java object assignment by value

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By Rafael del Nero , Java Developer, JavaWorld |

Tease your mind and test your learning, with these quick introductions to challenging concepts in Java programming.

Does Java pass by reference or pass by value?

You've probably heard that java passes by value, but what matters is how well you understand the concept and the code. find out what happens when you pass an object reference to a method in java..

Object references are passed by value

Are primitive types passed by value, passing immutable object references, passing mutable object references, take the object references challenge, what’s just happened, learn more about java.

Many programming languages allow passing parameters by reference or by value . In Java, we can only pass parameters by value . This imposes some limits and also raises questions. For instance, if the parameter value is changed in the method, what happens to the value following method execution? You may also wonder how Java manages object values in the memory heap. This Java Challenger helps you resolve these and other common questions about object references in Java.

All object references in Java are passed by value. This means that a copy of the value will be passed to a method. But the trick is that passing a copy of the value also changes the real value of the object. To understand why, start with this example:

What do you think the simpson.name will be after the transformIntoHomer method is executed?

In this case, it will be Homer! The reason is that Java object variables are simply references that point to real objects in the memory heap. Therefore, even though Java passes parameters to methods by value, if the variable points to an object reference, the real object will also be changed.

If you’re still not quite clear how this works, take a look at the figure below.

Like object types, primitive types are also passed by value. Can you deduce what will happen to the primitive types in the following code example?

If you determined that the value would change to 30, you are correct. It’s 30 because (again) Java passes object parameters by value. The number 30 is just a copy of the value, not the real value. Primitive types are allocated in the stack memory, so only the local value will be changed. In this case, there is no object reference.

What if we did the same test with an immutable String object?

The JDK contains many immutable classes. Examples include the wrapper types Integer , Double , Float , Long , Boolean , BigDecimal , and of course the very well known String class.

In the next example, notice what happens when we change the value of a String .

What do you think the output will be? If you guessed “” then congratulations! That happens because a String object is immutable, which means that the fields inside the String are final and can’t be changed.

Making the String class immutable gives us better control over one of Java’s most used objects. If the value of a String could be changed, it would create a lot of bugs. Also note that we’re not changing an attribute of the String class; instead, we’re simply assigning a new String value to it. In this case, the “Homer” value will be passed to name in the changeToHomer method. The String “Homer” will be eligible to be garbage collected as soon as the changeToHomer method completes execution. Even though the object can’t be changed, the local variable will be.

Unlike String , most objects in the JDK are mutable, like the StringBuilder class. The example below is similar to the previous one, but features StringBuilder rather than String :

Can you deduce the output for this example? In this case, because we’re working with a mutable object, the output will be “Homer Simpson.” You could expect the same behaviour from any other mutable object in Java.

You’ve already learned that Java variables are passed by value, meaning that a copy of the value is passed. Just remember that the copied value points to a real object in the Java memory heap. Passing by value still changes the value of the real object.

In this Java Challenger we’ll test what you’ve learned about object references. In the code example below, you see the immutable String and the mutable StringBuilder class. Each is being passed as a parameter to a method. Knowing that Java only passes by value, what do you believe will be the output once the main method from this class is executed?

Here are the options, check the end of this article for the answer key.

A : Warrior=null Weapon=null B : Warrior=Dragon Weapon=Dragon C : Warrior=Dragon Knight Weapon=Dragon Sword D : Warrior=Dragon Knight Weapon=Sword

The first parameter in the above example is the warriorProfession variable, which is a mutable object. The second parameter, weapon, is an immutable String :

Now let’s analyze what is happening inside this method. At the first line of this method, we append the Knight value to the warriorProfession variable. Remember that warriorProfession is a mutable object; therefore the real object will be changed, and the value from it will be “Dragon Knight.”

In the second instruction, the immutable local String variable will be changed to “Dragon Sword.” The real object will never be changed, however, since String is immutable and its attributes are final:

Finally, we pass null to the variables here, but not to the objects. The objects will remain the same as long as they are still accessible externally--in this case through the main method. And, although the local variables will be null, nothing will happen to the objects:

From all of this we can conclude that the final values from our mutable StringBuilder and immutable String will be:

The only value that changed in the changeWarriorClass method was warriorProfession , because it’s a mutable StringBuilder object. Note that warriorWeapon did not change because it’s an immutable String object.

The correct output from our Challenger code would be:

D : Warrior=Dragon Knight Weapon=Sword.

