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Here we will learn about trigonometry including how to use SOHCAHTOA, inverse trigonometric functions, exact trigonometric values and the hypotenuse. We’ll also learn about the sine rule, the cosine rule, how to find the area of a triangle using ½abSinC , 3 D trigonometry and how to use the sine, cosine and tangent graphs.
There are also trigonometry worksheets based on Edexcel, AQA and OCR exam questions, along with further guidance on where to go next if you’re still stuck.
Trigonometry is the relationship between angles and side lengths within triangles; it is derived from the greek words “trigōnon” meaning triangle and “metron” meaning measure.
Trigonometry was originally used by the Babylonians, over 1500 years before the Greek form that we use today. It is used widely in science and engineering and product design.
The higher GCSE curriculum expands the use of trigonometric functions for non right-angle triangles, developing from the fundamental knowledge of the three trigonometric ratios (expressed as the mnemonic SOHCAHTOA) and exact trigonometric values in right angle triangles.
See also: 15 Trigonometry questions
Get your free trigonometry worksheet of 20+ questions and answers. Includes reasoning and applied questions.
SOHCAHTOA is the abbreviation used to describe the three trigonometric ratios for the sine , cosine and tangent functions.
To determine which trigonometric function you need to use to answer a question, it depends on the location of the angle and the sides of the triangle that will be used. The trigonometric functions apply to right-angle triangles.
We can use SOHCAHTOA to calculate lengths and angles in 2D and 3D shapes by recognising right-angle triangles. E.g. We can find the length A C of a parallelogram or the length A H in the cuboid below.
Step-by-step guide: SOHCAHTOA
The hypotenuse is the longest side of a right angle triangle. It is the side opposite the right angle.
The hypotenuse does not occur for other types of triangles unless we know more information (such as an isosceles triangle can be made from 2 identical right angle triangles, back-to-back).
Once we know which angle we are using, we can label the sides opposite (O) , adjacent ( A ) and hypotenuse (H) . We know the hypotenuse is opposite the right angle. The opposite side is opposite the angle we are using. The adjacent side is next to the angle we are using. The triangle below is labelled based on using the angle θ .
Step-by-step guide: Hypotenuse
ABC is a right angle triangle. The size of angle ACB = 60º and the length BC = 16cm .
Calculate the value of x .
Labelling the sides OAH in relation to the angle 60º , we can use the hypotenuse, and we need to find the adjacent side. We therefore need to use the cosine function.
What are inverse trigonometric functions.
Inverse trigonometric functions allow us to calculate the size of angle θ for a right-angle triangle.
The inverse trigonometric functions look like this:
Step-by-step guide: Trigonometric functions
Calculate the size of angle θ correct to 2 decimal places.
The two sides that can be used to calculate the value of θ are the opposite and the hypotenuse and so we apply the sine function to θ to get
In order to calculate θ , we rearrange the equation by using the inverse sine function.
We therefore have:
What are exact trigonometric values.
Exact trigonometric values are found when the relationship between the sides and the angles in a triangle have a specific relationship. Summarising these values, we obtain the exact trigonometric values for sine, cosine and tangent for 0 ≤ θ ≤ 90º .
ABC is an equilateral triangle. M is the midpoint of AC . Calculate the exact size of the angle θ .
AC = 6cm so MC = 3cm
We therefore have the triangle:
Using the table above,
We need to be able to interpret problems and recognise whether we need to use Pythagoras’ Theorem in 2 D, 3 D, or one of the three trigonometric ratios.
This flow chart describes the information you need to know about a shape in order to solve the problem.
It is important to recognise that with most of these problems, you may need to use the Pythagorean Theorem, or trigonometry, or both within the same question so you must be confident with these topics individually to access this topic fully.
Below is a summary of methods that can be used for right angled triangles:
Calculate the length of the hypotenuse of a right triangle, x , to 1 decimal place.
