waec physics essay questions

Physics (Essay) Paper 2 WASSCE (SC), 2023

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General Comments

The quality of this year's exam paper was impressive, with appropriate items and clear, unambiguous questions that fell within the scope of the syllabus. The paper also included well-reflected operational and graphical cases, and rubrics were provided clearly. Additionally, the allotted time for the exam was sufficient.

However, there was a significant decline in performance compared to the WASSCE for School Candidates 2022 examination, with only 846,875 candidates taking the exam and achieving a raw mean score of 19 out of 60, and a standard deviation of 09.00. In contrast, the 2022 exam had 801,212 candidates and a raw mean score of 25 out of 60, with a standard deviation of 10.15.

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2024 WAEC GCE Physics OBJ/ESSAY Questions and Answers

WAEC GCE Physics OBJ/ESSAY Questions and Answers 2024 – Get Free Physics Objective/Essay Questions and Answers for the 2024 WAEC GCE November/December Exams

This announcement is for all candidates taking the 2024 WAEC General Certificate of Education (GCE) November/December examination. The Physics Objective/Essay questions and answers are now available here.

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WAEC GCE Physics 2024 Exam Details:

  • Subject: Physics 2 (Objective and Essay/Theory)
  • Date: Thursday, 5th December 2024
  • Physics 2 (Essay): 9:30 am – 11:00 am
  • Physics 1 (Objective): 11:00 am – 12:15 pm

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WAEC GCE 2024 Physics OBJ/ESSAY Questions and Answers

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2024 WAEC GCE Physics Questions and Answers – Study Materials

Access the second series of WAEC GCE Nov/Dec Physics questions and answers (Objective/Essay) right here.

WAEC GCE Physics Essay Past Questions and Answers

Question 1: (a) Explain the difference between scalar and vector quantities. (b) Give two examples of each. (c) A car travels 100 m north and then 75 m east. Calculate its resultant displacement.

Answer 1: (a) A scalar quantity has only magnitude and no direction, while a vector quantity has both magnitude and direction. (b) Examples:

  • Scalar: Temperature, mass
  • Vector: Displacement, velocity (c) To calculate the resultant displacement, use the Pythagoras theorem:

Resultant displacement=(1002+752)=10000+5625=15625=125 m\text{Resultant displacement} = \sqrt{(100^2 + 75^2)} = \sqrt{10000 + 5625} = \sqrt{15625} = 125 \, \text{m} Resultant displacement = ( 100 2 + 75 2 ) ​ = 10000 + 5625 ​ = 15625 ​ = 125 m

The resultant displacement is 125 m at an angle to the north-east.

Question 2: (a) State Ohm’s law. (b) A resistor of 10 Ω is connected in series with a 2 Ω resistor. If a potential difference of 24 V is applied across the combination, calculate: (i) the total resistance in the circuit, (ii) the current flowing through the circuit.

Answer 2: (a) Ohm’s law states that the current (I) passing through a conductor between two points is directly proportional to the voltage (V) across the two points, provided the temperature remains constant. Mathematically, V=IRV = IR V = I R , where RR R is the resistance.

(b) (i) Total resistance in series:

Rtotal=R1+R2=10 Ω+2 Ω=12 ΩR_{\text{total}} = R_1 + R_2 = 10 \, \Omega + 2 \, \Omega = 12 \, \Omega R total ​ = R 1 ​ + R 2 ​ = 10 Ω + 2 Ω = 12 Ω

(ii) Using Ohm’s law to find the current:

I=VR=24 V12 Ω=2 AI = \frac{V}{R} = \frac{24 \, V}{12 \, \Omega} = 2 \, A I = R V ​ = 12Ω24 V ​ = 2 A

The current flowing through the circuit is 2 A.

Question 3: (a) Define the term “latent heat of vaporization.” (b) A 500 g block of ice at 0°C is placed in a container of boiling water at 100°C. Calculate the amount of heat required to completely melt the ice. (Latent heat of fusion of ice = 336,000 J/kg)

Answer 3: (a) The latent heat of vaporization is the amount of heat required to convert a unit mass of a liquid into vapor without a change in temperature.

(b) Calculate the heat required:

  • Mass of ice, m=0.5 kgm = 0.5 \, \text{kg} m = 0.5 kg
  • Latent heat of fusion, Lf=336,000 J/kgL_f = 336,000 \, \text{J/kg} L f ​ = 336 , 000 J/kg

Q=m×Lf=0.5 kg×336,000 J/kg=168,000 JQ = m \times L_f = 0.5 \, \text{kg} \times 336,000 \, \text{J/kg} = 168,000 \, \text{J} Q = m × L f ​ = 0.5 kg × 336 , 000 J/kg = 168 , 000 J

The amount of heat required to completely melt the ice is 168,000 J.

WAEC GCE Physics Objective Past Questions and Answers

1. Which of the following is a scalar quantity? A. Velocity B. Displacement C. Force D. Energy Answer: D. Energy

2. The S.I. unit of electric charge is: A. Volt B. Joule C. Coulomb D. Ohm Answer: C. Coulomb

3. When a force of 10 N moves an object by 5 m in the direction of the force, the work done is: A. 50 J B. 2 J C. 15 J D. 5 J Answer: A. 50 J (Work done ( = \text{Force} \times \text{Distance} = 10 , \text{N} \times 5 , \text{m} = 50 , \text{J})

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