Video challenge! Debugging object references in Java

Debugging is one of the easiest ways to fully absorb programming concepts while also improving your code. In this video you can follow along while I debug and explain object references in Java.

Common mistakes with object references

• Trying to change an immutable value by reference.
• Trying to change a primitive variable by reference.
• Expecting the real object won't change when you change a mutable object parameter in a method.

What to remember about object references

• Java always passes parameter variables by value.
• Object variables in Java always point to the real object in the memory heap.
• A mutable object’s value can be changed when it is passed to a method.
• An immutable object’s value cannot be changed, even if it is passed a new value.
• “Passing by value” refers to passing a copy of the value.
• “Passing by reference” refers to passing the real reference of the variable in memory.
• Get more quick code tips: Read all of Rafael's articles in the InfoWorld Java Challengers series.
• Check out more videos in Rafael's Java Challengers video playlist .
• Find even more Java Challengers on Rafael's Java Challengers blog and in his book, with more than 70 code challenges .

This story, "Does Java pass by reference or pass by value?" was originally published by JavaWorld .

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Last Minute Java Object Assignment and Object Passing By Value or Reference Explained Tutorial

In Java, we create Classes. We create objects of the Classes. Let us know if it is possible to assign a Java Object  from one variable to another variable by value or reference in this Last Minute Java Tutorial. We also try to know whether it is possible to pass Java Objects to another method by Value or Reference in this tutorial.

You may also read about Introduction to Java Class Structure .

Java Object Assignment by Value or Reference Explained

In Java, objects are always passed by Reference. Reference is nothing but the starting address of a memory location where the actual object lies. You can create any number of references to just One Object. Let us go by an example.

We create a Class "Cloud" with a single Property called "color". It is a String object. We create 3 objects of the Cloud type.

Notice that all three references obj1, obj2 and obj3 are pointing to the same Cloud object. Thus the above example outputs the same color-property value " RED ". Later, we made the references obj2 and obj3 to point to the null location. Still the original object pointed or referenced by obj1 holds the value. So the final PRINT statement outputs "RED" as usual.

Note : Reference is also called a Variable whether Primitive or Object.

This concludes that a Java object assignment happens by Reference . But the actual value of memory location pointed by References are copied by Value only. So we are actually copying memory locations from one Reference variable to another Reference variable by Value . Interviewers ask this famous Java question just to test your knowledge. If someone asks in C language point of view , say that it is by Reference . If they ask in Java point of view , say that it is by Value. 

Java Object Passing by Value or Reference to a Method Explained

You already learnt that Object assignment in Java happens by Reference. Let us try to pass Objects to another method as a parameter or argument. We try to know whether Objects are passed by Value or Reference to another Method using the below example.

In the above example, we have created an object "obj1" of type Tractor. We assigned value of 100 to the property "height". We printed the value before passing the object to another method. Now, we passed the object to another method called "change" from the calling-method " main ". We modified the height property to 200 in the called-method . Now, we tried to print the value of the property in the Calling method. It shows that the Object is modified in the called-method.

Similarly, we can pass Java objects to the Constructor using Pass by Reference or simply Reference . 

This concludes that Java Objects are passed to methods by Reference . Here also, we pass the memory location pointed by one Reference variable to another Reference variable of a Called method as a Value only. So, you are actually passing Values (memory locations represented by integer or long data type). But the actual passed-object can only be referenced by a Reference variable. Interviewers take advantage of this tricky logic to confuse you. If someone asks in C language point of view , say that it is by Reference . If they ask in Java point of view , say that it is by Value .

Let us know more about Java Classes with different Constructors and Methods in coming chapters.

Share this Last Minute Java  Tutorial explaining Java Object Assignment using Reference and Java Object Passing with Pass by Reference with your friends and colleagues to encourage authors.

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Passing by Value vs. Passing by Reference in Java

While many languages put information passing into the hands of developers, all data is passed by value in java. see how to turn that restriction to your advantage..

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Understanding the technique used to pass information between variables and into methods can be a difficult task for a Java developer, especially those accustomed to a much more verbose programming language, such as C or C++. In these expressive languages, the developer is solely responsible for determining the technique used to pass information between different parts of the system. For example, C++ allows a developer to explicitly pass a piece of data either by value, by reference, or by pointer. The compiler simply ensures that the selected technique is properly implemented and that no invalid operation is performed.