The two important sides in this question are the opposite side ( O ) to the angle and the hypotenuse ( H ) so we need to use the sine function to calculate the value of x .
Sine rule (the law of sines), what is the sine rule.
The sine rule (or the law of sines) is a relationship between the size of an angle in a triangle and the opposite side. There are three relationships in a triangle as there are 3 angles with their opposing sides but you will only need to use two.
Pythagoras’ Theorem cannot be used to find the third side of a non-right angled triangle. Instead we can use the sine rule or the cosine rule, depending on the information we know about the triangle.
To find a missing angle: \frac{\sin (A)}{a}=\frac{\sin (B)}{b}
To find a missing side: \frac{a}{\sin (A)}=\frac{b}{\sin (B)}
Step-by-step guide: Sine rule
Calculate the length AB . Write your answer to 2 decimal places.
Label each angle A, B and C and each side a, b and c:
Here we know side a and we want to find the length of c , therefore we can state:
Here, the length AB = 7.00cm (2dp) .
What is the cosine rule.
The cosine rule (or the law of cosines) is a formula which can be used to calculate the missing sides of a triangle or to find a missing angle. To do this we need to know the two arrangements of the formula and what each variable represents.
To find a missing side: a^{2}=b^{2}+c^{2}-2bc\cos(A)
To find a missing angle: A=\cos^{-1}(\frac{b^2+c^2-a^2}{2bc})
Step-by-step guide: Cosine rule
Find the length of x for triangle ABC , correct to 2 decimal places.
The vertices are already labelled with A located on the angle we are using so we only need to label the opposite sides of a, b, and c .
Here, we need to find the missing side a , therefore we need to state the cosine rule with a 2 as the subject:
What is 1/2absin(c) .
\frac{1}{2}abSin(C) is a formula to calculate the area of any triangle.
Step-by-step guide: Area of a triangle trig
Calculate the area of the triangle ABC . Write your answer to 2 decimal places.
Here, we label each side a, b, and c .
What is 3d trigonometry.
3 D trigonometry is the application of the trigonometric skills developed for 2 dimensional triangles.
To find missing sides or angles in 3 dimensional shapes, we need to be very clear with the rules and formulae to find these different angles and side lengths. The flowchart below can help determine which function you need to use:
Once you can justify which rule or formulae you need to use, you may need to carry out this process again for another triangle in the question.
Top tip: Look out for common angles or common sides.
Step-by-step guide: 3D trigonometry
Calculate the size of the angle in the triangular prism ABCDEF.
We can see that triangle ABF and triangle ACF share the side AF . We can use triangle ACF to calculate the length of AF , which will then help us calculate the size of angle θ .
This triangle contains no information about the angles so we need to use Pythagoras Theorem.
This is a right angled triangle involving angles so we need to use SOHCAHTOA.
Since we know O and A , we need to use tan.
The trigonometric functions sine, cosine and tangent can be represented by graphs.
For example, as the angle changes, so does the value of sine. This can be plotted on a graph.
Let’s look at this in more detail below.
What are sine, cosine, and tangent graphs.
Trigonometric graphs are a visual representation of the sine, cosine and tangent functions. The horizontal axis represents the angle, usually written as θ , and the vertical axis is the trig function.
See below for all three trigonometric graphs for all angles of θ between -360º and 360º (-360 < θ < 360).
The graph of y = sin(θ)
Step-by-step guide: Sin graph
The graph of y = cos(θ)
Step-by-step guide: Cos graph
The graph of y = tan(θ)
Step-by-step guide: Tan graph
Use the graph of y = tan(θ) to estimate the value of y when θ = 120º .
Here we draw the vertical line at 120º until it reaches the tangent curve and then a horizontal line towards the y -axis.
As the scale for each mark on the y- axis is 0.25 , the value for tan(120) is approximately equal to -1.7 (1dp) .
E.g. This triangle has been incorrectly labelled with the side next to the angle.
This will have an impact on the formula for the sine rule, the cosine rule, and the area of the triangle.
