development and application?
Take the perspective of someone from a key industry that is part of, or will be affected by, the development of green hydrogen. How should you think about the technology and business opportunities and risks in the near term, and longer term? How might you retain flexibility while still participating in these key shifts?
Solving one problem often creates or obscures new ones. For example, many technologies that decarbonise (such as electric vehicles) have other impacts (such as heavy reliance on certain minerals and materials). How should those participating in the emerging green hydrogen economy anticipate, and address, potential environmental and social impacts? Can we learn from energy transitions of the past?
Where climate change meets business, markets and politics. Explore the FT’s coverage here .
Are you curious about the FT’s environmental sustainability commitments? Find out more about our science-based targets here
Explore the series.
International Edition
Abstract: Long-term decarbonization within the power sector and the materials manufacturing sector stands as the most urgent challenge of our era. Without decisive action, carbon emissions associated with these sectors are set to more than double by 2050. The rapid expansion of affordable renewable electricity presents unprecedented opportunities to revolutionize conventional engineering processes through electrochemistry, thus providing solutions to our society’s grand challenges. Hence, innovations in these sectors capable of reducing or eliminating CO2 generation will be pivotal in changing our current climate trajectory. In this talk, I will discuss two of my previous experiences exploring and applying foundational principles in electrochemistry, mechanical engineering and materials science to advance applications in energy storage and materials sustainability. First, I will present different approaches to electrolyte design for stabilizing metal electrodeposition processes at the interfaces in electrochemical cells, with practical applications in metal anode batteries. Then, I will introduce my work on a closed-loop materials recovery platform utilizing electrochemically mediated techniques, which can separate waste into valuable product streams without additional waste generation, relying solely on low-cost electricity, water and table salt. In the future, my research will delve deeper into fundamental mechanisms and pioneer technologies aimed at accelerating the transition to a low-carbon and climate-resilient future.
Bio: Duhan Zhang is dedicated to addressing pressing challenges at the intersection of energy, climate and sustainability. Currently, Duhan is a postdoctoral associate, working with Yet-Ming Chiang at the Massachusetts Institute of Technology in the Department of Materials Science and Engineering, distinguished by an MIT Energy Initiative Fellowship. She earned a Ph.D. in mechanical engineering from Cornell University, working with Lynden Archer, supported by the Telluride Association Fellowship. Her doctoral research focused on optimizing the stability of metal electrodeposition in energy storage systems by manipulating electrolyte properties. Her present work delves into energy materials, electrochemical energy storage and conversion systems, and electrification of materials recovery and manufacturing processes. Throughout her academic journey, Duhan has received multiple recognitions for her research and contributions, including the Mars Fellowship from the Lindau Nobel Laureate Meetings and the best paper award from the Joint Center for Energy Storage Research, among others. With a commitment to innovation and sustainability, she continues to push the boundaries of scientific inquiry for a brighter, greener future.
Upcoming events.
There’s no formula for the difficult moments managers face, but there are questions you should consider.
Imagine you’re a new manager, and one of your team members consistently underperforms. But there’s a catch: your struggling employee is a personal friend of your CEO. When performance review time rolls around, should you be honest and give them a low rating?
There are no simple answers for the tough decisions that managers face. Harvard Business School professor Joe Badaracco says that hard and fast rules only go so far in these sorts of situations. Instead, managers must use their best judgement to find a solution.
Badaracco is a business ethics expert and the author of the book, Managing in the Gray: Five Timeless Questions for Resolving Your Toughest Problems at Work .
In this episode, he explains how to approach what he calls “gray-area decisions.” First, gather as much information as you can, taking different perspectives into account. Then, consider the consequences of the different possible actions you can take, the values of your organization, and your own personal values.
Key episode topics include: leadership, managing conflicts, dismissing employees, managing people, managing employees, tough calls,
HBR On Leadership curates the best case studies and conversations with the world’s top business and management experts, to help you unlock the best in those around you. New episodes every week.
HANNAH BATES: Welcome to HBR on Leadership, case studies and conversations with the world’s top business and management experts – hand-selected to help you unlock the best in those around you.