In the case of Java, these low-level details are abstracted, which both reduces the onus on the developer to select a proper means of passing data and increases the security of the language (by inhibiting the manipulation of pointers and directly addressing memory). In addition, though, this level of abstraction hides the details of the technique performed, which can obfuscate a developer's understanding of how data is passed in a program. In this article, we will examine the various techniques used to pass data and deep-dive into the technique that the Java Virtual Machine (JVM) and the Java Programming Language use to pass data, as well as explore some examples that demonstrate in practical terms what these techniques mean for a developer.

Terminology

In general, there are two main techniques for passing data in a programming language: (1) passing by value and (2) passing by reference. While some languages consider passing by reference and passing by pointer two different techniques, in theory, one technique can be thought of as a specialization of the other, where a reference is simply an alias to an object, whose implementation is a pointer.

Passing by Value

The first technique, passing by value, is defined as follows:

Passing by value constitutes copying of data, where changes to the copied value are not reflected in the original value

For example, if we call a method that accepts a single integer argument and the method makes an assignment to this argument, the assignment is not preserved once the method returns. While one might expect that the assignment is preserved after the method returns, the assignment is lost because the value placed on the call stack was a copy of the value passed into the method, as illustrated in the snippet below:

If we execute this code, we obtain the following output:

We see that the change made to the argument passed into the process function was not preserved after we exited the scope of the function. This loss of data was due to the fact that a copy of the value held by the someValue variable was placed on the call stack prior to the execution of the process function. Once the process function exited, this copy was popped from the call stack and the changes made to it were lost, as illustrated in the figure below:

Additionally, the action of popping the call stack at the completion of the process method is illustrated in the figure below. Note that the value copied as the argument to the process method is lost (reclaimed) once the call stack is popped, and therefore, all changes made to that value are in turn lost during the reclamation step.

Passing by Reference

The alternative to passing by value is passing by reference, which is defined as follows:

Passing by reference consitutes the aliasing of data, where changes to the aliased value are reflected in the original value

Unlike passing by value, passing by reference ensures that a change made to a value in a different scope is preserved when that scope is exited. For example, if we pass a single argument into a method by reference, and the method makes an assignment to that value within its body, the assignment is preserved when the method exits. This can be demonstrated using the following snippet of C++ code:

If we run this code, we obtain the following output:

In this example, we can see that when we exit the function, the assignment we made to our argument that was passed by reference was preserved outside of the scope of the function. In the case of C++, we can see that under-the-hood, the compiler has passed a pointer into the function that points to the someValue variable. Thus, when this pointer is dereferenced (as happens during reassignment), we are making a change to the exact location in memory that stores the someValue variable. This principle is demonstrated in the illustrations below:

Passing Data in Java

Unlike in C++, Java does not have a means of explicitly differentiating between pass by reference and pass by value. Instead, the Java Language Specification ( Section 4.3 ) declares that the passing of all data, both object and primitive data, is defined by the following rule:

All data is passed by value

Although this rule may be simple on the surface, it requires some further explanation. In the case of primitive values, the value is simply the actual data associated with the primitive (.e.g 1 , 20.7 , true , etc.) and the value of the data is copied each time it is passed. For example, if we define an expression such as int x = 7 , the variable x holds the literal value of 7 . In the case of objects in Java, a more expanded rule is used:

The value associated with an object is actually a pointer, called a reference, to the object in memory

For example, if we define an expression such as Foo foo = new Foo() , the variable foo does not hold the Foo object created, but rather, a pointer value to the created Foo object. The value of this pointer to the object (what the Java specification calls an object reference , or simply reference) is copied each time it is passed. According to the Objects section (Section 4.3.1) of the Java Language Specification, only the following can be performed on an object reference:

• Field access, using either a qualified name or a field access expression
• Method invocation
• The cast operator
• The string concatenation operator  + , which, when given a  String operand and a reference, will convert the reference to a  String by invoking the  toString method of the referenced object (using  "null" if either the reference or the result of  toString is a null reference), and then will produce a newly created  String that is the concatenation of the two strings
• The instanceof operator
• The reference equality operators == and !=
• The conditional operator  ? :

In practice, this means that we can change the fields of the object passed into a method and invoke its methods, but we cannot change the object that the reference points to. Since the pointer is passed into the method by value, the original pointer is copied to the call stack when the method is invoked. When the method scope is exited, the copied pointer is lost, thus losing the change to the pointer value.