If the triangle is incorrectly labelled it can lead to the use of the incorrect standard or inverse trigonometric function.
This can lose accuracy marks. Always use as many decimal places as possible throughout the calculation, then round the solution.
Use the flowchart to help you to recognise when to use Pythagoras’ Theorem and when to use trigonometry. Remember, you may need to use both.
In order to use the sine rule we need to have pairs of opposite angles and sides.
For the cosine rule and the area of a triangle using A=1/2absin(C) , the angle is included between the two sides. Using any other angle will result in an incorrect solution.
If the vertical height of a triangle is not available then we cannot calculate the area by halving the base times the height.
If the inverse trig function is used instead of the standard trig function, the calculator may return a maths error as the solution does not exist.
The sine and cosine graphs are very similar and can easily be confused with one another. A tip to remember is that you “sine up” from 0 for the sine graph so the line is increasing whereas you “cosine down” from 1 so the line is decreasing for the cosine graph.
The tangent function has an asymptote at 90º because this value is undefined. As the curve repeats every 180º , the next asymptote is at 270º and so on.
Each trigonometric graph is a curve and therefore the only time you are required to use a ruler is to draw a set of axes. Practice sketching each curve freehand and label important values on each axis.
1. Calculate the length of the side BC:
This is a right angled triangle involving angles so use SOHCAHTOA.
First we need to label the sides O, A and H.
We know A and we want to find H so we need to use cos.
2. Using your knowledge of exact trigonometric values, work out the size of the angle marked . \theta
Using the exact trigonometric values,
3. Work out the size of angle \theta .
This is not a right angled triangle and we know an angle and its opposite side so we need to use the sine rule.
4. Calculate the area of the following triangle:
We do not know the base or the height so we need to use:
5. Calculate the length of AE.
The triangles AGH and AEH share the line AH . Using the triangle AGH we can calculate the length of the line AH.
Using the triangle AEH we can calculate the length of AE .
6. Write down the coordinates of a minimum point on the graph of y=cos(\theta) for 0^{\circ} \leqslant \theta \leqslant 360^{\circ}
The minimum point occurs at (180, -1)
1. Below is a sketch of a football pitch ABCD .
(a) Player F is standing exactly 60m perpendicular to Player E on the goal line and 75m from the corner where Player A is standing.
Player A kicks the football directly to Player F . Calculate the bearing of F from A . Write your answer correct to 2 decimal places.
(b) Player F then passes the ball to Player G (the goal keeper). Player G is standing at the midpoint of BC at a bearing of 060^{\circ} from F .
How far is Player G from Player F ? Write your answer to 2 decimal places.
Bearing of F from A = 180 – angle EAF
Angle AEF = \sin^{-1}(\frac{60}{75})
Angle AEF = 53.13^{\circ}
Bearing of F from A = 180 – 53.13 =126.87^{\circ}
FG = \frac{45}{sin(60)}
FG = 51.96m
2. Triangle ABE and ACD are similar with AB:BC = 1:3. Using the information on the diagram, calculate the area of the shaded region BCDE .
State the units in your answer.
Area (ABE) = ½ × a × b × sin(C) = ½ × 4 × 6 × sin(30)
Sin(30) = ½
Area (ABE) = 6cm^2
As AB:BC=1:3, BC= 4 × 3 = 12cm and DE = 6 × 3 = 18cm
AC = 12+4 = 16cm and AD = 6+18 = 24cm
Area (ACD) = ½ × a × b × sin(C) = ½ × 16 × 24 × sin(30)
Area (ACD) = 96cm^2
Area BCDE = 96 – 6 = 90cm^2
3. (a) The cuboid ABCDEFGH is shown below. ADEF is a square face with the side length of 2m , and the length AB = 8cm.
Calculate the length of the line AE. Write your answer as a surd in its simplest form.
(b) Given that the point X lies on the line EH so that XH = 3EX and angle XAB = 54.7^{\circ} , calculate the length of the line BX .