Imagine you’re a new manager and one of your team members consistently underperforms, but there’s a catch. Your struggling employee is a personal friend of your boss. When performance review time rolls around, should you be honest and give them a low rating or should you avoid conflict and give them the same rating they’ve been receiving for years? There are no simple answers to the tough decisions that managers face. Harvard Business School Professor Joe Badaracco says that in these sorts of situations, hard and fast rules only go so far. Instead, managers must do the more difficult thing. Use their best judgment to find a solution. In this episode, Badaracco explains how managers can approach what he calls gray area decisions. First, gather as much information as you can and take different perspectives into account. Then consider the consequences of different possible actions, the values of your organization and your own personal values. If you’re a new manager facing a tough dilemma, this episode is for you. It originally aired on Cold Call in November 2016. Here it is.
BRIAN KENNY: You’re fired. These are two words no one ever wants to hear, and with the exception of reality TV, it’s not usually how the message is delivered nowadays. Today, in an effort to be fair, most organizations have a process that involves personal improvement plans, mentoring and monitoring, even counseling, before taking such a drastic step of severing employment. Yet still the decision to fire an employee is rarely clear cut. And for the person being transitioned, quotations, the rationality used by their manager for that decision is most assuredly questionable. So, what exactly does or should go on in the mind of a manager deciding the fate of an employee? Today we’ll hear from Professor JOE BADARACCO about his case entitled “Two Tough Calls.” I’m your host, Brian Kenny, and you’re listening to Cold Call .
SPEAKER 3: So, we’re all sitting there in the classroom.
SPEAKER 4: Professor walks in.
SPEAKER 5: And they look up and you know what’s coming. Oh, the dreaded Cold Call .
BRIAN KENNY: Joe Badaracco is the John Shad Professor of Business Ethics at Harvard Business School. His research focuses on what counts as sound reflection for busy men and women who have serious responsibilities and face hard practical problems. He’s the author of many cases, articles and books on the topic, including the recently published Managing in the Gray. Joe, thanks for joining me.
JOE BADARACCO: Glad to be here, Brian.
BRIAN KENNY: So, I really enjoyed reading this case and reading parts of the book, and I think many people, anybody who’s managed a team, can relate to the challenge that you’re going to talk about in this case. But maybe you could start just by setting the case up for us. Who’s the protagonist and what’s going on?
JOE BADARACCO: Sure. The case is an unusual case, it’s written in the first person, so you’ve got to give the protagonist a name. So, let’s call her Susan. But you’re really hearing Susan’s voice and you’re hearing Susan tell her story. So, she was a computer science graduate, this is her first job, full-time job. She’d had a couple internships at Microsoft. She was a very talented programmer.
She also had a lot of management potential, so she was spotted early as somebody who could move up pretty quickly at this online retailer. She got two promotions pretty fast. She found herself managing a team of 14 people. Some of them were about her age. They were techies like her. Some of them were older than her, and some of them were not performing anywhere near the standard she expected. And it came time for her to give reviews, and she wanted to give reviews to several people that would’ve basically triggered lots of problems. I’ll talk in particular about a guy named Terry. So he had been brought into the company because he was a scuba diving pal of some of the executives.
BRIAN KENNY: Oh, we’ve all encountered a Terry.
JOE BADARACCO: And from Susan’s point of view, he was basically contributing nothing to the team. She’d worked with him, she’d tried to find some things for him to do, but her view was his contribution was basically zero. Now, under the performance evaluation system, it was one to five, and he’d been getting 3.5 for a number of years, and that was fine.
BRIAN KENNY: Pretty good.
JOE BADARACCO: But she thought he deserved a 2.5. In this company, 2.5 meant that you were basically on a greased shoot out the company. It was accompanied what’s called a PIP, a performance improvement plan, which a lot of companies have. But this was really a tripwire. And once you were on a PIP, as soon as you came in late or something like that, you got a box and you were out. So she wanted to give him what he deserved, the 2.5. She floated this idea among the people she worked for, and they said, you’re kind of young in the job, you’ve been doing well so far. Why make some waves? Are you sure you’ve got enough experience to judge him? Doesn’t he deserve another chance, given that he’s had threes and three point fives?