Although the pointer is lost, the changes to the fields are preserved because we are dereferencing the pointer to access the pointed-to object: The pointer passed into the method and the pointer copied to the call stack are identical (although independent) and thus point to the same object. Thus, when the pointer is dereferenced, the same object at the same location in memory is accessed. Therefore, when we make a change to the dereferenced object, we are changing a shared object. This concept is illustrated in the figure below:

This should not be confused with passing by reference: If the pointer were passed by reference, the variable foo would be an alias to someFoo and changing the object that foo points to would also change the object that someFoo points to. In this case, though, a copied pointer is passed into the function, and thus, the change to the pointer value is lost once the call stack it popped.

While it is crucial to understand the concepts behind passing data in a programming language (Java in particular), many times it is difficult to solidify these theoretical ideas without concrete examples. In this section, we will cover four primary examples:

• Assigning primitive values to a variable
• Passing primitive values to a method
• Assigning object values to a variable
• Passing object values to a method

For each of these examples, we will explore a snippet of code accompanied by print statements that show the value of the primitive or object at each major step in the assignment or the argument-passing process.

Primitive Type Example

Since Java primitives are not objects, primitives and objects are treated as two separate cases with respect to data binding (assignment) and argument-passing. In this section, we will focus on binding primitive data to a variable and passing primitive data to a simple method.

Assigning Values to Variable

If we assign an existing primitive value, such as someValue , to a new variable, anotherValue , the primitive value is copied to the new variable. Since the value is copied, the two variables are not aliases of one another, and therefore, when the original variable, someValue , is changed, the change is not reflected in anotherValue :

If we execute this snippet, we receive the following output:

Passing Values to Method

Similar to making primitive assignments, the arguments for a method are bound by value, and thus, if a change is made to the argument within the scope of the method, the changes are not preserved when the method scope is exited:

If we run this code, we see that the original value of 7 is preserved when the scope of the process method is exited, even though that argument was assigned a value of 50 within the method scope:

Object Type Example

While all values, both primitive and object, are passed by value in Java, there are some nuances in passing objects by value that are made explicit when seen in an example. Just as with primitive types, we will explore both assignment and argument binding the following examples.

The variable binding semantics of for objects and primitives are nearly identical, but instead of binding a copy of the primitive value, we bind a copy of the object address. We can see this in action in the following snippet:

In this example, we expect that assigning a new Ball object to someBall (after assigning someBall to anotherBall ) does not change the value of anotherBall , since anotherBall holds a copy of the address for the original someBall . When the address stored at someBall changes, no change is made to anotherBall because the copied value in anotherBall is completely independent of the address value stored in someBall . If we execute this code, we see our expected results (note that the address of each Ball object will vary between executions, but the address in line 1 and line 3 should be identical, regardless of the specific address value):

Passing Values to Methods

The last case we must cover is that of passing an object into a method. In this case, we see that we are able to change the fields associated with the passed in object, but if we try to reassign a value to the argument itself, this reassignment is lost when the method scope is exited.

If we execute this code, we see the following output:

Although there is a large volume of output, if we take each line one at a time, we see that when we make a change to the fields of a Vehicle object passed into a method, the field changes are preserved, but when we try to reassign a new Vehicle object to the argument, the change is not preserved once we leave the scope of the method.

In the former case, the address of the Vehicle created outside the method is copied to the argument of the method, and thus both point to the same Vehicle object. If this pointer is dereferenced (which occurs when the fields of the object are accessed or changed), the same object is changed. In the latter case, when we try to reassign the argument with a new address, the change is lost because the argument is only a copy of the address of the original object, and thus, once the method scope is exited, the copy is lost.

A secondary principle can be formed from this mechanism in Java: Do not reassign arguments passed into a method (codified by Martin Fowler in the refactoring Remove Assignments to Parameters ). To ensure that no such reassignment of method arguments is made, the arguments can be marked as final in the method signature. Note that a new local variable can be used instead of the arguments if reassigned is required:

Although fundamental principles such as data binding schemes and data passing schemes can seem abstract in the realm of daily programming, these concepts are essential in avoiding subtle mistakes. Unlike other programming languages (such as C++), Java simplifies its data binding and passing scheme into a single rule: Data is always passed by value. Although this rule can be a harsh restriction, its simplicity, and understanding how to apply this simplicity, can be a major asset when accomplishing a slew of daily tasks.

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The Java Tutorials have been written for JDK 8. Examples and practices described in this page don't take advantage of improvements introduced in later releases and might use technology no longer available. See Java Language Changes for a summary of updated language features in Java SE 9 and subsequent releases. See JDK Release Notes for information about new features, enhancements, and removed or deprecated options for all JDK releases.

Assignment, Arithmetic, and Unary Operators

The simple assignment operator.