AE^2 = AF^2 + EF^2
AE^2 = 2^2 + 2^2 = 8
AE = \sqrt{8} = 2\sqrt{2}
EX = 8 / 4 = 2m
AX = \sqrt{2^{2}+2\sqrt{2}^{2}}
AX = 2\sqrt{3}
Cosine rule stated to find BX :
BX^{2}=AX^{2}+AB^{2}-2\times{AX}\times{AB}\times\cos(A)
BX^{2}=(2\sqrt{3})^{2}+8^{2}-2\times{2\sqrt{3}}\times{8}\times\cos(54.7)
BX^{2}=43.97m
You have now learned how to:
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1. The angle of elevation of the top of the building at a distance of 50 m from its foot on a horizontal plane is found to be 60 °. Find the height of the building.
2. A ladder placed against a wall such that it reaches the top of the wall of height 6 m and the ladder is inclined at an angle of 60°. Find how far the ladder is from the foot of the wall.
3. A string of a kite is 100 meters long and t he inclination of the string with the ground is 60°. Find the height of the kite, assuming that there is no slack in the string.
4. From the top of the tower 30 m height a man is observing the base of a tree at an angle of depression measuring 30 ° . Find the distance between the tree and the tower.
5. A man wants to determine the height of a light house. He measured the angle at A and found that tan A = 3/4. What is the height of the light house if A is 40 m from the base?
6. A ladder is leaning against a vertical wall makes an angle of 20° with the ground. The foot of the ladder is 3 m from the wall. Find the length of ladder.
7. A kite is flying at a height of 65 m attached to a string. If the inclination of the string with the ground is 31°, find the length of string.
8. The length of a string between a kite and a point on the ground is 90 m. If the string makes an angle θ with the ground level such that tan θ = 15/8, how high will the kite be ?
9. An airplane is observed to be approaching a point that is at a distance of 12 km from the point of observation and makes an angle of elevation of 50 °. Find the height of the airplane above the ground.
10. A balloon is connected to a meteorological station by a cable of length 200 m inclined at 60 ° angle with the ground. Find the height of the balloon from the ground (Imagine that there is no slack in the cable).
1. Answer :
Draw a sketch.
Here, AB represents height of the building, BC represents distance of the building from the point of observation.
In the right triangle ABC, the side which is opposite to the angle 60° is known as opposite side (AB), the side which is opposite to 90° is called hypotenuse side (AC) and the remaining side is called adjacent side (BC).
Now we need to find the length of the side AB.
tanθ = Opposite side/Adjacent side
tan60° = AB/BC
√3 x 50 = AB
Approximate value of √3 is 1.732
AB = 50 (1.732)
AB = 86.6 m
So, the height of the building is 86.6 m.
2. Answer :
Here AB represents height of the wall, BC represents the distance between the wall and the foot of the ladder and AC represents the length of the ladder.
In the right triangle ABC, the side which is opposite to angle 60° is known as opposite side (AB), the side which is opposite to 90° is called hypotenuse side (AC) and remaining side is called adjacent side (BC).
Now, we need to find the distance between foot of the ladder and the wall. That is, we have to find the length of BC.
tanθ = opposite side/adjacent side
BC = (6/√3) x (√3/√3)
BC = (6√3)/3
Approximate value of √3 is 1.732.
BC = 2 (1.732)
BC = 3.464 m
So, the distance between foot of the ladder and the wall is 3.464 m.
3. Answer :
Here AB represents height of kite from the ground, BC represents the distance of kite from the point of observation.
In the right triangle ABC the side which is opposite to angle 60° is known as opposite side (AB), the side which is opposite to 90° is called hypotenuse side (AC) and remaining side is called adjacent side (BC).
Now we need to find the height of the side AB.
sinθ = opposite side/hypotenuse side
sinθ = AB/AC
sin60° = AB/100
√3/2 = AB/100
(√3/2) x 100 = AB
AB = 50√3 m
So, the height of kite from the ground 50√3 m.