BRIAN KENNY: And he’s a good scuba diver.
JOE BADARACCO: Apparently an excellent scuba diver. Yeah.
BRIAN KENNY: Let me stop you there.
JOE BADARACCO: Sure.
BRIAN KENNY: Because I want to want to pull the reins back in a little bit, and I guess one of the things that I’m curious about is why you decided to write this case, why you chose to write it in the way you did?
JOE BADARACCO: Well, after the incidents described in the case, the young woman came here to HBS to get an MBA. So I had her as a student. And I don’t recall how we got to talking about this case possibility, but it seemed really promising, because as you pointed out, many of our MBA students have already been in positions where they’ve had to let somebody go. Many of them in the last few years have had family members that have been fired or laid off, and some of them will actually admit in class that they personally have been laid off. So it’s a very real subject. And this was somebody who’s a contemporary of our MBA students facing one of these tough calls.
BRIAN KENNY: Tell me a little bit more about Susie. Is that what we’re calling her?
JOE BADARACCO: Yeah, Susie, Susan. Sure.
BRIAN KENNY: So, is she a millennial? Does that factor into this?
JOE BADARACCO: Well, I think she was kind of a millennial, but I think she was basically herself and she prided herself on being very direct to the point of being blunt. She thought that in organizations, people were rarely treated honestly, that there were lots of games played that people told you you were doing well when you weren’t doing so well and so forth. She said she was going to be blunt, she wanted people to be blunt with her.
She was also, as I mentioned, younger than some of the people she was managing, and some of the people she was considering letting go. And as you sort of read her first-person narrative in the case, some students sort of like her, they see her as a practitioner of what’s called sort of extreme transparency. And others say, this is kind of a arrogant, aggressive individual who’s a little bit too full of herself. And then what’s interesting in class is some students, often women will say, you wouldn’t say the same thing about a male protagonist in this situation. So that’s another issue that comes up in the case.
BRIAN KENNY: Yeah, you talk about her technical proficiency, which has given her some affinity with the technical team, which is pretty important. It allows her maybe to get things done a little faster because she kind of understands what she’s asking people to do. So, she’s a AA, hard-working type person, and she makes her hiring decisions pretty specifically based on her own personality type.
JOE BADARACCO: Exactly. She wants people who she said, come out of college hungry. They love to have goals, they’re willing to work 80 hours a week, and she is too. And she says to them, “Look, all you need to do to be successful here is to tell me what I need to do to help you be successful and complete the mission that our team has.” So, it’s a complicated picture. In many ways, there are things that are admirable about her, but there’s other things that kind of put people off.
BRIAN KENNY: So, what are some of the things as a manager that Susan needs to think about? I mean, it doesn’t seem like she’s in a place where she can just sever that relationship and have Terry move along. There’s a process that she has to go through both intellectually as well as managerially.
JOE BADARACCO: Yeah. Well, let me mention, first of all, what’s the central idea in my book that’s just come out. And it can be summarized essentially in a single sentence, and it says, “When you face one of these difficult decisions, a gray area decision, first of all, you want to work through it as a manager.” That means you get the best information. You can look at things in a couple different ways. If there’s expert judgment, in this case HR that can be brought to bear, talk to the senior people, which she did. You get the best information and judgments you can. That’s what it means to work through it as a manager.
But then in the end, it’s a judgment call and you’ve got to approach it as a human being. You’re going to make that call, you’re going to live with the consequences. And so it’s in that context that some of the questions in the book are really quite relevant, and these questions, by the way, aren’t mine. They’re not Harvard Business School’s. Basically, they come from a multi-year effort to try to look at how great thinkers over the millennia have advised us to look at really hard problems. So you look hard at the consequences, full consequences as objectively as you can. You think about what you believe your core human duties are. So what does she owe Terry? What does she owe the people on her team? You think about the values of your organization. You think clearly about what you can live with. Because you will live with it, and you’re also going to be held accountable in your organization.