One of the most common operators that you'll encounter is the simple assignment operator " = ". You saw this operator in the Bicycle class; it assigns the value on its right to the operand on its left:

This operator can also be used on objects to assign object references , as discussed in Creating Objects .

The Arithmetic Operators

The Java programming language provides operators that perform addition, subtraction, multiplication, and division. There's a good chance you'll recognize them by their counterparts in basic mathematics. The only symbol that might look new to you is " % ", which divides one operand by another and returns the remainder as its result.

The following program, ArithmeticDemo , tests the arithmetic operators.

This program prints the following:

You can also combine the arithmetic operators with the simple assignment operator to create compound assignments . For example, x+=1; and x=x+1; both increment the value of x by 1.

The + operator can also be used for concatenating (joining) two strings together, as shown in the following ConcatDemo program:

By the end of this program, the variable thirdString contains "This is a concatenated string.", which gets printed to standard output.

The Unary Operators

The unary operators require only one operand; they perform various operations such as incrementing/decrementing a value by one, negating an expression, or inverting the value of a boolean.

The following program, UnaryDemo , tests the unary operators:

The increment/decrement operators can be applied before (prefix) or after (postfix) the operand. The code result++; and ++result; will both end in result being incremented by one. The only difference is that the prefix version ( ++result ) evaluates to the incremented value, whereas the postfix version ( result++ ) evaluates to the original value. If you are just performing a simple increment/decrement, it doesn't really matter which version you choose. But if you use this operator in part of a larger expression, the one that you choose may make a significant difference.

The following program, PrePostDemo , illustrates the prefix/postfix unary increment operator:

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Array Variable Assignment in Java

An array is a collection of similar types of data in a contiguous location in memory. After Declaring an array we create and assign it a value or variable. During the assignment variable of the array things, we have to remember and have to check the below condition.

1. Element Level Promotion

Element-level promotions are not applicable at the array level. Like a character can be promoted to integer but a character array type cannot be promoted to int type array.

2. For Object Type Array

In the case of object-type arrays, child-type array variables can be assigned to parent-type array variables. That means after creating a parent-type array object we can assign a child array in this parent array.

When we assign one array to another array internally, the internal element or value won’t be copied, only the reference variable will be assigned hence sizes are not important but the type must be matched.

3. Dimension Matching

When we assign one array to another array in java, the dimension must be matched which means if one array is in a single dimension then another array must be in a single dimension. Samely if one array is in two dimensions another array must be in two dimensions. So, when we perform array assignment size is not important but dimension and type must be matched.

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Object.assign()

The Object.assign() static method copies all enumerable own properties from one or more source objects to a target object . It returns the modified target object.

The target object — what to apply the sources' properties to, which is returned after it is modified.

The source object(s) — objects containing the properties you want to apply.

Return value

The target object.

Description

Properties in the target object are overwritten by properties in the sources if they have the same key . Later sources' properties overwrite earlier ones.

The Object.assign() method only copies enumerable and own properties from a source object to a target object. It uses [[Get]] on the source and [[Set]] on the target, so it will invoke getters and setters . Therefore it assigns properties, versus copying or defining new properties. This may make it unsuitable for merging new properties into a prototype if the merge sources contain getters.

For copying property definitions (including their enumerability) into prototypes, use Object.getOwnPropertyDescriptor() and Object.defineProperty() instead.

Both String and Symbol properties are copied.

In case of an error, for example if a property is non-writable, a TypeError is raised, and the target object is changed if any properties are added before the error is raised.

Note: Object.assign() does not throw on null or undefined sources.

Cloning an object

Warning for deep clone.

For deep cloning , we need to use alternatives like structuredClone() , because Object.assign() copies property values.

If the source value is a reference to an object, it only copies the reference value.

Merging objects

Merging objects with same properties.

The properties are overwritten by other objects that have the same properties later in the parameters order.

Copying symbol-typed properties

Properties on the prototype chain and non-enumerable properties cannot be copied, primitives will be wrapped to objects, exceptions will interrupt the ongoing copying task, copying accessors, specifications, browser compatibility.

BCD tables only load in the browser with JavaScript enabled. Enable JavaScript to view data.

• Polyfill of Object.assign in core-js
• Object.defineProperties()
• Enumerability and ownership of properties
• Spread in object literals

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Object in java Assignment and Object Passing By Value or Reference

Table of Contents

Study and learn Interview MCQ Questions and Answers on object in java . Attend job interviews easily with these Multiple Choice Questions.