4. Answer :
Here AB represents height of the tower, BC represents the distance between foot of the tower and the foot of the tree.
Now we need to find the distance between foot of the tower and the foot of the tree (BC).
tan30° = AB/BC
1/√3 = 30/BC
BC = 30(1.732)
BC = 51.96 m
So, the distance between the tree and the tower is 51.96 m.
5. Answer :
Here BC represents height of the light house, AB represents the distance between the light house from the point of observation.
In the right triangle ABC the side which is opposite to the angle A is known as opposite side (BC), the side which is opposite to 90° is called hypotenuse side (AC) and remaining side is called adjacent side (AB).
Now we need to find the height of the light house (BC).
tanA = opposite side/adjacent side
tanA = BC/AB
Given : tanA = 3/4.
3/4 = BC/40
Multiply each side by 40.
So, the height of the light house is 30 m.
6. Answer :
Here AB represents height of the wall, BC represents the distance of the wall from the foot of the ladder.
In the right triangle ABC, the side which is opposite to the angle 20° is known as opposite side (AB),the side which is opposite to 90° is called hypotenuse side (AC) and remaining side is called adjacent side (BC).
Now we need to find the length of the ladder (AC).
cosθ = adjacent side/hypotenuse side
Cosθ = BC/AC
Cos 20° = 3/AC
0.9397 = 3/AC
AC = 3/0.9396
So, the length of the ladder is about 3.193 m.
7. Answer :
Here AB represents height of the kite. In the right triangle ABC the side which is opposite to angle 31° is known as opposite side (AB), the side which is opposite to 90° is called hypotenuse side (AC) and the remaining side is called adjacent side (BC).
Now we need to find the length of the string AC.
sin31° = AB/AC
0.5150 = 65/AC
AC = 65/0.5150
AC = 126.2 m
Hence, the length of the string is 126.2 m.
8. Answer :
Here AB represents height of the balloon from the ground. In the right triangle ABC the side which is opposite to angle θ is known as opposite side (AB), the side which is opposite to 90° is called hypotenuse side (AC) and remaining side is called adjacent side (BC).
tanθ = 15/8 ----> cotθ = 8/15
cscθ = √(1+ cot 2 θ)
cscθ = √(1 + 64/225)
cscθ = √(225 + 64)/225
cscθ = √289/225
cscθ = 17/15 ----> sinθ = 15/17
But, sinθ = opposite side/hypotenuse side = AB/AC.
AB/AC = 15/17
AB/90 = 15/17
So, the height of the tower is 79.41 m.
9. Answer :
Here AB represents height of the airplane from the ground. In the right triangle ABC the side which is opposite to angle 50° is known as opposite side (AB), the side which is opposite to 90° is called hypotenuse side (AC) and remaining side is called adjacent side (BC).
From the figure given above, AB stands for the height of the airplane above the ground.
sin50° = AB/AC
0.7660 = h/12
0.7660 x 12 = h
So, the height of the airplane above the ground is 9.192 km.
10. Answer :
Here AB represents height of the balloon from the ground. In the right triangle ABC the side which is opposite to angle 60° is known as opposite side (AB), the side which is opposite to 90° is called hypotenuse (AC) and the remaining side is called as adjacent side (BC).
From the figure given above, AB stands for the height of the balloon above the ground.
sin60° = AB/200
√3/2 = AB/200
AB = (√3/2) x 200
AB = 100(1.732)
AB = 173.2 m
So, the height of the balloon from the ground is 173.2 m.
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Study concepts, example questions & explanations for trigonometry, all trigonometry resources, example questions, example question #1 : solving word problems with trigonometry.
You can draw the following right triangle using the information given by the question:
Since you want to find the height of the platform, you will need to use tangent.
You can draw the following right triangle from the information given by the question.