A lot of people think if you’ve got one of these difficult decisions, you just trust your judgment, you trust your gut. You look at your moral compass. And what I really emphasize in the book is, the first thing you’ve got to do is the best analysis you can as a manager, okay? If you can use big data analytics, whatever it is, wring everything you can out of what you can learn. Then you make a judgment as a human being. But again, that’s not gut feel. That’s after you think through consequences, your duties, what’ll work. It’s only at the very end that you finally trust your judgment after it’s been tempered and shaped and guided by the preliminary steps.
BRIAN KENNY: You mentioned before the obligation that Susan as a manager has to Terry. Does Terry have an obligation back to Susan to do the job well? Does that make the whole decision much-
JOE BADARACCO: He certainly had an obligation to the company and the team to pull his oar, and he wasn’t doing it.
BRIAN KENNY: And part of my question was sort of what’s at the core of it too, is that I mentioned in the introduction how most organizations have sort of an extreme set of processes that one needs to go through. Have companies gone too far in trying to make sure that they’re giving every opportunity for the employee to perform?
JOE BADARACCO: I think that’s a tough one. I don’t have any basis for generalizing on that. At the end of the day, even when there are elaborate systems and lots of steps and checklists, a lot comes down to the judgment of managers. When do you start putting notes in a file about someone’s performance? Certainly you need to inform them if they’re on thin ice or if they’re about to go on probation. What do you tell them? How candidly do you inform them? How helpful are you? A lot of these things come down to one-on-one judgment calls, sort of the character and experience of the person who’s making the decision.
BRIAN KENNY: In the book, you talk about this concept of moral imagination. So can you describe what that is and how it factors into these kinds of decisions?
JOE BADARACCO: Well, it has a lot to do with how you actually deliver the bad news and how you follow up after that. You’ve really got to put yourself as best you can in their shoes, as if you were the person being fired, or let’s say it was one of your kids or your parent, sibling, how would you want to be treated? That’s a way of bringing to the foreground a lot of these basic human considerations that can be lost if you’re simply angry at the person for not performing, or you’re just going through the company’s checklist on how to process people out.
BRIAN KENNY: You’ve discussed this case in class before?
JOE BADARACCO: Many times.
BRIAN KENNY: So, I don’t want you to give away too much, but what kind of reactions do you get?
JOE BADARACCO: Well, first, students really do engage in this. I’m talking here about MBA students. They either have been or expect soon to be in situations like this. Secondly, they have, as I mentioned earlier, a variety of responses to Susan, so that pulls them further into the case. Some of them make very sound comments, and I think one worth thinking about is this, it says, look, you’re managing a team, you’ve got a company, whatever. Should you really expect that everybody on that team is going to be an A player, or after coaching from you is going to be an A player? The point they make is that good managers learn to work with… They want As, they have some Bs, they live with some Cs. And that’s what managing in the real world is like. So there’s a really good set of discussions about not just what she should do, but whether she should do anything.
BRIAN KENNY: Joe, thank you so much for joining me.
JOE BADARACCO: You’re welcome, Brian.
HANNAH BATES: That was Harvard Business School professor Joe Badaracco in conversation with Brian Kenny on Cold Call . He’s also the author of the book, Managing in the Gray: Five Timeless Questions for Resolving Your Problems At Work .
We’ll be back next Wednesday with another hand-picked conversation about leadership from Harvard Business Review. If you found this episode helpful, share it with your friends and colleagues, and follow our show on Apple Podcasts, Spotify, or wherever you get your podcasts. While you’re there, be sure to leave us a review. When you’re ready for more podcasts, articles, case studies, books and videos with the world’s top business and management experts, find it all at HBR.org.
This episode was produced by Anne Saini, and me, Hannah Bates. Ian Fox is our editor. Music by Coma Media. Special thanks to Maureen Hoch, Erica Truxler, Ramsey Khabbaz, Nicole Smith, Anne Bartholomew, and you, our listener. See you next week.
This article is about leadership.
Hello there! If you're struggling to decide the foods worth buying organic, best-selling author Michael Pollan has some suggestions for the ones worth splurging on to avoid harmful chemicals .
In today's big story, we're looking at a critical tech review that caused a bit of a stir on social media .
What's on deck:
Markets: Goldman Sachs quiets the haters with a monster earnings report .
Tech: Leaked docs show one of Prime Video's biggest issues, forcing customers to abandon shows .