Object in java

Objects are always passed by Reference. Reference is nothing but the starting address of a memory location where the actual object lies. You can create any number of references to just One Object. Let us go by an example .

We create a Class “Cloud” with a single Property called “color”. It is a String object . We create 3 objects of the Cloud type.

Notice that all three references obj1, obj2 and obj3 are pointing to the same Cloud object. Thus the above example outputs the same color-property value “ RED “. Later, we made the references obj2 and obj3 to point to the null location. Still the original object pointed or referenced by obj1 holds the value. So the final PRINT statement outputs “RED” as usual.

Note : Reference is also called a Variable whether Pri-mitive or Object.

This concludes that a Java object assignment happens by Reference . But the actual value of memory location pointed by References are copied by Value only. So we are actually copying memory locations from one Reference variable to another Reference variable by Value . Interviewers ask this famous Java question just to test your knowledge. If someone asks in C language point of view , say that it is by Reference . If they ask in Java point of view , say that it is by Value. 

object in java Passing by Value or Reference to a Method Explained

You already learnt that Object assignment in Java happens by Reference. Let us try to pass Objects to another method as a parameter or argument.

In the above example, we have created an object “obj1” of type Tractor. We assigned value of 100 to the property “height”. We printed the value before passing the object to another method. Now, we passed the object to another method called “change” from the calling-method “ main “. We modified the height property to 200 in the called-method . Now, we tried to print the value of the property in the Calling method.

Similarly, we can pass Java objects to the Constructor using Pass by Reference or simply Reference . 

Here also, we pass the memory location pointed by one Reference variable to another Reference variable of a Called method as a Value only. So, you are actually passing Values (memory locations represented by integer or long data type). Interviewers take advantage of this tricky logic to confuse you. If someone asks in C language point of view , say that it is by Reference . If they ask in Java point of view , say that it is by Value .

[WpProQuiz 157]

Object in java mcq, 1) what is the output of the below java program with two classes.

A) Hello Boss.!

B) No Output

C) Compiler error

D) None of the above

Answer [=] C

Explanation:

There can not be more than one public class declared inside a single java file.

2) What is the output of the below Java program?

The class name and the java file name should be the same. So, change either file name or class name to match.

3) State TRUE or FALSE. A Java class provides encapsulation.

Answer [=] A

4) What is the output of the below java class?

D) Compiler error

There can be any number of classes in a single .java file.

5) The value of one Pri-mitive variable is assigned to another Pri-mitive variable by ___ in Java.

A) Pass by value

B) Pass by reference

6) A Pri-mitive variable is passed from one method to another method by ___ in Java.

7) an object or pri-mitive value that is passed from one method to another method is called ___ in java. (argument / parameter).

A) Argument

B) Parameter

Answer [=] B

8) An object or a Pri-mitive value that is received in a method from another method is called ___ in Java. (Argument / Parameter)

9) what is the output of the below java program that passes an object to another method, 10) what is the output of the below java program that passes pri-mitive values.

The Pri-mitive values are passed by value only. So, changes in the method modify does not change the original value.

11) Java object assignment happens by ___.

A) Pass by Value

B) Pass by Reference

Yes. That is the reason why you can change the values of variables of the object using another reference.

12) Java object passing from one method to another method happens by ___.

References point to the original objects. So they can change the state of the objects.

13) In Java Pass by reference ___ is passed even if you are passing a reference to an object.

A) Address value

B) Variable value

C) Hash code

Yes. The address is passed automatically by Java. So, Java pundits argue that it is passing a value (Address).

14) A Java reference is comparable to ___ in C language.

B) Structure

15) ___ is the superclass to all Java classes either user-defined or built-in.

C) Superclass

Yes. java.lang.Object is the superclass to all Java classes.

16) State TRUE of FALSE. Java objects have built-in methods to handle threads.

Yes. The methods are wait(), notify() and notifyAll().

17) State TRUE or FALSE. Java Object’s hashcode() method is mainly used with Collection objects.

Java collection classes use the hashcode() method to determine the equality of two objects.

18) What is the output of the below Java program using toString() method?

A) Printing Object=

B) Printing Object=null

C) Printing Object=College Object

print() and println() methods call toString() method of objects automatically.

19) What is the output of the below Java program?

B) Runs= 250

C) Runs= 300

The reference C2 also points to the same object pointed by reference C1.

20) What is the output of the below Java program?

A) Posts=25

C) Posts=null

D) Runtime exception occurs

Even if one REFERENCE to the same object is alive, it can be used to access the object. So, wp2 still works even if wp1 is set to null.

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