In order to find the height of the flagpole, you will need to use tangent.
You can draw the following right triangle from the information given in the question:
In order to find out how far up the ladder goes, you will need to use sine.
In right triangle ABC, where angle A measures 90 degrees, side AB measures 15 and side AC measures 36, what is the length of side BC?
This triangle cannot exist.
A support wire is anchored 10 meters up from the base of a flagpole, and the wire makes a 25 o angle with the ground. How long is the wire, w? Round your answer to two decimal places.
23.81 meters
28.31 meters
21.83 meters
To make sense of the problem, start by drawing a diagram. Label the angle of elevation as 25 o , the height between the ground and where the wire hits the flagpole as 10 meters, and our unknown, the length of the wire, as w.
Now, we just need to solve for w using the information given in the diagram. We need to ask ourselves which parts of a triangle 10 and w are relative to our known angle of 25 o . 10 is opposite this angle, and w is the hypotenuse. Now, ask yourself which trig function(s) relate opposite and hypotenuse. There are two correct options: sine and cosecant. Using sine is probably the most common, but both options are detailed below.
We know that sine of a given angle is equal to the opposite divided by the hypotenuse, and cosecant of an angle is equal to the hypotenuse divided by the opposite (just the reciprocal of the sine function). Therefore:
To solve this problem instead using the cosecant function, we would get:
The reason that we got 23.7 here and 23.81 above is due to differences in rounding in the middle of the problem.
When the sun is 22 o above the horizon, how long is the shadow cast by a building that is 60 meters high?
To solve this problem, first set up a diagram that shows all of the info given in the problem.
Next, we need to interpret which side length corresponds to the shadow of the building, which is what the problem is asking us to find. Is it the hypotenuse, or the base of the triangle? Think about when you look at a shadow. When you see a shadow, you are seeing it on something else, like the ground, the sidewalk, or another object. We see the shadow on the ground, which corresponds to the base of our triangle, so that is what we'll be solving for. We'll call this base b.
Therefore the shadow cast by the building is 150 meters long.
If you got one of the incorrect answers, you may have used sine or cosine instead of tangent, or you may have used the tangent function but inverted the fraction (adjacent over opposite instead of opposite over adjacent.)
From the top of a lighthouse that sits 105 meters above the sea, the angle of depression of a boat is 19 o . How far from the boat is the top of the lighthouse?
423.18 meters
318.18 meters
36.15 meters
110.53 meters
To solve this problem, we need to create a diagram, but in order to create that diagram, we need to understand the vocabulary that is being used in this question. The following diagram clarifies the difference between an angle of depression (an angle that looks downward; relevant to our problem) and the angle of elevation (an angle that looks upward; relevant to other problems, but not this specific one.) Imagine that the top of the blue altitude line is the top of the lighthouse, the green line labelled GroundHorizon is sea level, and point B is where the boat is.
Merging together the given info and this diagram, we know that the angle of depression is 19 o and and the altitude (blue line) is 105 meters. While the blue line is drawn on the left hand side in the diagram, we can assume is it is the same as the right hand side. Next, we need to think of the trig function that relates the given angle, the given side, and the side we want to solve for. The altitude or blue line is opposite the known angle, and we want to find the distance between the boat (point B) and the top of the lighthouse. That means that we want to determine the length of the hypotenuse, or red line labelled SlantRange. The sine function relates opposite and hypotenuse, so we'll use that here. We get:
Angelina just got a new car, and she wants to ride it to the top of a mountain and visit a lookout point. If she drives 4000 meters along a road that is inclined 22 o to the horizontal, how high above her starting point is she when she arrives at the lookout?
9.37 meters
1480 meters
3708.74 meters
10677.87 meters
1616.1 meters
As with other trig problems, begin with a sketch of a diagram of the given and sought after information.