Business: The best bet in business these days? Targeting young men who like to gamble .
But first, the review is in!
If this was forwarded to you, sign up here.
Up for review.
"The Worst Product I've Ever Reviewed… For Now"
Marques Brownlee, the YouTuber better known as MKBHD, didn't mince words with the title of his review of Humane's AI Pin .
In a 25-minute video , Brownlee details all the issues he encountered using the AI device. (Spoiler alert: There were a lot.)
Brownlee's review aligns with other criticisms of the device . But not all of those came from someone with as much sway. His YouTube channel has more than 18 million subscribers.
One user on X pointed that out , calling the review "almost unethical" for "potentially killing someone else's nascent project" in a post reposted over 2,000 times.
Most of the internet disagreed, and a Humane exec even thanked Brownlee on X for the "fair and valid critiques."
But it highlights the power of Brownlee's reviews. Earlier this year, a negative video of Fisker's Ocean SUV by Brownlee also made waves on social media .
Critical reviews in the age of innovation raise some interesting questions.
To be clear, there was nothing wrong with Brownlee's review. Humane's AI Pin costs $700. Watering down his review to ease the blow would be a disservice to the millions of fans relying on his perspective before making such a significant purchase.
Too often, companies view potential customers as an extension of their research and development. They are happy to sell a product that is still a work in progress on the promise they'll fix it on the fly. ("Updates are coming!")
But in a world of instant gratification, it can be hard to appreciate that innovation takes time.
Even Apple can run into this conundrum. Take the Apple Vision Pro. Reviewers are impressed with the technology behind the much-anticipated gadget — but are still struggling to figure out what they can do with it . Maybe, over time, that will get sorted out. It's also worth remembering how cool tech can be, as Business Insider's Peter Kafka wrote following a bunch of trips in Waymo's software-powered taxis in San Francisco . Sure, robotaxis have their issues, Peter said, but they also elicit that "golly-gee-can-you-believe-it" sense.
As for Humane, America loves a comeback story. Just look at "Cyberpunk 2077." The highly anticipated video game had a disastrous launch in 2020 , but redeemed itself three years later, ultimately winning a major award .
Still, Humane shouldn't get a pass for releasing a product that didn't seem ready for primetime, according to the reviews.
And its issue could be bigger than glitchy tech. Humane's broader thesis about reducing screen time might not be as applicable. As BI's Katie Notopolous put it: " I love staring at my iPhone ."
1. Goldman finally strikes gold. After a rough stretch, the vaunted investment bank crushed earnings expectations , sending its stock soaring. A big tailwind, according to CEO David Solomon, is AI spawning " enormous opportunities " for the bank.
2. Buy the dip, Wedbush says. Last week's drop among tech stocks shouldn't scare away investors , according to Wedbush. A strong earnings report, buoyed by the ongoing AI craze, should keep them soaring, strategists said. But JPMorgan doesn't see it that way, saying prices are already stretched .
3. China's economy beat analysts' expectations. The country's GDP grew 5.3% in the first quarter of 2024, according to data published by the National Bureau of Statistics on Tuesday. It's a welcome return to form for the world's second-largest economy, although below-par new home and retail sales remain a cause for concern .
1. Amazon Prime Video viewers are giving up on its shows. Leaked documents show viewers are fed up with the streamer's error-ridden catalog system , which often has incomplete titles and missing episodes. In 2021, 60% of all content-related complaints were about Prime Video's catalog.
2. Eric Newcomer is bringing his Cerebral Valley AI Summit to New York. The conference, originally held in San Francisco, is famous for producing one of the largest generative AI acquisitions ever. Now, it's coming to New York in June .
3. OpenAI is plotting an expansion to NYC. Two people familiar with the plans told BI that the ChatGPT developer is looking to open a New York office next year. That would be the company's fifth office, alongside its current headquarters in San Francisco, a just-opened site in Tokyo, and spots in London and Dublin.
1. America's young men are spending their money like never before. From sports betting to meme coins, young men are more willing than ever to blow money in the hopes of making a fortune .
2. Investors are getting into women's sports. With women like Caitlin Clark dominating March Madness headlines, investors see a big opportunity. BI compiled a list of 13 investors and fund managers pouring money into the next big thing in sports.
3. Bad news for Live Nation. The Wall Street Journal reports that the Justice Department could hit the concert giant with an antitrust lawsuit as soon as next month. Live Nation, which owns Ticketmaster, has long faced criticism over its high fees.
Blackstone hires Walmart AI whiz to supercharge its portfolio companies .
Taylor Swift, Rihanna, Blackpink's Lisa: Celebrities spotted at Coachella 2024 .
NYC's rat czar says stop feeding the pigeons if you want the vermin gone .
A major Tesla executive left after 18 years at the company amid mass layoffs .
Some Tesla factory workers realized they were laid off when security scanned their badges and sent them back on shuttles, sources say .
New York is in, San Francisco is very much out for tech workers relocating .
AI could split workers into 2: The ones whose jobs get better and the ones who lose them completely .
Oh look at that! Now Google is using AI to answer search queries .
A longtime banker gives a rare inside look at how he is thinking about his next career move, from compensation to WFH .
Clarence Thomas didn't show up for work today .
Today's earnings: United Airlines, Bank of America, Morgan Stanley, and others are reporting .
It's Free Cone Day at participating Ben & Jerry's stores.
The Insider Today team: Dan DeFrancesco , deputy editor and anchor, in New York. Jordan Parker Erb , editor, in New York. Hallam Bullock , senior editor, in London. George Glover , reporter, in London.
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The following questions are multiple choice questions. Choose the most appropriate answer. (i) At infinite dilution, the equivalent conductance of CaSO 4 is. (a) 256 x 10-4. (b) 279. (c) 23.7. (d) 2.0 x 10- 8. (ii) If the degree of dissociation of CaSO 4 solution is 10% then equivalent conductance of CaSO 4 is.
There is Case Study Questions in class 12 Chemistry in session 2020-21. For the first time, the board has introduced the case study questions in the board exam. The first two questions in the board exam question paper will be based on Case Study and Assertion & Reason. The first question will have 5 MCQs … Continue reading Case Study Questions for Class 12 Chemistry Chapter 3 Electrochemistry
We have provided here Case Study questions for the Class 12 Chemistry Final Board exams. You can read these chapter-wise Case Study questions. ... Electrochemistry: 18: 9: 3: Chemical Kinetics: 15: 7: 4: d -and f -Block Elements: 18: 7: 5: Coordination Compounds: 18: 7: 6: Haloalkanes and Haloarenes: 15: 6: 7: Alcohols, Phenols and Ethers: 14: ...
A dry-cell battery is a battery with a paste electrolyte (as opposed to a wet-cell battery with a liquid electrolyte) in the the middle of its cylinder and attached are metal electrodes. A dry-cell battery is a primary cell that cannot be reused. In order to function, each dry-cell battery has a cathode and an anode.
The PDF file of the Electrochemistry Case Study for Class 12 Chemistry with Solutions is a very important study resource that can help students better prepare for the exam and boost conceptual learning. The solutions are in the hint manner as well as contain full examples too, refer to the link to access the Case Study on Electrochemistry Class ...
Case Il : Read the passage given below and answer the following questions from 58 to 62. The electrochemical cell shown below is concentration cell. M I M2+ (saturated solution of a sparingly soluble The emf of the cell depends on the difference in concentrations ofM2 • ions at the two electrodes.
Important Questions, MCQ's, NCERT Solutions - Class 12 Chemistry . Get here all the Important questions for Class 12 Chemistry chapter wise as free PDF download. Here you will get Extra Important Questions with answers, Numericals and Multiple Choice Questions (MCQ's) chapter wise in Printable format. Solving Chapter wise questions is one of the best ways to prepare for the examination.
Electrochemistry Basics. Electrochemistry is the study of chemical processes that cause electrons to move. This movement of electrons is called electricity, which can be generated by movements of electrons from one element to another in a reaction known as an oxidation-reduction ("redox") reaction.
Choose 1 answer: (Choice A) At equilibrium, E c e l l. . calculates to a value of 0 and the battery is considered dead because Q becomes K e q. . and K e q. . has a value of 0.