Angelina and her car start at the bottom left of the diagram. The road she is driving on is the hypotenuse of our triangle, and the angle of the road relative to flat ground is 22 o . Because we want to find the change in height (also called elevation), we want to determine the difference between her ending and starting heights, which is labelled x in the diagram. Next, consider which trig function relates together an angle and the sides opposite and hypotenuse relative to it; the correct one is sine. Then, set up:
Therefore the change in height between Angelina's starting and ending points is 1480 meters.
Two buildings with flat roofs are 50 feet apart. The shorter building is 40 feet tall. From the roof of the shorter building, the angle of elevation to the edge of the taller building is 48 o . How high is the taller building?
To solve this problem, let's start by drawing a diagram of the two buildings, the distance in between them, and the angle between the tops of the two buildings. Then, label in the given lengths and angle.
Two buildings with flat roofs are 80 feet apart. The shorter building is 55 feet tall. From the roof of the shorter building, the angle of elevation to the edge of the taller building is 32 o . How high is the taller building?
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Plus each one comes with an answer key. Law of Sines and Cosines Worksheet. (This sheet is a summative worksheet that focuses on deciding when to use the law of sines or cosines as well as on using both formulas to solve for a single triangle's side or angle) Law of Sines. Ambiguous Case of the Law of Sines. Law Of Cosines.
Trigonometry Worksheets. There are six sets of Trigonometry worksheets: Trig Ratios: Sin, Cos, Tan; Sin & Cos of Complementary Angles; Find Missing Sides; Find Missing Angles; Area of Triangle using Sine; Law of Sines and Cosines; Sine, Cosine, & Tangent Worksheets. In these free math worksheets, students learn how to find the trig ratios: sine ...
Trig Section 1.3: Applying Right Triangles SHORT ANSWER. Solve the problem. 1) A 29 foot water slide has a 17 foot vertical ladder. How far is it along the ground from the end of the slide back to the base of the ladder that leads to the slide? 1) 2) A painter leans a 30 foot ladder against one wall of a house. At what height does the ladder
Trigonometry to Find Angle Measures. 3) tan Y = 0.6494. 5) cos V = 0.6820. 2) cos Z = 0.1219. 4) sin U = 0.8746. 6) sin C = 0.2756. Find the measure of the indicated angle to the nearest degree. 7) ©0 c2209172o 8KGuQtvae 1S8orfLtEwbaWrAeC xLnLECx.R R GAclfl1 ArwingyhztTsh 1rceXs7enrYvJeldj.5 U tMvajdjed rwqiEtHhg 5Ionrf1iNngiItue3 ...
This Trigonometry Worksheet will produce multi-step trigonometric problems. This worksheet is a great resource for the 5th Grade, 6th Grade, 7th Grade, and 8th Grade. These Trigonometry Worksheets allow you to select different variables to customize for your needs. These Geometry worksheets are randomly created and will never repeat.
Click here for Answers. . Answers - Version 1. Trigonometry Answers Version 1 - Corbettmaths. Watch on. Answers - Version 2. Trigonometry Answers Version 2 - Corbettmaths. Watch on. Practice Questions.
Trigonometry worksheets promote an understanding of trigonometry concepts. Students can use these worksheets to improve their skills in solving trigonometric problems. The questions included in the worksheet are based on solving trigonometric identities, deriving trigonometry formulas, understanding trigonometry elements such sines, cosines, etc.
Cazoom Math has created a series of dynamic trigonometry worksheets that will help build your child's knowledge of trigonometry in an exciting and fun way. ... and astronomers. Aside from this, trigonometry can instill problem-solving skills that help students in future careers be able to work well with others. It also builds critical ...
Using Trigonometry improves students' problem solving abilities and promotes critical thinking, skills which will prove useful throughout their studies and into adult life. Providing students with trigonometry worksheets helps to nurture these skills, allowing them to be successful not just at their maths exams but right the way through their ...
The Trigonometry worksheet contains 15 multiple choice questions, with a mix of worded problems and deeper problem solving questions. Answers and a mark scheme for all Trigonometry questions. Follows variation theory with plenty of opportunities for students to work independently at their own level. All questions created by fully qualified ...