Case Study: Industrial Electrolysis. Page ID. Electrolysis reactions are the basic foundations of today's modern industry. There are various elements, chemical compounds, and organic compounds that are only produced by electrolysis including aluminum, chlorine, and NaOH. Electrolysis is the process by which an electric current spurs an ...
QB365 Provides the updated CASE Study Questions for Class 12 , and also provide the detail solution for each and every case study questions . Case study questions are latest updated question pattern from NCERT, QB365 will helps to get more marks in Exams - Complete list of 12th Standard CBSE question papers, syllabus, exam tips, study material, previous year exam question papers, centum tips ...
This will help them to understand the type of Case Study questions that can be asked in Grade 12 Chemistry examinations. Our expert faculty for standard 12 Chemistry have designed these questions based on the trend of questions that have been asked in last year's exams. The solutions have been designed in a manner to help the grade 12 ...
Using reduction potentials. Standard reduction potentials. Voltage as an intensive property. Spontaneity and redox reactions. Free energy and cell potential. Worked example: Constructing a galvanic cell using reduction potential values. Worked example: Identifying the best oxidising agent using Eo (red.) values.
Class 12 Chemistry Case Study Questions for Term 1 exam includes The Solid State, The P block elements, Haloalkanes and Haloarenes, Biomolecules, etc. Questions for all these chapters are given in the PDF file that are available here for free to download. Term 1 exam is about to be held in November-December this year.
Tag: case study questions on electrochemistry. Join our Telegram Channel for Free PDF Download. Join Now! March 17, 2021 August 6, 2021 Physics Gurukul 1 Comment on Case Study Questions for Class 12 Chemistry Chapter 3 Electrochemistry.
Solution: (a) Both assertion and reason are true and the reason is correct explanation for assertion. 4. Assertion : Λ m for weak electrolytes shows a sharp increase when the electrolytic solution is diluted. Reason : For weak electrolytes degree of dissociation increases with dilution of solution.
Class 12th Chemsitry - Electrochemistry Case Study Questions and Answers 2022 - 2023 - Complete list of 12th Standard CBSE question papers, syllabus, exam tips, study material, previous year exam question papers, centum tips, formula, answer keys, solutions etc..
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The following questions are multiple choice questions. Choose the most appropriate answer: Q. The total number of moles of chlorine gas evolved is. A. 0.5. B. 1.0. C. 1.5. D. 1.9. Detailed Solution for Case Based Questions Test: Electrochemistry - Question 13.
Fuel cells offer cleaner, quieter, and more efficient power production than conventional internal combustion engines. Fuel cells can use a variety of fuels, such as: natural gas, methanol, gasoline, and hydrogen. Fuel cells are becoming increasingly reliable, with some systems demonstrating very low degradation rates.
knowledge and literature in electrochemistry. The entire platform can be conveniently installed in a glovebox (Fig. 1b, c) to ensure compat-ibility with oxygen- and moisture-sensitive chemistry. As an initial case study, we deployed an autonomous closed-loop workflow to investigate the oxidative addition of RX electrophiles to
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Ultimately, though, the promise of green hydrogen will hinge on how businesses and policymakers weigh several questions, trade-offs, and potential long-term consequences. We know from previous ...
Case Study: Treating and Managing a Pediatric Uvular Cyst. Prompt surgery was necessary when symptoms drastically increased. An 18-month-old patient presented with persistent ear infections but did not have any noticeable upper airway or oral symptoms. The patient was originally seen by W. Kyle Mudd, DO, a pediatrician at Cleveland Clinic, who ...
Without decisive action, carbon emissions associated with these sectors are set to more than double by 2050. The rapid expansion of affordable renewable electricity presents unprecedented opportunities to revolutionize conventional engineering processes through electrochemistry, thus providing solutions to our society's grand challenges.
In this episode, he explains how to approach what he calls "gray-area decisions.". First, gather as much information as you can, taking different perspectives into account. Then, consider the ...
For Now". Marques Brownlee, the YouTuber better known as MKBHD, didn't mince words with the title of his review of Humane's AI Pin. In a 25-minute video, Brownlee details all the issues he ...