456.7 690.7. 452.6. 698.2. Create your own worksheets like this one with Infinite Geometry. Free trial available at KutaSoftware.com.
This Trigonometry Worksheet will produce problems for solving right triangles. This worksheet is a great resource for the 5th Grade, 6th Grade, 7th Grade, and 8th Grade. Worksheets By Topics; ... You may enter a message or special instruction that will appear on the bottom left corner of the Trigonometry Worksheet. Trigonometry Worksheet Answer ...
Trigonometry Worksheets for High School. Explore the surplus collection of trigonometry worksheets that cover key skills in quadrants and angles, measuring angles in degrees and radians, conversion between degrees, minutes and radians, understanding the six trigonometric ratios, unit circles, frequently used trigonometric identities, evaluating ...
40° 50° 2.3 cm 1.9 cm. 24) 6 in AB C. 62° 28° 3.2 in 6.8 in. -2-. Create your own worksheets like this one with Infinite Algebra 2. Free trial available at KutaSoftware.com. Title. Right Triangle Trig Missing Sides and Angles.
Trigonometry 4 units · 36 skills. Unit 1 Right triangles & trigonometry. Unit 2 Trigonometric functions. Unit 3 Non-right triangles & trigonometry. Unit 4 Trigonometric equations and identities. Course challenge. Test your knowledge of the skills in this course. Start Course challenge. Math.
Question 5: Find the size of the angle marked x to 1 decimal place. [2 marks] Level 4-5 GCSE KS3 AQA Edexcel OCR WJEC. Question 6: From a parking space 4\text { m} outside a tall building, the top of the building has an angle of elevation of 87\degree.
Videos and Worksheets; Primary; 5-a-day. 5-a-day GCSE 9-1; 5-a-day Primary; 5-a-day Further Maths; More. Further Maths; GCSE Revision; Revision Cards; Books; Trigonometry Textbook Exercise. Click here for Questions. Textbook Exercise. Previous: Types of Triangles Textbook Exercise. Next: 3D Trigonometry Textbook Exercise. GCSE Revision Cards. 5 ...
Each one has model problems worked out step by step, practice problems, as well as challenge questions at the sheets end. Plus each one comes with an answer key. SOHCAHTOA. Sine, Cosine, tangent, to find side length. Sine, Cosine, Tangent Chart. Inverse Trig Functions. Real World Applications of SOHCATOA.
Subject: Mathematics. Age range: 14-16. Resource type: Worksheet/Activity. File previews. pdf, 59.72 KB. pdf, 58.84 KB. Trigonometry questions designed to test students ability to apply their knowledge of basic trigonometry using the sine, cosine and tangent ratios. Includes problem solving questions. Solutions provided!
Example 1: find a side given the angle and the hypotenuse. ABC is a right angle triangle. The size of angle ACB = 60º and the length BC = 16cm. Calculate the value of x. Labelling the sides OAH in relation to the angle 60º, we can use the hypotenuse, and we need to find the adjacent side. We therefore need to use the cosine function.
Introduction to Trigonometry Choosing a Trigonometric Ratio to Use Calculating Angles & Lengths Using Trigonometry Angles of Elevation & Depression 3D Trigonometry Problems Trigonometry & Bearings 2-Minute Feedback Form
6. A ladder is leaning against a vertical wall makes an angle of 20° with the ground. The foot of the ladder is 3 m from the wall. Find the length of ladder. 7. A kite is flying at a height of 65 m attached to a string. If the inclination of the string with the ground is 31°, find the length of string. 8.
Correct answer: 23.81 meters. Explanation: To make sense of the problem, start by drawing a diagram. Label the angle of elevation as 25 o, the height between the ground and where the wire hits the flagpole as 10 meters, and our unknown, the length of the wire, as w. Now, we just need to solve for w using the information given in the diagram.